Online exam in Pipes and Cistern For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT
Pipes and Cistern-Test 2
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Subject :- Quantitative Aptitude
Chapter :- Pipers and Cistern-Test 2
Questions :- 25
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A pipe can fill a cistern in 8 hours. After half the tank is filled, three more similar taps
are opened. What is the total time taken to fill the cistern completely?
Correct
In One hour pipe can fill = 1/8
Time is taken to fill half of the tank = 1/2 * 8 = 4
hours
Part filled by four pipes in one hour = (4*1/8) =
1/2
Required Remaining Part = 1/2
Total time = 4 + 1 = 5
Incorrect
In One hour pipe can fill = 1/8
Time is taken to fill half of the tank = 1/2 * 8 = 4
hours
Part filled by four pipes in one hour = (4*1/8) =
1/2
Required Remaining Part = 1/2
Total time = 4 + 1 = 5
Question 2 of 25
2. Question
1 points
Two pipes P and Q are opened together to fill a tank. Both the pipes fill the tank in time
“x” If Q separately took 16 minutes more time than “x” to fill the tank and Q took 36
minutes more time than “x” to fill the tank, then find out the value of x?
Correct
Time is taken to fill the tank by both Pipes x= √a*b
x = √16*36 = 4 * 6 = 24
Incorrect
Time is taken to fill the tank by both Pipes x= √a*b
x = √16*36 = 4 * 6 = 24
Question 3 of 25
3. Question
1 points
A Cistern has an inlet pipe and outlet pipe. The inlet pipe fills the cistern completely in 1
hour 20 minutes when the outlet pipe is plugged. The outlet pipe empties the tank
completely in 6 hours when the inlet pipe is plugged. If there is a leakage also which is
capable of draining out the water from the tank at half of the rate of the outlet pipe, then
what is the time taken to fill the empty tank when both the pipes are opened?
Efficiency of leakage = half of the rate of the
outlet pipe = 8.33%
Net Efficiency = 75 – (16.66 + 8.33) = 50%
Required time = 100/50 = 2 hours
Question 4 of 25
4. Question
1 points
A Cistern has an inlet pipe and outlet pipe. The inlet pipe fills the cistern completely in 1
hour 20 minutes when the outlet pipe is plugged. The outlet pipe empties the tank completely in 4 hours when the inlet pipe is plugged. If both pipes are opened
simultaneously at a time when the tank was one-third filled, when will the tank fill
thereafter?
Two pipes P and Q can fill a cistern in 10 hours and 20 hours respectively. If they are
opened simultaneously. Sometimes later, tap Q was closed, then it takes total 8 hours to fill up the whole tank. After how many hours Q was closed?
Correct
Pipe P Efficiency = 100/10 = 10%
Pipe Q Efficiency = 100/20 = 5%
Net Efficiency = 15%
15x + 10(8-x) = 100
x = 4
Incorrect
Pipe P Efficiency = 100/10 = 10%
Pipe Q Efficiency = 100/20 = 5%
Net Efficiency = 15%
15x + 10(8-x) = 100
x = 4
Question 6 of 25
6. Question
1 points
Three pipes A, B, and C can fill the tank in 10 hours, 20 hours and 40 hours respectively. In the beginning all of them are opened simultaneously. After 2 hours, tap C is closed
and A and B are kept running. After the 4th hour, tap B is also closed. The remaining
work is done by tap A alone. What is the percentage of the work done by tap A alone?
Correct
Pipe A’s work in % = 100/10 = 10%
Pipe B’s work in % = 100/20 = 5%
Pipe C’s work in % = 100/40 = 2.5%
All of them are opened for 2 hours + after 2
hours, tap C is closed + After the 4th hour, tap B
is also closed = 100
=> (10+5+2.5)*2 + (10+5)*2 + X = 100
=> 35 + 30 + work by tap A alone = 100
=> work by tap A alone = 100-65 = 35%
Incorrect
Pipe A’s work in % = 100/10 = 10%
Pipe B’s work in % = 100/20 = 5%
Pipe C’s work in % = 100/40 = 2.5%
All of them are opened for 2 hours + after 2
hours, tap C is closed + After the 4th hour, tap B
is also closed = 100
=> (10+5+2.5)*2 + (10+5)*2 + X = 100
=> 35 + 30 + work by tap A alone = 100
=> work by tap A alone = 100-65 = 35%
Question 7 of 25
7. Question
1 points
A pipe can fill a tank in 12 minutes and another pipe can fill it in 15 minutes, but a
third pipe can empty it in 6 minutes. The first two pipes are kept open for 5 min in the
beginning and then third pipe is also opened. Time taken to empty the water tank is?
