Online Mock Test in Percentage For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT
Percentage-Test 2
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Subject :- Quantitative Aptitude
Chapter :- Percentage- Test 2
Questions :- 25
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In a factory there are three types of bulbs L1, L2 and L3 which produces 20%, 15%
and 32% of the total products respectively. L1, L2 and L3 produces 3%, 7% and 2%
defective products, respectively. Find the percentage of non-defective products ?
In a class of 500 students ,65% are boys. 20% of the girls and 40% of the boys failed
the exam.Find the of students in the school passed the exam?
Correct
Total students are 100% = 500
Boys = 65% of 500 = 325,
Girls = 35% =35*500/100 =175
Girls failed in the exam= 175*80/100 = 140
Boys failed in the exam =40/100x 325 = 195
Total = 140+195 = 335
Incorrect
Total students are 100% = 500
Boys = 65% of 500 = 325,
Girls = 35% =35*500/100 =175
Girls failed in the exam= 175*80/100 = 140
Boys failed in the exam =40/100x 325 = 195
Total = 140+195 = 335
Question 3 of 25
3. Question
1 points
The population of village increases at the rate of 6% per annum. There is an additional
increase of 2% in the population due to rural development .Therefore the percentage
increase in the population after 2 years will be
The total salary of Guagn and Harish in an organization is Rs 30000. If the salary of
Gugan increase by 5% and salary of Harish increase by 7%, then their total salary would increase to Rs 31800. Find the salary of Harish ?
Correct
7% increases 30000 = Rs 2100 =30000+2100 =
Rs 32,100
But the actual increase in salary = 31800
Difference =32100 – 31800 = 300
2% = 300
Gugan’s salary =300/2 x 100 = 15000
Harish’s salary =30000 – 15000 = Rs 15000
Incorrect
7% increases 30000 = Rs 2100 =30000+2100 =
Rs 32,100
But the actual increase in salary = 31800
Difference =32100 – 31800 = 300
2% = 300
Gugan’s salary =300/2 x 100 = 15000
Harish’s salary =30000 – 15000 = Rs 15000
Question 5 of 25
5. Question
1 points
In an examination 70% candidates passed in prelims and 55% candidates passed in
Mains. If 62% candidates passed in both these subjects, then what per cent of candidates failed in both the exams?
Correct
Students passed in Prelims = 70%
Students passed in Mains = 55%
Students passed in both = 62%
No of students passed in at least one subject =
(70+55)-62 = 63%.
students failed in both subjects = 100-63 = 37%.
Incorrect
Students passed in Prelims = 70%
Students passed in Mains = 55%
Students passed in both = 62%
No of students passed in at least one subject =
(70+55)-62 = 63%.
students failed in both subjects = 100-63 = 37%.
Question 6 of 25
6. Question
1 points
In a class, 60% of the students are boys and in an examination, 80% of the girls scored
more than 40 marks(Maximum Marks:150). If 60% of the total students scored more than 40 marks in the same exam, what is the fraction of the boys who scored 40 marks or
less.
Correct
Assume Total no of students = 100
60% of the students are boys. so
Boys=60,Girls=40
No. of girls who scored more than 40 marks =
80% of girls = 80% of 40 = 32.
No. of students who scored more than 40 marks
= 60% of Total Students = 60
Therefore No. of boys who scored more than 40
marks = 60-32=28
No. of boys who scored less= Total boys –
Boys(scored more) = 60-28=32
Fraction=(scored less)/Total boys = 32/60 =8/15
Incorrect
Assume Total no of students = 100
60% of the students are boys. so
Boys=60,Girls=40
No. of girls who scored more than 40 marks =
80% of girls = 80% of 40 = 32.
No. of students who scored more than 40 marks
= 60% of Total Students = 60
Therefore No. of boys who scored more than 40
marks = 60-32=28
No. of boys who scored less= Total boys –
Boys(scored more) = 60-28=32
Fraction=(scored less)/Total boys = 32/60 =8/15
Question 7 of 25
7. Question
1 points
In an election 10% of the voters on the voters’ list did not cast votes and 60 voters
cast their ballot papers blank. There were only two candidates. The winner was supported by 47% of all voters in the list and he got 308 votes more than his rival. The
number of voters on the list was:
Correct
Let total number of voters= x
People who voted for the winner are = 0.47x
People who voted for the loser are = 0.47x-308
People who cast blanks are = 60
and people who did not vote are = 0.1x
solve the following equation
0.47x+0.47x-308+60+0.1x=x => x=6200
Incorrect
Let total number of voters= x
People who voted for the winner are = 0.47x
People who voted for the loser are = 0.47x-308
People who cast blanks are = 60
and people who did not vote are = 0.1x
solve the following equation
0.47x+0.47x-308+60+0.1x=x => x=6200
Question 8 of 25
8. Question
1 points
Deepak was to get a 50% hike in his pay but the computer operator wrongly typed the
figure as 80% and printed the new pay slip. He received this revised salary for three
months before the organization realized the mistake. What percentage of his correct new salary will get in the fourth month, if theexcess paid to him in the previous three
months is to be deducted from his fourth month?
