Online Quiz in Percentage For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT
Percentage-Test 1
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Subject :- Quantitative Aptitude
Chapter :- Percentage- Test 1
Questions :- 25
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Veena bought a watch costing Rs. 1404 including sales tax at 8%. She asked the
shopkeeper to reduce the price of the watch so that she can save the amount equal to the
tax. The reduction of the price of the watch is?
Correct
1.08x = 1404
x = 1300
The reduction of the price of the watch = 104
Incorrect
1.08x = 1404
x = 1300
The reduction of the price of the watch = 104
Question 2 of 25
2. Question
1 points
A Sales Executive gets a commission on total sales at 8%. If the sale is exceeded
Rs.10,000 he gets an additional commission as a bonus of 4% on the excess of sales over
Rs.10,000. If he gets the total commission of Rs.950, then the bonus he received is?
Correct
Commission up to 10000 = 10000 * 8/100 = 800
Ratio = 2x:x ; Commission = 2x, Bonus = x ;
Bonus = 950 – 800 * 1/3 = 150 * 1/3 = 50
Incorrect
Commission up to 10000 = 10000 * 8/100 = 800
Ratio = 2x:x ; Commission = 2x, Bonus = x ;
Bonus = 950 – 800 * 1/3 = 150 * 1/3 = 50
Question 3 of 25
3. Question
1 points
In a College there are 1800 students. Last day except 4% of the boys all the students
were present in the college. Today except 5% of the girls all the students are present in the college, but in both the days number of students present in the college, were same.
The number of girls in the college is?
Correct
From Options;
let Number of girls = 800
Number of boys = 1000
96% of 1000 + 800 = 95% of 800 +
1000[satisfies the condition; Check the condition
with other options also]
Incorrect
From Options;
let Number of girls = 800
Number of boys = 1000
96% of 1000 + 800 = 95% of 800 +
1000[satisfies the condition; Check the condition
with other options also]
Question 4 of 25
4. Question
1 points
In a library 60% of the books are in Hindi, 60% of the remaining books are in English
rest of the books are in Malayalam. If there are 4800 books in English, then the total
number of books in Malayalam are?
Correct
Let there are X books in the library.
Hindi books = 60% of X = 60X /100 = 0.6X
Remaining Books = X – 0.6X = 0.4X
English books = 40% of reaming books = 60%
of 0.4X = 0.24X.
Malayalam Books = X-0.6X -0.24X = 0.16X
Given,
0.24X = 4800
X = 4800/0.24 = 20000
Malayalam Books = 0.16X = 0.16*20000 =
3200.
Incorrect
Let there are X books in the library.
Hindi books = 60% of X = 60X /100 = 0.6X
Remaining Books = X – 0.6X = 0.4X
English books = 40% of reaming books = 60%
of 0.4X = 0.24X.
Malayalam Books = X-0.6X -0.24X = 0.16X
Given,
0.24X = 4800
X = 4800/0.24 = 20000
Malayalam Books = 0.16X = 0.16*20000 =
3200.
Question 5 of 25
5. Question
1 points
80% of a small number is 4 less than 40% of a larger number. The larger number is 125
greater than the smaller one. The sum of these two numbers is
Correct
smaller number = x; larger number = y
0.8x + 4 = 0.4y
4y – 8x = 40
y – x = 125
x = 115; y = 240
x + y = 355
Incorrect
smaller number = x; larger number = y
0.8x + 4 = 0.4y
4y – 8x = 40
y – x = 125
x = 115; y = 240
x + y = 355
Question 6 of 25
6. Question
1 points
In a private company 60% of the employees are men and 48% of the employees
are Engineer and 66.6% of Engineers are men. The percentage of women who are not
engineers is?
Correct
Men = 600x
Women = 400x
Total engineers = 480x
Male engineers = 480x * 0.66 = 320x
Women who are Engineers = 160x
Women who are not Engineers = 400x – 160x =
240x
Required percentage = 240/400 * 100 = 60%
Incorrect
Men = 600x
Women = 400x
Total engineers = 480x
Male engineers = 480x * 0.66 = 320x
Women who are Engineers = 160x
Women who are not Engineers = 400x – 160x =
240x
Required percentage = 240/400 * 100 = 60%
Question 7 of 25
7. Question
1 points
Initially, Suresh has Rs.200 in his paytm wallet then he increased it by 20%. Once
again he increased his amount by 25%. The final value of money in his wallet will be how
much % greater than the initial amount?