Correct
x/6 – (x+5)/12 – (x+5)/15 = 0
x = 45 mins
Incorrect
x/6 – (x+5)/12 – (x+5)/15 = 0
x = 45 mins
Question 8 of 25
8. Question
1 points
Two pipes A and B can fill a tank in 12 hours and 18 hours respectively. The pipes
are opened simultaneously and it is found that due to leakage in the bottom of the tank
it took 48 minutes excess time to fill the cistern. When the cistern is full, in what time
will the leak empty it?
Correct
Work done by the two pipes in 1 hour = (1/12)+(1/18) = (15/108).
Time taken by these pipes to fill the tank = (108/15)hrs = 7 hours 12 min.
Due to leakage, time taken = 7 hours 12 min +48 min = 8 hours
Work done by two pipes and leak in 1 hour =1/8.
Work done by the leak in 1 hour =(15/108)- (1/8)=(1/72).
Leak will empty the full cistern in 72 hours.
Incorrect
Work done by the two pipes in 1 hour = (1/12)+(1/18) = (15/108).
Time taken by these pipes to fill the tank = (108/15)hrs = 7 hours 12 min.
Due to leakage, time taken = 7 hours 12 min +48 min = 8 hours
Work done by two pipes and leak in 1 hour =1/8.
Work done by the leak in 1 hour =(15/108)- (1/8)=(1/72).
Leak will empty the full cistern in 72 hours.
Question 9 of 25
9. Question
1 points
A tank is normally filled in 6 hours but takes two hours longer to fill because of a
leak in the bottom of the tank. If the tank is full the leak will empty it in how many hours?
Correct
Work done by leak in 1 hr=(1/6-1/8)=1/24
Leak will empty the tank in 24 hours
Incorrect
Work done by leak in 1 hr=(1/6-1/8)=1/24
Leak will empty the tank in 24 hours
Question 10 of 25
10. Question
1 points
Twelve pipes are connected to a Cistern. Some of them are inlet pipes and the others
are outlet pipes. Each of the inlet pipes can fill the tank in 8 hours and each of the outlet
pipes can empty the cistern completely in 6 hours. If all the pipes are kept open, the
empty tank gets filled in 24 hours. How many inlet pipes are there?
Correct
(x/8)-[(12-x)/6] = 1/24
x = 7
Incorrect
(x/8)-[(12-x)/6] = 1/24
x = 7
Question 11 of 25
11. Question
1 points
A dam has four inlets – A, B, C and D. The dam can be filled in 12 minutes through the
first three inlets and it can be filled in 15 minutes through the second, the third and
fourth inlet also it can be filled through the first and the fourth inlet in 20 minutes. How
much time required to fill up the dam by all the four inlets?
Correct
(1/A + 1/B + 1/C) = 1/12 …(i)
(1/B + 1/C + 1/D) = 1/15 …(ii)
(1/A + 1/D) = 1/20 …(iii)
From eqn (i) and (ii)
(1/A – 1/D) = 1/60…(iv)
From eqn (iii) and (iv)
A=30 D=60.
Let the time taken to full the tank = T
T(1/A + 1/B +1/C +1/D)= 1
T(1/30 + 1/15) = 1
T = 10 mins
Incorrect
(1/A + 1/B + 1/C) = 1/12 …(i)
(1/B + 1/C + 1/D) = 1/15 …(ii)
(1/A + 1/D) = 1/20 …(iii)
From eqn (i) and (ii)
(1/A – 1/D) = 1/60…(iv)
From eqn (iii) and (iv)
A=30 D=60.
Let the time taken to full the tank = T
T(1/A + 1/B +1/C +1/D)= 1
T(1/30 + 1/15) = 1
T = 10 mins
Question 12 of 25
12. Question
1 points
Three pipes P, Q and R connected to a Cistern. The first pipe (i.e) P can fill 1/2 part
of the tank in one hour, second pipe, Q can fill 1/3 part of the cistern in one hour. R is
connected to empty the cistern. After opening all the three pipes 7/12 part of the cistern.
Then how much time required to empty the cistern completely?
Correct
In 1 hour, P can fill = 1/2 Part
Time taken to fill the Cistern by Pipe P = 2
hours
In 1 hour, Q can fill = 1/3 Part
Time taken to fill the Cistern by Pipe P = 3
hours
[1/2 + 1/3 – 1/R] = 7/12
1/R = 1/4
Time required to empty the Cistern = 4 hours
Incorrect
In 1 hour, P can fill = 1/2 Part
Time taken to fill the Cistern by Pipe P = 2
hours
In 1 hour, Q can fill = 1/3 Part
Time taken to fill the Cistern by Pipe P = 3
hours
[1/2 + 1/3 – 1/R] = 7/12
1/R = 1/4
Time required to empty the Cistern = 4 hours
Question 13 of 25
13. Question
1 points
A Cistern can be filled by an inlet pipe at the rate of 4 litres per minute. A leak in the
bottom of a cistern can empty the full tank in 8 hours. When the cistern is full, the inlet is
opened and due to the leak, the cistern is empty in 40 hours. How many litres does the
cistern hold?
