Home Quantitative Aptitude Ratio and Proportions-Test 3

Ratio and Proportions-Test 3

Ratio and Proportions

Online exam in Ratio and Proportions For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT

Ratio and Proportions-Test 3

Subject :- Quantitative Aptitude

Chapter :- Ratio and Proportion- Test 3

Questions :- 25

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Question 1 of 25

1. Question
1 points
Divide Rs.2340 into three parts, such that first part be double that of second part and
second part be 1/3 of the third part.Find the Third part amount?
- Rs.780
- Rs.1170
- Rs.750
- Rs.390
- None of these
Correct

First: Second: Third = 2:1:3
Third part = 3*2340/6 = 1170

Incorrect

First: Second: Third = 2:1:3
Third part = 3*2340/6 = 1170
Question 2 of 25

2. Question
1 points
The ratio of income of A and B is 2:3. The sum of their expenditure is Rs.8000 and the
amount of savings of A is equal to the amount of expenditure of B.What is the their ratio
of sum of income to their sum of savings?
- 5:3
- 3:2
- 4:3
- 3:1
- None of these
Correct

2I-E + E = 8000
I = 4000
Sum of their Income = 5*I = 5*4000 = 20,000
Sum of their Savings = 20000-8000 = 12,000
20000:12000 = 5:3

Incorrect

2I-E + E = 8000
I = 4000
Sum of their Income = 5*I = 5*4000 = 20,000
Sum of their Savings = 20000-8000 = 12,000
20000:12000 = 5:3
Question 3 of 25

3. Question
1 points
There are 2 containers of equal capacity. The ratio of milk to water in the first container
is 4:5 and in the second container is 3:7.If they are mixed up then the ratio of milk to water in the mixture will be
- 17:63
- 65:96
- 34:75
- 67:113
- None of these
Correct

4+5 = 9=> 40:50

3+7 = 10=> 27:63
40+27 : 50:63 = 67:113

Incorrect

4+5 = 9=> 40:50

3+7 = 10=> 27:63
40+27 : 50:63 = 67:113
Question 4 of 25

4. Question
1 points
There are two numbers. When 25% of the first number is added to the second number,
the resultant number is 1.5times th first number.What is the ratio of 1st number to the
2nd number ?
- 3:5
- 5:4
- 4:5
- 2:3
- None of these
Correct

A+25/100 + B = 1.5A
A/4 + B = 15A/10
10A+40B/40 =60A/40
10A+40B = 60A
50A = 40B
A/B = 4/5

Incorrect

A+25/100 + B = 1.5A
A/4 + B = 15A/10
10A+40B/40 =60A/40
10A+40B = 60A
50A = 40B
A/B = 4/5
Question 5 of 25

5. Question
1 points
A bag contains 10p,25p and Rs50p coins in the ratio of 5:2:1 respectively. If the total
money in the bag is Rs.120.Find the number of 25p coins in that bag?
- 160
- 130
- 110
- 90
- None of these
Correct

10*5 : 25*2 : 50*1 = 50:50:50 = 1:1:1
120/3 = Rs.40
Rs. 1 = 4
Rs.40 = 4*40 = 160 coins

Incorrect

10*5 : 25*2 : 50*1 = 50:50:50 = 1:1:1
120/3 = Rs.40
Rs. 1 = 4
Rs.40 = 4*40 = 160 coins
Question 6 of 25

6. Question
1 points
The ratio of Ganesh’s age and his mother’s age is 5:12.The difference of their ages is
21.The ratio of their ages after 4 years will be
- 3:7
- 6:11
- 4:7
- 19:40
- None of these
Correct

12x – 5x = 21

7x = 21
X = 3
5:12 = 15:36
After 4 years = 19:40

Incorrect

12x – 5x = 21

7x = 21
X = 3
5:12 = 15:36
After 4 years = 19:40
Question 7 of 25

7. Question
1 points
The ratio of students of three classes is 2:3:4. If 12 students are increased in each classes then their ratio turns into 13:18:23. What was the total number of students in all the three classes originally ?
- 250
- 215
- 225
- 190
- None of these
Correct

50:75:100
15 students increased
65:90:115 => 13:18 :23
Total no of students = 50+75+100 = 225

Incorrect

50:75:100
15 students increased
65:90:115 => 13:18 :23
Total no of students = 50+75+100 = 225
Question 8 of 25

8. Question
1 points
Ravi and Govind have money in the ratio 5 : 12 and Govind and Kiran also have money
in the same ratio 5 : 12. If Ravi has Rs. 500, Kiran has
- Rs.2500
- Rs.2880
- Rs.1850
- Rs.3100
- None of these
Correct

Ravi : Kiran = 5/12* 5/12 = 25/144
Kiran = 144*500/25 = 2880

Incorrect

Ravi : Kiran = 5/12* 5/12 = 25/144
Kiran = 144*500/25 = 2880
Question 9 of 25

9. Question
1 points
A town with a population of 1000 has provision for 30days, after 10 days 600 more men
added, how long will the food last at the same rate ?
- 12 days
- 14 ½ days
- 12 ½ days
- 15 days
- None of these
Correct