The prices of two articles are in the ratio 3 : 4. If the price of the first article be increased
by 10% and that of the second by Rs. 4, the original ratio remains the same. The original
price of the second article is
Correct
Let the price of two articles are 3X and 4X.
After increment the ratio will be:
110% of 3x/(4X+4) = 3/4
x=10
Thus the CP of second article = 4X = 4*10 = Rs.40.
Incorrect
Let the price of two articles are 3X and 4X.
After increment the ratio will be:
110% of 3x/(4X+4) = 3/4
x=10
Thus the CP of second article = 4X = 4*10 = Rs.40.
Question 10 of 25
10. Question
1 points
The ratio of the number of boys and girls in a school is 3:2. If 20% of the boys and 25%
of the girls are scholarship holders, the percentage of the students who are not
scholarship holders is
Correct
Consider Total no of students = 100
Ratio is 3:2 i.e Boys=60 and Girls=40
20% of boys who get scholarship =
60*20/100=12%
25% of girls who get scholarship = 40*25/100
=10%
Therefore % of students who do not get
scholarship =100-(12+10) = 78%
Incorrect
Consider Total no of students = 100
Ratio is 3:2 i.e Boys=60 and Girls=40
20% of boys who get scholarship =
60*20/100=12%
25% of girls who get scholarship = 40*25/100
=10%
Therefore % of students who do not get
scholarship =100-(12+10) = 78%
Question 11 of 25
11. Question
1 points
Sohan spends 23% of an amount of money on an insurance policy, 33% on food, 19% on
children’s education and 16% on recreation. He deposits the remaining amount of Rs. 504
in bank. How much total amount did he spend on food and insurance policy together?
Correct
Total amount = x
Savings(%)
[100 – (23 + 33 + 19 + 16 )]% = 9 %
9% of x = 504
=> x = 504 * 100/9 = 5600
Amount spend on food and insurance policy
together = 56% of 5600 = Rs.3136
Incorrect
Total amount = x
Savings(%)
[100 – (23 + 33 + 19 + 16 )]% = 9 %
9% of x = 504
=> x = 504 * 100/9 = 5600
Amount spend on food and insurance policy
together = 56% of 5600 = Rs.3136
Question 12 of 25
12. Question
1 points
Deepika went to a fruit shop with a certain amount of money. She retains 15% of her money for auto fare. She can buy either 40 apples or 70 oranges with that remaining
amount. If she buys 35 oranges, how many more apples she can buy?
Correct
Assume Total amount = Rs.100
Auto fare= 15% of Total amount i.e Rs.15
Now the amount is Rs.85
Price of 70 oranges = Rs.85
Price of 35 oranges = (85/70)*35 = Rs. 42.50
Remaining amount to buy apples is =Rs. 42.50
Price of 40 apples = Rs.85
Price of X apples = Rs.42.50
X=(85/42.5)*40 = 20 Apples
Incorrect
Assume Total amount = Rs.100
Auto fare= 15% of Total amount i.e Rs.15
Now the amount is Rs.85
Price of 70 oranges = Rs.85
Price of 35 oranges = (85/70)*35 = Rs. 42.50
Remaining amount to buy apples is =Rs. 42.50
Price of 40 apples = Rs.85
Price of X apples = Rs.42.50
X=(85/42.5)*40 = 20 Apples
Question 13 of 25
13. Question
1 points
The price of a car is Rs. 4,50,000. It was insured to 80% of its price. The car was
damaged completely in an accident and the insurance company paid 90% of the
insurance. What was the difference between the price of the car and the amount received?
The tank-full petrol in Arun’s motor-cycle last for 10 days. If he starts using 25% more
every day, how many days will the tank-full petrol last?
Correct
Assume – Arun’s motorcycle uses 1L per day
and therefore tank’s Capacity = 10L.
25% increased per day= 1+(25/100) = 5/4 ie.1.25L per day
Days = 10/1.25 = 8
Incorrect
Assume – Arun’s motorcycle uses 1L per day
and therefore tank’s Capacity = 10L.
25% increased per day= 1+(25/100) = 5/4 ie.1.25L per day
Days = 10/1.25 = 8
Question 15 of 25
15. Question
1 points
Last year there were 610 boys in a school. The number decreased by 20 percent this
year. How many girls are there in the school if the number of girls is 175 percent of the
total number of boys in the school this year ?
Correct
No of boys in a school last year = 610
No of boys in a school for this year
610*80/100=122
610-122=488
No of girls =175/100 * 488=854
Incorrect
No of boys in a school last year = 610
No of boys in a school for this year
610*80/100=122
610-122=488
No of girls =175/100 * 488=854
Question 16 of 25
16. Question
1 points
A reduction of 20% percent in the price of rice enables a housewife to buy 5 kg more for
rupees 1200. The reduced price per kg of rice
Correct
let original price is x rupees per kg
1200/(4x/5) – 1200/x = 5
We will get x = 60, so reduced price = (4*60)/5
= 48
Incorrect
let original price is x rupees per kg
1200/(4x/5) – 1200/x = 5
We will get x = 60, so reduced price = (4*60)/5
= 48
Question 17 of 25
17. Question
1 points
The population of a village has increased annually at the rate of 20%. If at the end of 3
years it is 21600, the population in the beginning of the first year?
