Online Mock Test in Ratio and Proportions For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT
Ratio and Proportions-Test 4
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Subject :- Quantitative Aptitude
Chapter :- Ratio and Proportion- Test 4
Questions :- 25
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A sum of money is divided among A,B,C and D in the ratio of 3:4:9:10.if the shares of C is Rs2580 more than the share of B,then what is the total amount of money of A and D together?
Correct
here,A:B:C:D=3:4:9:10
difference in the ratio of C and B=9-4=5 and 5=2580 = 1=516
total amount of A and D together=(3+10)*516=Rs6708
Incorrect
here,A:B:C:D=3:4:9:10
difference in the ratio of C and B=9-4=5 and 5=2580 = 1=516
total amount of A and D together=(3+10)*516=Rs6708
Question 2 of 25
2. Question
1 points
S,M and K rented a set of DVD’s at a rent of Rs578.if they use it for 8 hr and 14 hr.what is K’s share of rent to be paid?
Correct
here,S:M:K=8/12:12/2:14/2=4:6:7
K’s share=7/17*578=7*34=Rs238
Incorrect
here,S:M:K=8/12:12/2:14/2=4:6:7
K’s share=7/17*578=7*34=Rs238
Question 3 of 25
3. Question
1 points
A sum of money is to be distributed among P,Q and R in the ratio of 6:19:7.if R gives Rs200 from his share to Q,the ratio of P,Q and R becomes 3:10:3,what is the total sum?
Correct
here,P:Q:R=6:19:7
new ratio of P:Q:R=3:10:3
so,data is inadequate
Incorrect
here,P:Q:R=6:19:7
new ratio of P:Q:R=3:10:3
so,data is inadequate
Question 4 of 25
4. Question
1 points
The sides of a triangle are in the ratio of 1/2:1/33:1/4 and its perimeter is 104 cm.the length of the longest side is
Correct
here,ratio of triangle = 1/2:1/3:1/4 =6:4:3
now,perimeter of triangle=6+4+3=104
13=104
1=8
therefore,length of the longest side =6*8=48cm
Incorrect
here,ratio of triangle = 1/2:1/3:1/4 =6:4:3
now,perimeter of triangle=6+4+3=104
13=104
1=8
therefore,length of the longest side =6*8=48cm
Question 5 of 25
5. Question
1 points
The ratio of the number of students studying in school A,B and C is 5:6:8.if the number of students in each of the school is increased by 30%,25% and 25%.what will be the new ratio of the students in schools A,B and C?
Correct
here,A:B:C=5:6:8
increase in ratio=5*130/100:6*125/100:8*125/100=650:750:1000=13:15:20
Incorrect
here,A:B:C=5:6:8
increase in ratio=5*130/100:6*125/100:8*125/100=650:750:1000=13:15:20
Question 6 of 25
6. Question
1 points
The ratio of the number of students studying in school A,B and C is 5:8:4.if the number of students in each of the school is increased by 20%,25% and 30%.what will be the new ratio of the students in schools A,B and C?
Correct
here,A:B:C=5:8:4
increase in ratio=5*120/100:8*125/100:4*130/100=650:1000:520=15:25:13
Incorrect
here,A:B:C=5:8:4
increase in ratio=5*120/100:8*125/100:4*130/100=650:1000:520=15:25:13
Question 7 of 25
7. Question
1 points
Production of company A is 120% of the production of company B and 80% of the production of company C.what is the ratio between the production of companies A,B and C?
In a collage the number of students studying arts,commerce and science are in the ratio of 3:5:8.if the number of students studying arts.commerce and science is increased by 20%,40% and 25%,what will be the new ratio of students studying arts ,commerce and science?
Correct
here,A:C:S=3:5:8
new ratio = 3*120/100:5*140/100:8*125/100=18:35:50
Incorrect
here,A:C:S=3:5:8
new ratio = 3*120/100:5*140/100:8*125/100=18:35:50
Question 9 of 25
9. Question
1 points
Salaries of A,B and C in the ratio of 2:3:5.if their salary were increased by 15%,10% and 20%,what will be the new ratio of their salaries?
Correct
here,A:B:c=2:3:5
new ratio = 2*115/100:3*110/100:5*120/100=23:33:60
Incorrect
here,A:B:c=2:3:5
new ratio = 2*115/100:3*110/100:5*120/100=23:33:60
Question 10 of 25
10. Question
1 points
Ratio of the earning of A and B is 4:7.if the earnings of A increased by 50% and B decreased by 25% then new ratio becomes 8:7,what are A’s earnings?