1000*20/1600 = 12 1/2 days

Incorrect

1000*20/1600 = 12 1/2 days
Question 10 of 25

10. Question
1 points
A man spends Rs.2480 to buy lunch box Rs.120 each and bottles at Rs.80 each,What will
be the ratio of maximum number of bottles to lunch box are bought ?
- 13:12
- 11:13
- 9:12
- 7:10
- None of these
Correct

13*80+ 12*120 = 1040+1440 = 2480

Incorrect

13*80+ 12*120 = 1040+1440 = 2480
Question 11 of 25

11. Question
1 points
When X is subtracted from the number 9,15 an 27,the remainders are in continued proportion.what is the value of X?
- 8
- 6
- 4
- 5
- none of these
Correct

Incorrect
Question 12 of 25

12. Question
1 points
The 4th proportional to 5,8,15 is
- 18
- 24
- 19
- 20
- 21
Correct

here,let the 4th proportional be X

then,5:8::15:X

product of extremes = product of means

X=120/5=24

Incorrect

here,let the 4th proportional be X

then,5:8::15:X

product of extremes = product of means

X=120/5=24
Question 13 of 25

13. Question
1 points
The mean proportional between 234 and 104 is
- 12
- 39
- 45
- 54
- none of these
Correct

mean proportional between 234 and 104
$= \sqrt{234 \times 104} = \sqrt{2 \times 13 \times 9 \times 13 \times 8} = 4 \times 13 \times 3 = 156$

Incorrect

mean proportional between 234 and 104
$= \sqrt{234 \times 104} = \sqrt{2 \times 13 \times 9 \times 13 \times 8} = 4 \times 13 \times 3 = 156$
Question 14 of 25

14. Question
1 points
The 3rd proportional to 0.36 and 0.48 is
- 0.64
- 0.1728
- 0.42
- 0.94
- none of these
Correct

here,let 3rd proportional be X

then,0.36:0.48::0.48:X

X=0.48*0.48/0.36=0.64

Incorrect

here,let 3rd proportional be X

then,0.36:0.48::0.48:X

X=0.48*0.48/0.36=0.64
Question 15 of 25

15. Question
1 points
The ratio of 3rd proportional to 12 and 30 and the mean proportional between 9 and 25 is
- 2:1
- 5:1
- 7:15
- 9:14
- none of these
Correct

here,let 3rd proportional be X

then,12:30::30:X

X=900/12=75

men proportional=
$= \sqrt{9 \times 25} = \sqrt{225 = 15}$
required ratio = 75:15=5:1

Incorrect

here,let 3rd proportional be X

then,12:30::30:X

X=900/12=75

men proportional=
$= \sqrt{9 \times 25} = \sqrt{225 = 15}$
required ratio = 75:15=5:1
Question 16 of 25

16. Question
1 points
Rs 73689 are divided between A and B in the ratio 4:7.what is the difference between thrice share of A and twice share of B?
- Rs36699
- Rs46893
- Rs20097
- Rs26796
- Rs13398
Correct

2*share of B-3*share of A=2*7/11-3*4/11=2/11=2/11*73689=13398

Incorrect

2*share of B-3*share of A=2*7/11-3*4/11=2/11=2/11*73689=13398
Question 17 of 25

17. Question
1 points
A sum of Rs 221 is divided among X,Y and Z such that X gets Rs 52 more than Y.Y gets Rs 20 more than Z.the ratio of the shares of X,Y and Z is
- 9:5:3
- 9:3:5
- 5:9:3
- 10:6:5
- none of these
Correct

here,221 is divided among X,Y and Z

let Z gets Rs a

then, Y gets Rs a+26 and X gets Rs a+78

then,a+a+26+a+78=221

3a+104=221

a=39

so, share of Z=Rs39

Y=39+26=Rs65

X=39+78=Rs117

required ratio = 117:65:39=9:5:3

Incorrect

here,221 is divided among X,Y and Z

let Z gets Rs a

then, Y gets Rs a+26 and X gets Rs a+78

then,a+a+26+a+78=221

3a+104=221

a=39

so, share of Z=Rs39

Y=39+26=Rs65

X=39+78=Rs117

required ratio = 117:65:39=9:5:3
Question 18 of 25

18. Question
1 points
A particular sum was divided among A,B and C in the ratio of 2:6:7,if the amount received by A was Rs4908,what was the difference between the amounts received by B and C?
- Rs2454
- Rs3494
- Rs2135
- Rs2481
- none of these
Correct

here,A:B:C=2:6:7

amount received by A=Rs4908

difference between the amounts received by B and C=7-6/2*4908=Rs2454

Incorrect

here,A:B:C=2:6:7

amount received by A=Rs4908

difference between the amounts received by B and C=7-6/2*4908=Rs2454
Question 19 of 25

