Online Quiz in Mixture and Allegations For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT
Mixture and Allegations-Test 3
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Subject :- Quantitative Aptitude
Chapter :- Mixture and Allegations-Test 3
Questions :- 25
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The ratio of A & B in a mixture is 8:1, 15ltr of mixture is taken out and same amount of
B is added, now ratio become 4:3. Find the initial amount of A in the mixture (approx)?
Correct
initial …………A : B
. 8 : 1 →(1)
Find 4 : 3 →(2)
Make value of A same, multiply by 2 in
equation (2)
A : B
8 : 1
8 : 6 (+5)
5 = 15
1=3
8+6=14 =42
So initial = 8/9 *42 = 37.33
Incorrect
initial …………A : B
. 8 : 1 →(1)
Find 4 : 3 →(2)
Make value of A same, multiply by 2 in
equation (2)
A : B
8 : 1
8 : 6 (+5)
5 = 15
1=3
8+6=14 =42
So initial = 8/9 *42 = 37.33
Question 2 of 25
2. Question
1 points
A shopkeeper sells his milk at cost price but he add some water and earn 16(2/3)% profit. Find the ratio of milk and water?
Correct
In this case we will let milk 100 and water
profit
Milk : Water
100 : 16(2/3)%
6 : 1
Incorrect
In this case we will let milk 100 and water
profit
Milk : Water
100 : 16(2/3)%
6 : 1
Question 3 of 25
3. Question
1 points
There is 70ltr milk in a container. From this 7ltr of milk is taken out and added some
quantity of water. This process is repeated two more times. Find the remaining milk in
container?
A man has to distribute Rs65 in a class of 50 students. He gives 1.5 rupee to boys and
1 rupee to girls each. Find how many girls are there in the class?
In an alloy the ratio of copper and aluminum is 4:5 and in other alloy the ratio of copper and aluminum is 6:7. In what ratio these alloy should be taken to make ratio of copper and aluminum is 5:6?
In a bag there are three types of coins, 1 rupee, 50 paisa and 25 paisa in the ratio of
5:10:24. There total value is Rs 208. The total number of coins is?
400 gm of sugar solution has 30% sugar in it. How much sugar should be added to make it 50% in the solution (in gm)?
Correct
30% of 400 =120
Remaining =280, this will remain same in
another solution but now it will become
50%. So
50% = 280
100% = 560
Difference = 560-400 = 160
Incorrect
30% of 400 =120
Remaining =280, this will remain same in
another solution but now it will become
50%. So
50% = 280
100% = 560
Difference = 560-400 = 160
Question 8 of 25
8. Question
1 points
A mixture of certain quantity of milk with 15 ltr of water is sold at 80 paisa/ltr. If pure
milk be worth Rs 1.10 per ltr. How much milk is there in the mixture?
A merchant borrowed Rs 3500 from two money lenders. For one loan he paid 14%
p.a and for other 18% p.a. the interest paid for one year was Rs525. How much did he
borrow at 18%p.a?
Correct
525/3500 * 100 = 15%
14………….18
. 15
3……………..1
1/4 * 3500 = 875
Incorrect
525/3500 * 100 = 15%
14………….18
. 15
3……………..1
1/4 * 3500 = 875
Question 10 of 25
10. Question
1 points
How many kg of salt at 42 paisa per kg must a man mix with 25 kg of salt at 24
paisa per kg, so that he may on selling the mixture at 40 paisa per kg, gain 25% on the
outlay?
After selling an article a man gains 25%. Also he uses a false weight of 10%. Find the total profit earn by him?
Correct
in this case we keep 1000 in the middle,
Add profit one side and minus weight on
the other side, to find net profit.
. 1000
(weight)900 1250(profit)
. 1250-900= 350
350/900 * 100= 38(8/9)%
Incorrect
in this case we keep 1000 in the middle,
Add profit one side and minus weight on
the other side, to find net profit.
. 1000
(weight)900 1250(profit)
. 1250-900= 350
350/900 * 100= 38(8/9)%
Question 12 of 25
12. Question
1 points
A man wants to gain 20% after selling milk at cost price. So in what ratio he has to add
water to earn this profit?
Correct
Incorrect
Question 13 of 25
13. Question
1 points
A shopkeeper has two types of article. The CP of 1st article is 20Rs/kg and other
article is X Rs/kg. He has quantity of 1st article is 10kg and other article is 20 kg. He
sold the mixture of these article at Rs 39/kg with a profit of 30%. Find the value of X?
A sugar solution of 60 kg has 20% sugar in it. How much sugar must be added in this to make it half of the solution?
Correct
20% of 60kg = 12
Sugar = 12
Water= 48
Now if we add only sugar then the value of
water will be constant and that will be 50%
of solution
So : 50% = 48
100%= 96 new solution
Now 96-60= 36kg
Incorrect
20% of 60kg = 12
Sugar = 12
Water= 48
Now if we add only sugar then the value of
water will be constant and that will be 50%
of solution
So : 50% = 48
100%= 96 new solution
Now 96-60= 36kg
Question 15 of 25
15. Question
1 points
A man has 80 pens. He sells some of these at 15% profit and the rest at 10%loss.