Mr.Ramesh gives 10% of some amount to his wife and 10% of the remaining to hospital
expenses and again 10% of the remaining amount to charity. Then he has only Rs.7290
with him. What is the initial sum of money with that person?
Correct
Remaining amount = x * 0.9 * 0.9 * 0.9
0.729x = 7290
x = 10000
Incorrect
Remaining amount = x * 0.9 * 0.9 * 0.9
0.729x = 7290
x = 10000
Question 9 of 25
9. Question
1 points
Initially, a shopkeeper had “x” pens. A customer bought 10% of pens from “x” then
another customer bought 20% of the remaining pens after that one more customer
purchased 25% of the remaining pens. Finally, shopkeeper is left with 270 pens in his
shop. How many pens were there initially in his shop?
Correct
x*0.9*0.8*0.75 =270
x = 270 * 10000 / 9 * 8 * 75
x = 500
Incorrect
x*0.9*0.8*0.75 =270
x = 270 * 10000 / 9 * 8 * 75
x = 500
Question 10 of 25
10. Question
1 points
The cost of packaging of the oranges is 20% the cost of fresh oranges themselves. The
cost of oranges increased by 30% but the cost of packaging decreased by 50%, then the
percentage change of the cost of packed oranges, if the cost of packed oranges is equal
to the sum of the cost of fresh oranges and cost of packaging
Correct
Let initial Cost of fresh, oranges = 100.
packaging cost = 20. Initial total cost = 100 + 20
= 120
After increasing in cost of fresh mangoes 30%,
Cost of fresh mangoes = 130
And cost of packing go down by 50 % so,
Let initial Cost of fresh, oranges = 100.
packaging cost = 20. Initial total cost = 100 + 20
= 120
After increasing in cost of fresh mangoes 30%,
Cost of fresh mangoes = 130
And cost of packing go down by 50 % so,
Cost Price of two laptops is same. One of the laptops is sold at a profit of 15% and the
Selling Price of another one laptop is Rs. 3400 more than the first one. The net profit is
20%. What is the Cost Price of Each laptop?
In an office there are 40% female employees. 50% of the male employees are UG graduates. The total 52% of employees are UG graduates out of 1800 employees.
What is the number of female employees who are UG graduates?
Correct
Total employees = 1800
female employees = 40%
male employees = 60%
50% of male employess = UG graduates = 30%
Female employees who are UG graduates = 22%
22% of 1800 = 396
Incorrect
Total employees = 1800
female employees = 40%
male employees = 60%
50% of male employess = UG graduates = 30%
Female employees who are UG graduates = 22%
22% of 1800 = 396
Question 13 of 25
13. Question
1 points
Ravi got 70% in English and 56% in Biology and the maximum marks of both
papers is 100. What percent does he score in Maths, if he scores 60% marks in all the three subjects?. Maximum Marks of Maths paper is 200.
Correct
70 + 56 + x = 60% of all three subjects
70 + 56 + x = 60% of 400
x = 240 – 126 = 114
% = 114/200 * 100 = 57%
Incorrect
70 + 56 + x = 60% of all three subjects
70 + 56 + x = 60% of 400
x = 240 – 126 = 114
% = 114/200 * 100 = 57%
Question 14 of 25
14. Question
1 points
Ankita is 25 years old. If Rahul’s age is 25% greater than that of Ankita then how
much percent Ankita’s age is less than Rahul’s age?
Correct
Percentage decrease = 25/125 * 100 = 20%
Incorrect
Percentage decrease = 25/125 * 100 = 20%
Question 15 of 25
15. Question
1 points
Mr.Ravi’s salary was reduced by 25% for three months. But after the three months, his
salary was increased to the original salary. What is the percentage increase in salary of
Mr.Ravi?