Correct
here,only initial and final ratio of the earnings is given.so,data is inadequate
Incorrect
here,only initial and final ratio of the earnings is given.so,data is inadequate
Question 11 of 25
11. Question
1 points
Seats for maths,physics and biology are in the ratio of 5:7:8.there is an increase in seats by 40%,50% and 75%.what will be the ratio of increased seats ?
Correct
here,M:P:B=5:7:8
new ratio=5*140/100:7*150/100:8*175/100=10:15:20=2:3:4
Incorrect
here,M:P:B=5:7:8
new ratio=5*140/100:7*150/100:8*175/100=10:15:20=2:3:4
Question 12 of 25
12. Question
1 points
In a school the number of boys and that of the girls are in the ratio of 2:3.if the number of boys is increased by 20% and girls increased by 10%,what will be the new ratio of boys and girls?
Correct
here,B:G=2:3
new ratio = 2*120/100:3*110/100=24:33=8:11
Incorrect
here,B:G=2:3
new ratio = 2*120/100:3*110/100=24:33=8:11
Question 13 of 25
13. Question
1 points
In a collage,the ratio of boys to girls is 31:23.when 75 more join in the collage,this ratio becomes 124:107.how many more girls should join the collage to make number of boys and girls equal?
Correct
here,B:G=31:23
let x be the common ratio
then,no of boys=31x and no of girls-=23x
new ratio , 31x/23x+75=124/107
31x*107=23x*124+75*124
465x=9300
x=9300/465=20
difference in ratio of boys and girls=124-107=17
so,no of girls should join=17*20=340
Incorrect
here,B:G=31:23
let x be the common ratio
then,no of boys=31x and no of girls-=23x
new ratio , 31x/23x+75=124/107
31x*107=23x*124+75*124
465x=9300
x=9300/465=20
difference in ratio of boys and girls=124-107=17
so,no of girls should join=17*20=340
Question 14 of 25
14. Question
1 points
number students in arts and science faculties in an institute are in the ratio of 5:8, respectively. if 150 more students join art faculty while 80 more students join science faculty , the respective ratio becomes 3:4. originally what was the total number students in both faculties together?
Correct
here,A:S=5:8
let x be the common ratio
then, no of arts =5x and no of science=8x
new ratio, 5x+150/8x+80=3/4
20x+600=24x+240
4x=360
x=90
total no of students in both faculties = (5+8)*90=13*90=1170
Incorrect
here,A:S=5:8
let x be the common ratio
then, no of arts =5x and no of science=8x
new ratio, 5x+150/8x+80=3/4
20x+600=24x+240
4x=360
x=90
total no of students in both faculties = (5+8)*90=13*90=1170
Question 15 of 25
15. Question
1 points
rohit has some 50paisa coins, some rs 2 coins, some rs 1 coins and some rs 5 coins. the value of all the coins is rs 50. no of rs 2 coins is 5 more than that of the rs 5 coins. 50 paisa coins are double in number than rs 1 coins. value of 50 paisa coins and rs 1 coins is rs 26. how many rs 2 coins does he have?
Correct
here, ratio of the coins = 50:200:100:500=1:4:2:10
now, if the number of rs 2 coins be X
then ,no of rs 5 coins =X-5
2X+5(X-5)=50-26
7X=24+25
X=49/7=7
Incorrect
here, ratio of the coins = 50:200:100:500=1:4:2:10
now, if the number of rs 2 coins be X
then ,no of rs 5 coins =X-5
2X+5(X-5)=50-26
7X=24+25
X=49/7=7
Question 16 of 25
16. Question
1 points
20 boys and 25 girls from a group of social workers. during their membership drive, the same no of boys and girls joined the group. how many members does the group to girls is 7:8?
Correct
here,let X be no of boys and girls
ratio of boys to girls = 20:25
now, 20+X/25+X=7/8
160+8X=175+7X
X=15
so,the total no of members in group = 25+20+30=75
Incorrect
here,let X be no of boys and girls
ratio of boys to girls = 20:25
now, 20+X/25+X=7/8
160+8X=175+7X
X=15
so,the total no of members in group = 25+20+30=75
Question 17 of 25
17. Question
1 points
the ratio between two numbers is 2:3.if each number is increased by 4,the ratio becomes 5:7,the difference between the number is
Correct
here, ratio =2:3 and let x be the common ratio
then, 2x+4/3x+4=5/7
x=28-20=8
required difference = 8*(3-2)=8
Incorrect
here, ratio =2:3 and let x be the common ratio
then, 2x+4/3x+4=5/7
x=28-20=8
required difference = 8*(3-2)=8
Question 18 of 25
18. Question
1 points
income of 2 companies A and B are in the ratio of 5:8 had the income of company A been more by rs 25 lakhs ,the ratio of their income would have of their 5:4 , what is the income of company B?