Overall he gets a profit of 10%. Find how many pens were sold at 15% profit ?
There are two types of jar. In the 1st jar the ratio of copper and aluminium is 1:2 and in
the 2nd Jar is 1: 4. In what ratio these two jar should be mix to make 3rd jar In which
the ratio of copper & aluminium become 1:3?
Correct
copper in 1st = 1/3
Copper in 2nd = 1/5
copper in 3rd = ¼
1/3 1/5
. 1/4
1/20 1/12
3 : 5
Incorrect
copper in 1st = 1/3
Copper in 2nd = 1/5
copper in 3rd = ¼
1/3 1/5
. 1/4
1/20 1/12
3 : 5
Question 18 of 25
18. Question
1 points
A butler stole wine from a butt of sherry which contained 50% spirit and he replaced
it with wine which contains 20% spirit. Now the strength of butt remain only 30%.
How much of the butt did he steal?
Correct
50%………………20%
…..…..30%
10…………….20
1 : 2
Both types of wine were in the ratio 1 : 2
Butt with alcohol of 50% strengeth = 1/3
So stole = 2/3 part
Incorrect
50%………………20%
…..…..30%
10…………….20
1 : 2
Both types of wine were in the ratio 1 : 2
Butt with alcohol of 50% strengeth = 1/3
So stole = 2/3 part
Question 19 of 25
19. Question
1 points
There are 65 students in a class. 39 rupees were distributed among them so that each
boy gets 80 paisa and each girl gets 30 paisa. Find the number of girls in the class?
Correct
The average money received by every
student = 3900/65 = 60paisa
Boy girl
80 30
… 60
30 20
3 : 2
Girl = 2/5 *65 = 26
Incorrect
The average money received by every
student = 3900/65 = 60paisa
Boy girl
80 30
… 60
30 20
3 : 2
Girl = 2/5 *65 = 26
Question 20 of 25
20. Question
1 points
A container has 40 l of milk. From this, 4 l of milk is taken out and replaced with
water. Now 4 l of mixture is taken out and replaced with water again. Find how much
quantity of milk is remaining in the container?
Correct
4/10 = 1/10 out so remaining = 9/10
The process is repeated 2 times, so multiply
it 2 times and multiply it with total quantity
also
So (9/10)2 * 40 = 32.4 l
Incorrect
4/10 = 1/10 out so remaining = 9/10
The process is repeated 2 times, so multiply
it 2 times and multiply it with total quantity
also
So (9/10)2 * 40 = 32.4 l
Question 21 of 25
21. Question
1 points
A container contains 80 Litre milk. From this container 8 Litre milk was taken out
and replaced with water. This process was further repeated two times. How much milk
is now contained in the container?
Correct
Remaining Quantity= x*(1-y/x)^n
where x= quantity of initial liquid=80 here;
y= quantity of newly added liquid=8 here
n= number of times the process is
repeated= 3 here
80*(1-8/80)^3 = 58.32 L
Incorrect
Remaining Quantity= x*(1-y/x)^n
where x= quantity of initial liquid=80 here;
y= quantity of newly added liquid=8 here
n= number of times the process is
repeated= 3 here
80*(1-8/80)^3 = 58.32 L
Question 22 of 25
22. Question
1 points
A trader sold two articles in Rs 800. On one he gained 33(1/3)% and on another he
gained 20%. In this whole transaction he gained 25%. Find the cost price of the
second article (the one sold at 20% gain)
Correct
At 25% profit and SP=800; CP=640
33(1/3) 20
. 25
5 25/3
3:5 (by alligation)
hence CP od second article=5/8*640=400
Incorrect
At 25% profit and SP=800; CP=640
33(1/3) 20
. 25
5 25/3
3:5 (by alligation)
hence CP od second article=5/8*640=400
Question 23 of 25
23. Question
1 points
A mixture of certain quantity of milk with 20 Litre of water is sold at 80 paise per litre. If pure milk be worth Rs 1.20 per litre. How much milk is present in the mixture?
Correct
120 0
. 80
80 40
=>2:1
1=20 L
hence 2=40 L
Incorrect
120 0
. 80
80 40
=>2:1
1=20 L
hence 2=40 L
Question 24 of 25
24. Question
1 points
In an alloy, zinc and copper are in the ratio 1:3. In the second alloy the same elements
are in the ratio 2:3. If what proportion should the two alloys be mixed so as to
form a new alloy in which zinc and copper are in the ratio 1:2.
Correct
1/4 2/5
. 1/3
1/15 1/12
=>4:5
Incorrect
1/4 2/5
. 1/3
1/15 1/12
=>4:5
Question 25 of 25
25. Question
1 points
400 grams of sugar solution has 40% sugar in it. How much sugar should be added to
make it 50% in the solution?
Correct
40% of 400= 160 gm
remaining=240. This remaining quantity
will remain constant as only sugar is to be
added. For sugar to be 50% , the quantity of
sugar should be equal to 240
hence more to be added=240-160=80
Incorrect
40% of 400= 160 gm
remaining=240. This remaining quantity
will remain constant as only sugar is to be
added. For sugar to be 50% , the quantity of
sugar should be equal to 240
hence more to be added=240-160=80