Write a C Program to Find Whether the Given Number is Armstrong Number or not.
An Armstrong number is a number that is the sum of its own digits each raised to the power of the number of digits.
EX : 371 is an Armstrong number.
(3^3) + (7^3) + (1^3) = 371.
Code for check three digit Armstrong number in c
#include <stdio.h>
int main()
{
int num, temp, digit, sum = 0;
printf(“Enter a three-digit number: “);
scanf(“%d”, &num);
temp = num;
while (temp != 0)
{
// picking last digit from temp
digit = temp % 10;
sum += digit * digit * digit;
// removing last digit from the temp number
temp /= 10;
}
if (sum == num)
printf(“%d is an Armstrong number.”, num);
else
printf(“%d is not an Armstrong number.”, num);
return 0;
}
Output:
i) Enter a three-digit number: 153
Given number is Armstrong.
ii) Enter a three-digit number: 516
Given number is not Armstrong.
Code for check ‘n’ digit Armstrong number in c
#include<stdio.h>
#include<math.h>
int main()
{
long int n,s=0;
int a,t,d;
printf(“Enter a value : “);
scanf(“%ld”,&n); // Read the number.
t=n;
d=0; //here we calculate no,of digits of the given number
while(t>0)
{
d++;
t=t/10;
}
t=n;
while(t>0) //If entered number is greater than zero then only loop will execute
{
a=t%10; //pick last digit from temporary variable.
s=s+pow(a,d); //adding cube ‘a’ to ‘s’.
t=t/10; //removing last digit from ‘t’
}
if(n==s)
printf(“Given number is Armstrong\n”);
else
printf(“Given number is not Armstrong\n”);
return 0;
}
Output:
i) Enter a value : 1634
Given number is Armstrong.
ii) Enter a value : 632
Given number is not Armstrong.
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Task: Write a C program to generate Armstrong numbers from ‘m’ to ‘n’ natural numbers. For example user entered 250 & 500 then output will be : 370 371 407