Correct
Part emptied by the leak in 1 hour = 1/8
part filled by (leak & inlet open) in 1 hour = 1/40
Part filled by the inlet pipe in 1 hour = 1/8 – 1/40 = 1/10
Inlet pipe fills the tank in = 10 hours
Inlet pipe fills water at the rate of 4 litres a minute.
Capacity of Cistern = 10 * 60 * 4 = 2400 litre
Incorrect
Part emptied by the leak in 1 hour = 1/8
part filled by (leak & inlet open) in 1 hour = 1/40
Part filled by the inlet pipe in 1 hour = 1/8 – 1/40 = 1/10
Inlet pipe fills the tank in = 10 hours
Inlet pipe fills water at the rate of 4 litres a minute.
Capacity of Cistern = 10 * 60 * 4 = 2400 litre
Question 14 of 25
14. Question
1 points
In a tank there is a pipe which can be used for filling the tank as well as for emptying it.
The capacity of the tank is 1200 m³. The emptying of the tank is 10 m³ per minute higher than its filling capacity and the pump needs 6 minutes lesser to empty the tank than
it needs to fill it. What is the filling capacity of the pipe?
Two pipes P and Q can fill a cistern in 12 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours will the tank be full?
Correct
Pipe P can fill = 1/12
Pipe Q can fill = 1/4
For every two hour, 1/12 + 1/4 = 1/3 Part filled
Total = 6 hours
Incorrect
Pipe P can fill = 1/12
Pipe Q can fill = 1/4
For every two hour, 1/12 + 1/4 = 1/3 Part filled
Total = 6 hours
Question 16 of 25
16. Question
1 points
Two pipes A and B can fill a tank in 10 hours and 15 hours respectively while a third pipe C can empty the full tank in 20 hours. All the pipes are opened for 5 hours and then C is closed. Find the time in which the tank is full?
Correct
(1/10 + 1/15 – 1/20)*5 + (1/10 + 1/15)*T = 1.
We will get T = 2.5 hrs
so total time = 5 + 2.5 = 7.5 hrs
Incorrect
(1/10 + 1/15 – 1/20)*5 + (1/10 + 1/15)*T = 1.
We will get T = 2.5 hrs
so total time = 5 + 2.5 = 7.5 hrs
Question 17 of 25
17. Question
1 points
Three pipe P, Q and R can fill a tank in 12 minutes, 18 minutes and 24 minutes
respectively. The pipe R is closed 12 minutes before the tank is filled. In what time the tank is full?
Correct
Let T is the time taken by the pipes to fill the tank
(1/12 + 1/18 + 1/24)*(T – 12) + (1/12 +1/18)*12 = 1
We will get T = 108/13 = 8.(4/13) hrs
Incorrect
Let T is the time taken by the pipes to fill the tank
(1/12 + 1/18 + 1/24)*(T – 12) + (1/12 +1/18)*12 = 1
We will get T = 108/13 = 8.(4/13) hrs
Question 18 of 25
18. Question
1 points
On pipe P is 4 times faster than pipe Q and takes 45 minutes less than pipe Q. In what
time the cistern is full if both the pipes are opened together?
Correct
Let P takes x minutes to fill the tank alone, then Q will take 4x minutes to fill the tank
4x – x = 45, x = 15
So P will take 15 minutes and Q will take 60 minutes to fill the tank. Both will fill the tank in
(60*15)/(75) = 12 minutes
Incorrect
Let P takes x minutes to fill the tank alone, then Q will take 4x minutes to fill the tank
4x – x = 45, x = 15
So P will take 15 minutes and Q will take 60 minutes to fill the tank. Both will fill the tank in
(60*15)/(75) = 12 minutes
Question 19 of 25
19. Question
1 points
Two pipes can fill a tank in 15 and 20 hours respectively. The pipes are opened
simultaneously and it is found that due to the leakage in the bottom, 17/7 hours extra are
taken extra to fill the tank. If the tank is full, in what approximate time would the leak
empty it?
Correct
Total time taken by both pipes before the leak
was developed = 60/7 hours
now, leaks is developed which will take T time
to empty the tank so, (1/15 +1/20 – 1/T) = 1/11
solve for T, we will get 660/17 hours = 39 hours
(approx.)
