Series-Test 8

The given series is a triangular pattern series. So, we have :
3 10 29 66 127 ?
7 19 37 61
12 18 24
6 6
So, missing term = 127 + (61 + 24 + 6) = 127 + 91 = 218.

The given series is a triangular pattern series. So, we have :
2 12 36 80 150
10 24 44 70
14 20 26
6 6
So, missing term = 150 + (70 + 26 + 6) = 150 + 102 = 252

Each term at an even place in the series is the product of its two adjacent terms.

Thus, if the missing term be x, then we have :

Let the missing terms of he series be 

Thus, the sequence 2, 15, 4, 12, 6, 7, 

 is a combination of two series :

I. 

 and

II. 

I consists of consecutive even numbers. So, missing term 

.

The pattern in II is -3, -5, ……. So, missing term 

Let the missing terms of the series be 

Thus, the sequence 20, 20, 19, 16, 17, 13, 14, 11, 

 is a combination of two series

I. 

and

The pattern in I is -1, -2, -3, ……. So, missing term, 

The pattern in II is -4, -3, -2, So, missing term, 

The given sequence is a combination of two series :

I. 0. 3, 8, 15, 25, ?             and             II. 2, 5, 10, 17, 26

The pattern in each one of I and II is + 3, + 5, + 7, + 9, ……..

So, missing term = 24 + 11 = 35.

The terms of the given series are numbers formed by joining together consecutive odd numbers in order i.e. 1 and 3, 3, and 5, 5 and 7, 7, and 9, 9 and 11, …..

So, missing term = number formed by joining 11 and 13 = 1113.

The given sequence is a combination of two series :

I.  625, 125, 25, 5            and                II. 5, 25, ?

The pattern in I is ÷ 5, while that in II is x 5.

So, missing term = 25 x 5 = 125.

The correct pattern is + 6, + 12, + 24, + 48, + 96, + 192.

So, 96 is wrong and must be replaced by (46 + 48) i.e. 94.

The correct pattern is – 192, – 96, – 48, – 24, – 12, – 6.

So, 48 is wrong and must be replaced by (92 – 48) i.e. 44.

Each term of the series is obtained by dividing the preceding term by 4.

So, 1536 is wrong and must be replaced by (1536 ÷ 4 ) i.e. 384.

The correct pattern is × 2 + 1, × 3 + 1, × 2 + 1, × 3 + 1, ……

So, 356, is wrong and must be replaced by (129 × 3 + 1) i.e. 388.

The correct pattern is × 1 + 1,  × 2 + 2, × 3 + 3, × 4 + 4, ……

So, 32 is wrong and must be replaced by (10 × 3 + 3) i.e. 33.

The correct pattern is × 6 – 6, × 5 – 5, × 4 – 4, …….

So, 24 is wrong and must be replaced by (6 × 5 – 5) i.e. 25.

The correct pattern is 

So, 521 is wrong and must be replace by 

 i.e. 525.

The terms of the series are 

So, 25 is wrong and must be replaced by 

 i.e. 27.

The given sequence is a combination of three series :

I.   1st, 4th, 7th terms i.e. 2, 4, 9, …….

II.  2nd, 5th, 8th terms i.e. 3, 6, 12, …..

III. 3rd, 6th, 9th terms i.e. 4, 8, 16, ……

In each one of I, II and III, each term is twice the preceding term.

So, 9 is wrong and must be replaced by ( 4 x 2) i.e. 8.

Clearly, the first and second letters of each term are moved five steps forward to obtain the corresponding letters of the next term.

Thus, the first letter of the missing term must be five steps ahead of P i.e. U, while the second letter must be five steps ahead of R i.e. W.

So, the missing term is UW.

The given series may be divided into 2 groups :

I. A, B, C, D, E, F, ? , ?        and      II. N, O, P, ?

Clearly, the given series consists of two terms of I followed by one term of II.

The missing terms in I are G and H while the missing term in II  is Q.

The given sequence is a combination of two series :

I. 1st, 3rd, 5th, 7th, 9th, 11th terms i.e. A, B, C, D, E, ?

II. 2nd, 4th, 6th, 8th, 10th terms i.e. B, D, F, H, ?

Clearly, I consists of consecutive letters while II consists of alternate letters the missing letter in I is F, while that in II is J.

So, the missing terms i.e. 10th and 11th terms are J and F respectively.

The given sequence is a combination of two series :

I. Y, T, O             and        II. B, G, ?

I consists of 2nd, 7th and 12th letters from the end of the english alphabet, while II consists of 2nd, 7th and 12th letters from the beginning of the english alphabet. So, the missing letter in II is the 12th letter from the beginning of the english alphabet, which is I.

The number of letters in the terms of the given series increases by one at each step. The first letter of each term is two steps ahead of the last letter of the preceding term. However, each term consists of consecutive letters in order.

Each term of the series is obtained by removing two letters from the preceding term one from the beginning and one from the end. So, the missing term is PENDICU.

In the first step, one letter from the beginning and one from the end of a term are removed to give the next term. In the second step, two letters from the beginning of a term are removed. These two steps are repeated alternately.

One letter from the beginning and one from the end of a term are removed, one by one, in alternate steps.