Correct
Incorrect
Question 18 of 25
18. Question
1 points
12 percent of the voters in an election did not cast their votes. In this election there are
only two candidates. The winner by obtaining 45% of the total votes and defeated his rival by 2000 votes. The total number of votes in the election
Correct
12% percent didn’t cast their vote. 45% of total
votes get by the winning candidates, so
remaining 43% will be scored by his rival. So,
(45/100 -43/100)*P = 2000
P = 100000
Incorrect
12% percent didn’t cast their vote. 45% of total
votes get by the winning candidates, so
remaining 43% will be scored by his rival. So,
(45/100 -43/100)*P = 2000
P = 100000
Question 19 of 25
19. Question
1 points
A number is first decreased by 25%. The decreased number is then increased by 20%.
The resulting number is less than the original number by 40. Then the original number is
Correct
Let the number is a
a – (75/100)*a*(120/100) = 40
we will get a = 400
Incorrect
Let the number is a
a – (75/100)*a*(120/100) = 40
we will get a = 400
Question 20 of 25
20. Question
1 points
The number of seats in a cinema hall is decreased by 8% and also the price of the
ticket is increased by 4 percent. What is the effect on the revenue collected?
Correct
Let initially seats are 100 and price of each seat
is 100, so total initial revenue = 10000
now, seats are 92 and price of each seat = 104,
so total revenue = 92*104 = 9568
so percent change in revenue = (432/10000)*100
= 4.32 decrease
Incorrect
Let initially seats are 100 and price of each seat
is 100, so total initial revenue = 10000
now, seats are 92 and price of each seat = 104,
so total revenue = 92*104 = 9568
so percent change in revenue = (432/10000)*100
= 4.32 decrease
Question 21 of 25
21. Question
1 points
A man spends 60% of his income. His income is increased by 20% and his
expenditure also increases by 10%. Find the percentage decrease in his saving?
Correct
Let initially income is 100. So, expenditure = 60
and saving = 40
now income is increased by 20% i.e. 120. So,
expenditure = (70/100)*120 = 84 and saving =
36
so % percent decrease in saving = (4/40)*100 =10%
Incorrect
Let initially income is 100. So, expenditure = 60
and saving = 40
now income is increased by 20% i.e. 120. So,
expenditure = (70/100)*120 = 84 and saving =
36
so % percent decrease in saving = (4/40)*100 =10%
Question 22 of 25
22. Question
1 points
Weights of two friends A and B are in the ratio of 1:2. A’s weight increases by 20% and
the total weight of A and B together becomes 60 kg, with an increase of 30%. By what
percent the weight of B increase?
Correct
weight of A is x and weight of B is 2x
given that 60 kg weight is the 30% percent
increase of the original weight, so
(130/100)*W = 60, W = 600/13 kg (W =
original weight)
X + 2x = 600/13, x = 200/13
So weight of A = 200/13 and of B = 400/13
(120/100)*(200/13) + [(100 + a)/100]*(400/13)
= 60
Solve for a. We will get a = 35%
Incorrect
weight of A is x and weight of B is 2x
given that 60 kg weight is the 30% percent
increase of the original weight, so
(130/100)*W = 60, W = 600/13 kg (W =
original weight)
X + 2x = 600/13, x = 200/13
So weight of A = 200/13 and of B = 400/13
(120/100)*(200/13) + [(100 + a)/100]*(400/13)
= 60
Solve for a. We will get a = 35%
Question 23 of 25
23. Question
1 points
The marked price of an article is 20% higher than the cost price. A discount of 20%
is given on the marked price. In this transaction the seller
Correct
let cost price = 100 so, marked price = 120
now discount of 20% is given, so sp =
120*80/100 = 96
so % loss = (4/100)*100 = 4 percent
Incorrect
let cost price = 100 so, marked price = 120
now discount of 20% is given, so sp =
120*80/100 = 96
so % loss = (4/100)*100 = 4 percent
Question 24 of 25
24. Question
1 points
When the price of rice is increased by 30 percent, a family reduces its consumption
such that the expenditure is only 20 percent more than before. If 50 kg of rice is consumed by family before, then find the new consumption of family (approx.)
Correct
Suppose initially price per kg of rice is 100 then
their expenditure is 5000.
Now their expenditure is only increased by only
20% i.e – 6000.
Increased price of rice = 130.
So new consumption = 6000/130 = 46
Incorrect
Suppose initially price per kg of rice is 100 then
their expenditure is 5000.
Now their expenditure is only increased by only
20% i.e – 6000.
Increased price of rice = 130.
So new consumption = 6000/130 = 46
Question 25 of 25
25. Question
1 points
A man has 4000 rupees in his account two years ago. In the first year he deposited 20
percent of the amount in his account. In the next year he deposited 10 percent of the
increased amount in the account. Find the total amount in the account of the person
after 2 years.