Incorrect
Total time taken by both pipes before the leak
was developed = 60/7 hours
now, leaks is developed which will take T time
to empty the tank so, (1/15 +1/20 – 1/T) = 1/11
solve for T, we will get 660/17 hours = 39 hours
(approx.)
Question 20 of 25
20. Question
1 points
Two pipes A and B can fill a tank in 8 minutes and 12 minutes respectively. If both
the pipes are opened simultaneously, after what time should B be closed so that the tank
is full in 6 minutes?
Correct
Let after x minutes pipe B is closed
(1/8 + 1/12)*x + (1/8)*(6 -x) = 1
X= 3 minutes
Incorrect
Let after x minutes pipe B is closed
(1/8 + 1/12)*x + (1/8)*(6 -x) = 1
X= 3 minutes
Question 21 of 25
21. Question
1 points
In what time would a cistern be filled by three pipes whose diameters are 1cm, 2 cm
and 3 cm running together, when the largest pipe alone can fill the tank in 21 minutes?
The amount of water flowing through the pipe is directly proportional to the square of
its diameter.
Correct
More the diameter more will be the water
flowing through it and less will be the time
taken.
Means bigger pipe will take less time to fill the tank
So, for 1 cm time, (1^2)/(3^2) = 21/t, we get t = 189
For 2 cm time, (2^2)/(3^2) = 21/t. We get t = 189/4
So total time = 1/21 + 1/189 + 4/189 = 2/27
So total time = 13.5 minutes
Incorrect
More the diameter more will be the water
flowing through it and less will be the time
taken.
Means bigger pipe will take less time to fill the tank
So, for 1 cm time, (1^2)/(3^2) = 21/t, we get t = 189
For 2 cm time, (2^2)/(3^2) = 21/t. We get t = 189/4
So total time = 1/21 + 1/189 + 4/189 = 2/27
So total time = 13.5 minutes
Question 22 of 25
22. Question
1 points
Two pipes P and Q can fill a tank in 10 min and 12 min respectively and a waste pipe
can carry off 12 litres of water per minute. If all the pipes are opened when the tank is full
and it takes one hour to empty the tank. Find the capacity of the tank.
Correct
Let the waste pipe take ‘T’ time to empty the tank.
(1/10 + 1/12 – 1/T)*60 = -1
We will get T = 5 min
So capacity = 5*12 = 60ltr
Incorrect
Let the waste pipe take ‘T’ time to empty the tank.
(1/10 + 1/12 – 1/T)*60 = -1
We will get T = 5 min
So capacity = 5*12 = 60ltr
Question 23 of 25
23. Question
1 points
One pipe fill 1/4 of the tank in 4 minutes and another pipe fills 1/5 of the tank in 4
minutes. Find the time taken by both pipe together to fill half the tank?
Correct
Incorrect
Question 24 of 25
24. Question
1 points
Two pipes can separately fill the tank in 15hrs and 30hrs respectively. Both the pipe
are opened and when the tank is 1/3 full a leak is developed due to which 1/3 water
supplied by the pipe leaks out. What is the total time to fill the tank?
Correct
(1/15 + 1/30)*T1 = 1/3, T1 = 10/3 hr
Now after leak is developed, [(1/15 + 1/30) –(1/3)*(1/15 + 1/30)]*T2 = 2/3
T2 = 10 hr. So total time = 10 + 10/3 = 40/3 hr
Incorrect
(1/15 + 1/30)*T1 = 1/3, T1 = 10/3 hr
Now after leak is developed, [(1/15 + 1/30) –(1/3)*(1/15 + 1/30)]*T2 = 2/3
T2 = 10 hr. So total time = 10 + 10/3 = 40/3 hr
Question 25 of 25
25. Question
1 points
Three pipes A, B and C is attached to a cistern. A can fill it in 20 minutes and B can
fill it in 30 minutes. C is a waste pipe. After opening both the pipes A and B, Riya leaves
the cistern to fill and returns when the cistern is supposed to be filled. But she found that
waste pipe C had been left open, she closes it and now the cistern takes 5 minutes more to fill. In how much time the pipe C can empty the full cistern?
Correct
The tank supposed to be filled in (30*20)/50 = 12 minutes
so, (1/20 + 1/30)*12 – 12/C + (1/20 + 1/30)*5 =
1 (A and B work for 12 minutes and also C work
for 12 minutes and then A and B takes 5 more minutes to fill the tank)
solve for C, we will get C = 144/5 = 28.8
Incorrect
The tank supposed to be filled in (30*20)/50 = 12 minutes
so, (1/20 + 1/30)*12 – 12/C + (1/20 + 1/30)*5 =
1 (A and B work for 12 minutes and also C work
for 12 minutes and then A and B takes 5 more minutes to fill the tank)
solve for C, we will get C = 144/5 = 28.8