Correct
Percentage increase = 25/75 * 100 = 33.33%
Incorrect
Percentage increase = 25/75 * 100 = 33.33%
Question 16 of 25
16. Question
1 points
In an election only two candidates A and B contested 30% of the voters did not vote and
1600 votes were declared as invalid. The winner, A got 4800 votes more than his
opponent thus he secured 51% votes of the total voters on the voter list. Percentage votes of the loser candidate, B out of the total voters on the voter list is:
Correct
Total voters on the voter list = x
0.51x + 0.51x – 4800 = 0.70x – 1600
1.02x – 4800 = 0.70x – 1600
x = 10000
Votes of the loser candidate = 5100 – 4800 =
300
Percentage votes of the loser candidate =
300/10000 * 100 = 3%
Incorrect
Total voters on the voter list = x
0.51x + 0.51x – 4800 = 0.70x – 1600
1.02x – 4800 = 0.70x – 1600
x = 10000
Votes of the loser candidate = 5100 – 4800 =
300
Percentage votes of the loser candidate =
300/10000 * 100 = 3%
Question 17 of 25
17. Question
1 points
In a school there are 2000 students. On January 2nd, all the students were present in
the school except 4% of the boys and on January 3rd, all the students are present in
the school except 28/3% of the girls, but in both the days number of students present in the school, were same. The number of girls in the school is?
Correct
From Options;
let Number of girls = 600
Number of boys = 1400
96% of 1400 + 600 = [600 – 28/3 % of 600] +
1400 = 1944[satisfies the condition; Check the
condition with other options also]
Incorrect
From Options;
let Number of girls = 600
Number of boys = 1400
96% of 1400 + 600 = [600 – 28/3 % of 600] +
1400 = 1944[satisfies the condition; Check the
condition with other options also]
Question 18 of 25
18. Question
1 points
A school has raised 75% of the amount it needs for a new building by receiving an
average donation of Rs. 1200 from the parents of the students. The people already
solicited represents the parents of 60% of the students. If the School is to raise exactly the amount needed for the new building, what should be the average donation from the
remaining students to be solicited?
Correct
Let the number of parents be x who has been
asked for the donations.
People already solicited = 60% of x = 0.6x
Remaining people = 40% of x = 0.4x
Amount collected from the parents solicited=
1200 *0.6x = 720x
720x = 75%; Remaining amount = 25% = 240x
Thus, Average donations from remaining
parents = 240x /0.4x = 600
Incorrect
Let the number of parents be x who has been
asked for the donations.
People already solicited = 60% of x = 0.6x
Remaining people = 40% of x = 0.4x
Amount collected from the parents solicited=
1200 *0.6x = 720x
720x = 75%; Remaining amount = 25% = 240x
Thus, Average donations from remaining
parents = 240x /0.4x = 600
Question 19 of 25
19. Question
1 points
The monthly income of Shyama and Kamal together is Rs.28000. The income of
Shyama and Kamal is increased by 25% and 12.5% respectively. The new income of
Kamal becomes 120% of the new salary of Shyama. What is the new income of Shyama?
Correct
The monthly income of Shyama and Kamal =>
S + K = 28000 —(1)
Shyama’s income = x; Kamal’s income = 28000
– x.
K = 120/100 * S —(2)
S’s new income = (28000 – x)*112.5/100
K’s new income = x * 125/100
(28000 – x)*112.5/100 = x * 125/100
x = 12000
New Income of Shyama = 125% of 12000 =
15000
Incorrect
The monthly income of Shyama and Kamal =>
S + K = 28000 —(1)
Shyama’s income = x; Kamal’s income = 28000
– x.
K = 120/100 * S —(2)
S’s new income = (28000 – x)*112.5/100
K’s new income = x * 125/100
(28000 – x)*112.5/100 = x * 125/100
x = 12000
New Income of Shyama = 125% of 12000 =
15000
Question 20 of 25
20. Question
1 points
500 kg of ore contained a certain amount of iron. After the first blast furnace process,
200 kg of slag containing 12.5% of iron was removed. The percentage of iron in the
remaining ore was found to be 20% more than the percentage in the original ore. How
many kg of iron were there in the original 500 kg ore?
