Write a program in C to demonstrate how to handle the pointers in the program.
Solution:
#include <stdio.h>
void main()
{
int* p;
int a;
a=852;
printf(” Here in the declaration p = int pointer, int a= 29\n”);
printf(” Address of a : %p\n”,&a);
printf(” Value of a : %d\n”,a);
p=&a;
printf(” Now p is assigned with the address of a.\n”);
printf(” Address of pointer p : %p\n”,p);
printf(” Content of pointer p : %d\n”,*p);
a=563;
printf(” The value of a assigned to 563 now.\n”);
printf(” Address of pointer p : %p\n”,p);
printf(” Content of pointer p : %d\n”,*p);
*p=1954;
printf(” The pointer variable p is assigned the value 1954 now.\n”);
printf(” Address of a : %p\n”,&a);/*as p contain the address of a – so *p changed the value of a and now a become 1563*/
printf(” Value of a : %d\n\n”,a);
}
Output:
Here in the declaration p = int pointer, int a= 29
Address of a : 0x7ffee0797354
Value of a : 852
Now p is assigned with the address of a.
Address of pointer p : 0x7ffee0797354
Content of pointer p : 852
The value of a assigned to 563 now.
Address of pointer p : 0x7ffee0797354
Content of pointer p : 563
The pointer variable p is assigned the value 1954 now.
Address of a : 0x7ffee0797354
Value of a : 563