19. Question
1 points
The cost of making an article is divided between materials , labour and overheads in the ratio of 3:4:1.if the materials cost is Rs234,then the labour cost is
- Rs176
- Rs312
- Rs78
- Rs390
- none of these
Correct

here,M:L:O=3:4:1

total materials cost=Rs234

i.e. 3=234

1=234/3=78

labour cost = respective ratio *78=4*78=Rs312

Incorrect

here,M:L:O=3:4:1

total materials cost=Rs234

i.e. 3=234

1=234/3=78

labour cost = respective ratio *78=4*78=Rs312
Question 20 of 25

20. Question
1 points
A certain amount was to be distributed among A,B and C in the ratio 2:3:4,but was erroneously distributed in the ratio of 7:2:5.as a result of this,B got Rs40 less.what is the amount?
- Rs210
- Rs270
- Rs230
- Rs280
- none of these
Correct

here,A:B:C=2:3:4

but erroneously distributed=7:2:5

difference in ratio of B=3-2=1

but the given difference is Rs40

total amount=(2+3+4)*40=Rs360

Incorrect

here,A:B:C=2:3:4

but erroneously distributed=7:2:5

difference in ratio of B=3-2=1

but the given difference is Rs40

total amount=(2+3+4)*40=Rs360
Question 21 of 25

21. Question
1 points
An amount of money is to divided among P,Q and R in the ratio of 3:5:7,if the amount received by R is Rs4000 more than the amount received by Q,what will be total amount received by P and Q together?
- Rs8000
- Rs12000
- Rs16000
- cannot be determined
- none of these
Correct

here,P:Q:R=3:5:7

difference in the ratio between R and Q=Rs4000

7-5=4000

2=4000

1=Rs2000

amount received by P and Q together=(3+5)*2000=Rs16000

Incorrect

here,P:Q:R=3:5:7

difference in the ratio between R and Q=Rs4000

7-5=4000

2=4000

1=Rs2000

amount received by P and Q together=(3+5)*2000=Rs16000
Question 22 of 25

22. Question
1 points
The ages of mira,tina and sania are in the ratio of 6:4:7.if the sum of their ages is 34 yr,what is sania’s age?
- 12yr
- 10yr
- 18yr
- 8yr
- none of these
Correct

here,M:T:S=6:4:7

now,sum of their ages = 34yr

let their ages be 6x,4x and 7x

so, 6x+4x+7x=34

17x=34

x=34/17=2

sania’s age=2*7=14yr

Incorrect

here,M:T:S=6:4:7

now,sum of their ages = 34yr

let their ages be 6x,4x and 7x

so, 6x+4x+7x=34

17x=34

x=34/17=2

sania’s age=2*7=14yr
Question 23 of 25

23. Question
1 points
Mr.Pandit owned 950 gold coins all of which is distributed among his 3 daughters lalita,amita and neeta.lalita gave 25 gold coins to her husband , amita donated 15 gold coins and neeta made jewellery out coins of 30 gold coins.the new ratio of the coins left with them 20:73:83.how many gold coins is amita receive from pandit ?
- 380
- 415
- 400
- 350
- none of these
Correct

here,L:A:N=20:73:83

let X be ratio

20X+25+73X+15+83X+30=950

176X=70=950

X=880/176=5

gold coins received by amita from pandit=5*73+15=`380

Incorrect

here,L:A:N=20:73:83

let X be ratio

20X+25+73X+15+83X+30=950

176X=70=950

X=880/176=5

gold coins received by amita from pandit=5*73+15=`380
Question 24 of 25

24. Question
1 points
A sum of money is divided among A,B,C and D in the ratio of 2:3:7:11.if the share of C is Rs2755 more money by B and D together?
- Rs4408
- Rs5510
- Rs6612
- Rs7714
- none of these
Correct

here,A:B:C:D=2:3:7:11

difference in ratio of C and A=7-2=5

5=2755 = 1=551

total amount B and D together = (3+11)*551=Rs7714

Incorrect

here,A:B:C:D=2:3:7:11

difference in ratio of C and A=7-2=5

5=2755 = 1=551

total amount B and D together = (3+11)*551=Rs7714
Question 25 of 25

25. Question
1 points
A sum of money is to be divided among 4 persons in the ratio of 2:3:4:5.out of the 4 one person gets Rs200 more than the other and Rs100 less than another.what is the sum?
- Rs2800
- Rs1400
- Rs4200
- Rs4500
- none of these
Correct

here,5-4=100 = 1=100

4-2=200 = 2=200 = 1=100

total sum = (2+3+4+5)*100=14*100=Rs1400

Incorrect

here,5-4=100 = 1=100

4-2=200 = 2=200 = 1=100

total sum = (2+3+4+5)*100=14*100=Rs1400

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