Online Mock Test in Percentage For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT
Percentage-Test 3
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Subject :- Quantitative Aptitude
Chapter :- Percentage- Test 3
Questions :- 25
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In an election contested by two parties A and B, party A secured 25 percent of the total
votes more than Party B. If party B gets 15000 votes. By how much votes does party B
loses the election?
Correct
Let total votes = T and party B gets 15000 votes
then party A will get T -15000 votes
T – 15000 – 15000 = 25T/100
T = 40000, so A get 25000 and B gets 15000
votes, so difference = 10000
Incorrect
Let total votes = T and party B gets 15000 votes
then party A will get T -15000 votes
T – 15000 – 15000 = 25T/100
T = 40000, so A get 25000 and B gets 15000
votes, so difference = 10000
Question 2 of 25
2. Question
1 points
A vendor sells 50 percent of apples he had and throws away 20 percent of the
remainder. Next day he sells 60 percent of the remainder and throws away the rest. What
percent of his apples does the vendor throw?
Correct
Let total apples be 100
first day he throws = 50*20/100 = 10 apples
next day he throws = 40*40/100 = 16 apples
so total = 26
Incorrect
Let total apples be 100
first day he throws = 50*20/100 = 10 apples
next day he throws = 40*40/100 = 16 apples
so total = 26
Question 3 of 25
3. Question
1 points
40% of the women are above 30 years of age and 80 percent of the women are less than
or equal to 50 years of age. 20 percent of all women play basketball. If 30 percent of the
women above the age of 50 plays basketball, what percent of players are less than or equal to 50 years?
Correct
take total women =100
Women less than or equal to 50 years = 80 and
women above 50 years = 20
20 = women plays basketball
30% of the women above 50 plays basketball =6
So remaining 14 women who plays basketball
are less than or equal to 50 years
So (14/20)*100 = 70%
Incorrect
take total women =100
Women less than or equal to 50 years = 80 and
women above 50 years = 20
20 = women plays basketball
30% of the women above 50 plays basketball =6
So remaining 14 women who plays basketball
are less than or equal to 50 years
So (14/20)*100 = 70%
Question 4 of 25
4. Question
1 points
Alisha goes to a supermarket and bought things worth rupees 60, out of which 40 paise
went on sales tax. If the tax rate is 10 percent, then what was the cost of tax free items?
Correct
tax = 40/100 = (10/100)*T, T = 4
so cost of tax free items = 60 – 4 – 0.40 = 55.60
Incorrect
tax = 40/100 = (10/100)*T, T = 4
so cost of tax free items = 60 – 4 – 0.40 = 55.60
Question 5 of 25
5. Question
1 points
60 percent of the employees of a company are women and 75% of the women earn
20000 or more in a month. Total number of employees who earns more than 20000 per
month in the company is 60 percent of the total employees. What fraction of men earns
less than 20000 per month?
Correct
let total employees are 100
males = 40 and females = 60 (45 women earns
more than 20000)
total 60 employee earns more than 20000 per
month, so number of males earns more than
20000 is 15
so fraction = 25/40 = 5/8
Incorrect
let total employees are 100
males = 40 and females = 60 (45 women earns
more than 20000)
total 60 employee earns more than 20000 per
month, so number of males earns more than
20000 is 15
so fraction = 25/40 = 5/8
Question 6 of 25
6. Question
1 points
In a library, 30% of the books are in History. 50% of the remaining are in English
and 40% of the remaining are in German. The remaining 4200 books are in regional languages. What is the total number of books in library?
Correct
Incorrect
Question 7 of 25
7. Question
1 points
A got 30% of the maximum marks in an examination and failed by 10 marks.
However, B who took the same examination got 40% of the total marks and got 15 marks
more than the passing marks. What were the passing marks in the examination?