Correct
here, A:B =5:8
let X be the common ratio
then, A income =5X and B income =8X
now ,5X+25/8X=5/4
40X-20X=100
20X=100
X=5
income of company B = 8×5=Rs 40 lakhs
Incorrect
here, A:B =5:8
let X be the common ratio
then, A income =5X and B income =8X
now ,5X+25/8X=5/4
40X-20X=100
20X=100
X=5
income of company B = 8×5=Rs 40 lakhs
Question 19 of 25
19. Question
1 points
at present, pia is 6 yr older to ray. the respective ratio between the present ages of pia and mini is 3:4. at present, ray is 14 yr younger to mini. what is rays present age?
Correct
let rays present age be Xyr and pia present age is (X=6)yr and mini present is (X+14)yr
now,X+6/X+14=3/4 = X=18
hence ray present age is 18 yr
Incorrect
let rays present age be Xyr and pia present age is (X=6)yr and mini present is (X+14)yr
now,X+6/X+14=3/4 = X=18
hence ray present age is 18 yr
Question 20 of 25
20. Question
1 points
the ratio of present ages of mahesh and ajay is 3:2. after 8yr ,ratio of their ages will be 11:8. what will be the present age of mahesh son if his age is half of the present age of ajay?
Correct
here, ratio of present ages of mahesh and ajay =3:2
after, 8yr ratio of there ages = 11:8
let X be the common ratio
then, present age of mahesh=3X and ajay=2X
now , 3X + 8/2X+8=11/8 X=12
present age of mahesh=3x12yr =36yr and ajay=2x12yr=24yr
hence mahesh son age is 24×1/2=12yr
Incorrect
here, ratio of present ages of mahesh and ajay =3:2
after, 8yr ratio of there ages = 11:8
let X be the common ratio
then, present age of mahesh=3X and ajay=2X
now , 3X + 8/2X+8=11/8 X=12
present age of mahesh=3x12yr =36yr and ajay=2x12yr=24yr
hence mahesh son age is 24×1/2=12yr
Question 21 of 25
21. Question
1 points
the difference between the present age of anil and sudhir is 6 yr. the ratio between their ages after 4 yr will be 3:4. what can be the present age of sudhir?
Correct
here, difference between age of anil sudhir is 6 yrs
let present ages of anil=Xyr and sudhir =X+6yr
so, X+4/X+6+4=3/4
X=14yr
sudhir present age = 14+6=20yr
Incorrect
here, difference between age of anil sudhir is 6 yrs
let present ages of anil=Xyr and sudhir =X+6yr
so, X+4/X+6+4=3/4
X=14yr
sudhir present age = 14+6=20yr
Question 22 of 25
22. Question
1 points
The ratio between the present age of ram and rakesh is 6:11.4yr ago the ratio of their ages was 1:2.what will be rakesh age after 5 yr?
Correct
here,present age of ram and rakesh=6:11
ratio of their 4yr ago=1:2
rakesh’s after 5yr = 2*20+9=49yr
Incorrect
here,present age of ram and rakesh=6:11
ratio of their 4yr ago=1:2
rakesh’s after 5yr = 2*20+9=49yr
Question 23 of 25
23. Question
1 points
The ratio between the present age of ram,rohan and raj is 3:4:5.if the average of their present age 28yr,then what would be the sum of the ages of ram and rohan together after 5yr?
Correct
here,ram:rohan:raj=3:4:5
let x be the common ratio
let present of ram,rohan and raj be 3x,4x and 5x
then,3x+4x+5x=28*3
x=7
ages of ram and rohan together after 5 yr=(3+4)*7+10=59yr
Incorrect
here,ram:rohan:raj=3:4:5
let x be the common ratio
let present of ram,rohan and raj be 3x,4x and 5x
then,3x+4x+5x=28*3
x=7
ages of ram and rohan together after 5 yr=(3+4)*7+10=59yr
Question 24 of 25
24. Question
1 points
The ratio between present age of M and W is 3:11.W is 12yr younger than R.R age after 7 yr will be 78yr.what is present age of M’s father who is 25yr older than M?
Correct
here,M:W=3:11
R present age =78yr
W’s present age = 78=12=66yr
M present age =18yr
M’s father age =25+18=43yr
Incorrect
here,M:W=3:11
R present age =78yr
W’s present age = 78=12=66yr
M present age =18yr
M’s father age =25+18=43yr
Question 25 of 25
25. Question
1 points
The ratio of the ages of tina and rakesh is 9:10.10 yr ago the ratio of their ages was 4:5,what is the present age of rakesh?