Correct
Initially ‘x’ kg of iron in 500 kg ore.
Iron in the 200 kg of removed =200*12.5/100=
25 kg.
The percentage of iron in the remaining ore was
found to be 20% more than the percentage in the
original ore
So (x-25)/300 = (120/100)*x/500
=> x – 25 = 18x/25
=> 7x = 625
=> x = 89.2
Incorrect
Initially ‘x’ kg of iron in 500 kg ore.
Iron in the 200 kg of removed =200*12.5/100=
25 kg.
The percentage of iron in the remaining ore was
found to be 20% more than the percentage in the
original ore
So (x-25)/300 = (120/100)*x/500
=> x – 25 = 18x/25
=> 7x = 625
=> x = 89.2
Question 21 of 25
21. Question
1 points
In a class of 60 students , 40% of the students passed in Reasoning, 5% of the students
failed in Quants and Reasoning, and 20% of the students passed in both the subjects. Find the number of student passed only in Quants?
Correct
Total students=60
Failed in both=5% of 60=3
Passed in both=20% of 60=12
Passed in reasoning=50% of 60=24
Those passed only in reasoning =24-12=12
students.
Passed only in Quants=60-(12+12+3)=33
Incorrect
Total students=60
Failed in both=5% of 60=3
Passed in both=20% of 60=12
Passed in reasoning=50% of 60=24
Those passed only in reasoning =24-12=12
students.
Passed only in Quants=60-(12+12+3)=33
Question 22 of 25
22. Question
1 points
The maximum marks per paper in 3 subjects in Mathematics , Physics and
Chemistry are set in the ratio 1 : 2 : 3 respectively. Giri obtained 40% in
Mathematics, 60% in Physics and 35% in Chemistry papers. What is overall percentage
marks did he get overall?
In an examination, 50% of the students passed in Science and 75% passed in Social,
while 20% students failed in both the subjects. If 270 students passed in both
subjects, find the total number of students who appeared in the exam?
Correct
Answer – 3.600 Explanation :
passed in science = 50%
passed in social = 75%
20% students failed in both the subjects
and 80% passed in at least one subject
No of students passed in both subjects =
50+75−x=80 x=45% 45% of x = 270 x =
270*100/45 = 600
Total number of students =600
Incorrect
Answer – 3.600 Explanation :
passed in science = 50%
passed in social = 75%
20% students failed in both the subjects
and 80% passed in at least one subject
No of students passed in both subjects =
50+75−x=80 x=45% 45% of x = 270 x =
270*100/45 = 600
Total number of students =600
Question 24 of 25
24. Question
1 points
Fresh fruits contain 75% while dry fruits contain 20% water. If the weight of dry fruits
is 300 kg, what was its total weight when it was fresh?
Correct
Quantity of water in 300 kg dry fruits, = (20
/100) *300 = 60 kg
Quantity of fruit alone= 300-60 =240 kg
25 kg fruit piece in 100 kg fresh fruits
For 240 = (100 *240)/25 = 960 kg.
Incorrect
Quantity of water in 300 kg dry fruits, = (20
/100) *300 = 60 kg
Quantity of fruit alone= 300-60 =240 kg
25 kg fruit piece in 100 kg fresh fruits
For 240 = (100 *240)/25 = 960 kg.
Question 25 of 25
25. Question
1 points
In a college election 35% voted for Person A, whereas 42% voted for Person B. The
remaining people were not vote to any person. If the difference between those who vote for Person B in the election and those who are uncertain was 570, how many people
are participated in the college election?
Correct
Let the number of individuals involved in
election be x.
Percentage of those who were not vote = 100-
(35+42) = 23%
The difference between those who voted
42% of x – 23% of x = 570
19% of x = 570
x=570*100/19 = 3000
Incorrect
Let the number of individuals involved in
election be x.
Percentage of those who were not vote = 100-
(35+42) = 23%
The difference between those who voted
42% of x – 23% of x = 570
19% of x = 570
x=570*100/19 = 3000