Correct
(30/100)*T = P -10
(40/100)*T = P + 15
U will get P = 85
Incorrect
(30/100)*T = P -10
(40/100)*T = P + 15
U will get P = 85
Question 8 of 25
8. Question
1 points
The population of a town is 15000. It increases by 10 percent in the first year and 20 percent in the second year. But in the third year it decreases by 10 percent. What will be
the population after 3 years.
Correct
15000*(11/10)*(12/10)*(9/10) = 17820
Incorrect
15000*(11/10)*(12/10)*(9/10) = 17820
Question 9 of 25
9. Question
1 points
30 litre of solution contains alcohol and water in the ratio 2:3. How much alcohol must be added to the solution to make a solution containing 60% of alcohol?
Correct
alcohol = 30*2/5 = 12 and water = 18 litres
(12 + x)/(30 +x) = 60/100, we will get x = 15
Incorrect
alcohol = 30*2/5 = 12 and water = 18 litres
(12 + x)/(30 +x) = 60/100, we will get x = 15
Question 10 of 25
10. Question
1 points
2000 sweets need to be distributed equally among the school students in such a way that
each student gets sweet equal to 20% of total students. Then the number of sweets, each
student gets.
Correct
Incorrect
Question 11 of 25
11. Question
1 points
In a library 5 percent books are in English, 10 percent of the remaining are in hindi and 15 percent of the remaining are in Sanskrit. The remaining 11628 books are in French. Then find the total number of books in the library.
Correct
Incorrect
Question 12 of 25
12. Question
1 points
A solution contains 10% of salt by weight. On evaporation 15 litre of water evaporates
and now concentration of salt becomes 20 percent. Find the initial quantity of solution
Correct
Incorrect
Question 13 of 25
13. Question
1 points
A student has to get 40 percent marks to pass an examination. He got 60 marks but
fails by 20 marks. Find the maximum marks of the examination.
Correct
Incorrect
Question 14 of 25
14. Question
1 points
The number of seats in a cinema hall is decreased by 12 percent and the price of
tickets also decreased by 4 percent. Find the change in the collection of revenue.
Correct
Let initial seats = 100 and cost per seat = 100,
so initial revenue = 10000
now final revenue = 88*96 = 8448
% percent change in revenue = [(10000 –8448)/10000]*100 = 15.52%
Incorrect
Let initial seats = 100 and cost per seat = 100,
so initial revenue = 10000
now final revenue = 88*96 = 8448
% percent change in revenue = [(10000 –8448)/10000]*100 = 15.52%
Question 15 of 25
15. Question
1 points
A trader marks the price at 8 percent higher than the original price. Due to the hike
in demand he again increases the price by 10 percent. How much percent profit he gets.
Correct
Suppose initial price = 100
Then final price = 100*(108/100)*(110/100) =
118.8
So percent profit = 18.8
Incorrect
Suppose initial price = 100
Then final price = 100*(108/100)*(110/100) =
118.8
So percent profit = 18.8
Question 16 of 25
16. Question
1 points
The population of a town is 15000. It increases by 10 percent in the first year and 20 percent in the second year. But in the third year it decreases by 10 percent. What will be
the population after 3 years.
Correct
15000*(11/10)*(12/10)*(9/10) = 17820
Incorrect
15000*(11/10)*(12/10)*(9/10) = 17820
Question 17 of 25
17. Question
1 points
One type of liquid contains 20 percent milk and in other liquid it contains 30 percent
milk. If 4 parts of the first and 6 parts of the second are taken and formed a new liquid A.
Find the percentage of milk in third liquid.
Correct
milk = 20 and water = 80 (in 1st liquid)
milk = 30 and water = 70 (in 2nd liquid)
milk in final mixture = 20*4 + 30*6 = 260
so (260/1000)*100 = 26%
Incorrect
milk = 20 and water = 80 (in 1st liquid)
milk = 30 and water = 70 (in 2nd liquid)
milk in final mixture = 20*4 + 30*6 = 260
so (260/1000)*100 = 26%
Question 18 of 25
18. Question
1 points
A man has 2000 rupees in his account two years ago. In the first year he deposited 20
percent of the amount in his account. In the next year he deposited 10 percent of the
increased amount in the account. Find the total amount in the account of the person
after 2 years.
Correct
2000 + 400 + 240 = 2640 (400 in first year and
240 is added in the second year)
Incorrect
2000 + 400 + 240 = 2640 (400 in first year and
240 is added in the second year)
Question 19 of 25
19. Question
1 points
1000 sweets need to be distributed equally among the school students in such a way that
each student gets sweet equal to 10% of total students. Then the number of sweets, each
student gets.
Correct
No of students = T. Each student gets 10% of T.
So, T students get T^2/10 sweets.
T^2/10 = 1000. We get T =10
Incorrect
No of students = T. Each student gets 10% of T.
So, T students get T^2/10 sweets.
T^2/10 = 1000. We get T =10
Question 20 of 25
20. Question
1 points
If the price of an article is increased by 15%, then by how much the household should
decrease their consumption so as to keep his expenditure same.
Correct
Decrease in expenditure = (15/115)*100 =
300/23 %
Incorrect
Decrease in expenditure = (15/115)*100 =
300/23 %
Question 21 of 25
21. Question
1 points
If the price of an article is increased by 15%, then by how much the household should
decrease their consumption so as to keep his expenditure same.
Correct
Decrease in expenditure = (15/115)*100 =
300/23 %
Incorrect
Decrease in expenditure = (15/115)*100 =
300/23 %
Question 22 of 25
22. Question
1 points
The ratio between male and female in a city is 3: 7. The children percentage among
the males and females of the city is 25 and 30 percent respectively. If the number of adult males in the city is 18000, then find the population of the town?
Correct
Males and females are 3x and 7x respectively
(3x)*75/100 = 18000. X = 8000
so total population = 10*8000 = 80000
Incorrect
Males and females are 3x and 7x respectively
(3x)*75/100 = 18000. X = 8000
so total population = 10*8000 = 80000
Question 23 of 25
23. Question
1 points
Pankaj gave 50 percent of the amount to akash. Akash in turn gave two-fifth of the
amount to venu. After paying a bill of 500 rupees, venu now have 8000 rupees left with
him. Find the amount hold by pankaj initially.
Correct
Let pankaj have P amount initially
[[(50/100)*P]*2/5 – 500] = 8000
P = 42500
Incorrect
Let pankaj have P amount initially
[[(50/100)*P]*2/5 – 500] = 8000
P = 42500
Question 24 of 25
24. Question
1 points
Rakesh spent 30 percent of his monthly income on food items. Of the remaining
amount he spent 60 percent on clothes and bills. Now he save five-seventh of the
remaining amount and the he saves 120000 yearly, then find his monthly income.
Correct
Let monthly income is P
(70/100)*P*(40/100)*5/7 = 10000
P = 50000
Incorrect
Let monthly income is P
(70/100)*P*(40/100)*5/7 = 10000
P = 50000
Question 25 of 25
25. Question
1 points
Weight of A and B are in the ratio of 3:5. If the weight of A is increased by 20 percent
and then the total weight becomes 132 kg with an increase of 10 percent. B weight is
increased by what percent.
Correct
Weight of A and B are 3x and 5x.
Initial weight before increase = (132*100)/110 =
120
8x = 120. X = 15
Initial weight of A and B are 45 and 75 kg
respectively.
New weight of A = 54 so weight of B = 132 –
54 = 78.
So % increase = [(78-75)/75]*100 = 4 %
Incorrect
Weight of A and B are 3x and 5x.
Initial weight before increase = (132*100)/110 =
120
8x = 120. X = 15
Initial weight of A and B are 45 and 75 kg
respectively.
New weight of A = 54 so weight of B = 132 –
54 = 78.
So % increase = [(78-75)/75]*100 = 4 %