Online Quiz in Boat and Stream For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT
Boat and Stream-Test 3
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Subject :- Quantitative Aptitude
Chapter :- Boat and Stream-Test 3
Questions :- 25
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The speed of a Boat in standing water is 10 km/hr. It traveled Down Stream from point
A to B in certain time. After reaching B the Boat is powered by Engine then Boat started
to return from Point B to A. The time taken for Forward journey and Backward journey
are same. Then what is the speed of the stream?
Correct
S+R = D/t ; S-R+x = D/t
S+R = S-R+x
R =x/2
Incorrect
S+R = D/t ; S-R+x = D/t
S+R = S-R+x
R =x/2
Question 2 of 25
2. Question
1 points
A Boat going upstream takes 8 hours 24 minutes to cover a certain distance, while it
takes 5 hours to cover 5/7 of the same distance running downstream. Then what is
the ratio of the speed of boat to speed of water current?
Correct
(S-R)*42/5 = (S+R)*7
S:R = 11:1
Incorrect
(S-R)*42/5 = (S+R)*7
S:R = 11:1
Question 3 of 25
3. Question
1 points
A Boat takes total 16 hours for traveling downstream from point A to point B and coming back point C which is somewhere between A and B. If the speed of the Boat in Still water is 9 Km/hr and rate of stream is 6 Km/hr, then what is the distance between A and C?
Correct
16 = D/9+6 + x/9-6
Incorrect
16 = D/9+6 + x/9-6
Question 4 of 25
4. Question
1 points
A Boat takes 128 min less to travel to 48 Km downstream than to travel the same distance upstream. If the speed of the stream is 3 Km/hr. Then Speed of Boat in still water is?
Correct
32/15 = 48(1/s-3 – 1/s+3)
s= 12
Incorrect
32/15 = 48(1/s-3 – 1/s+3)
s= 12
Question 5 of 25
5. Question
1 points
The speed of Boat in Still water is 40 Km/hr and speed of the stream is 20 Km/hr.
The distance between Point A and Point B is 480 Km. The boat started traveling downstream from A to B, in the midway, it is powered by an Engine due to which speed of
the Boat increased. Now Boat reached Point B and started back to point A with help of the same engine. It took 19 hours for the entire journey. Then with the help of the engine, the speed of the boat increased by how many Km/hr?
Correct
19 = 240/60 + 240/60+x + 480/20+x
x = 20
Incorrect
19 = 240/60 + 240/60+x + 480/20+x
x = 20
Question 6 of 25
6. Question
1 points
A Boat covers upstream in 12 Hours 48 minutes to travel distance from Point A to B,
while it takes 6 hours to cover 3/4th of the same distance running downstream. The
speed of the current is 15 Km/hr. The boat covered both forward distance from A to B
and backward distance from B to A. Then what is the distance between A and B?
Correct
(S+R)*8 = (S-R)*64/5
S:R = 13:3
R = 15 S = 65
D = (65+15) *8 = 640
Incorrect
(S+R)*8 = (S-R)*64/5
S:R = 13:3
R = 15 S = 65
D = (65+15) *8 = 640
Question 7 of 25
7. Question
1 points
A Boat takes total 10 hours for traveling downstream from point A to point B and
coming back point C which is somewhere between A and B. The speed of the Boat in Still water is 9 Km/hr and rate of Stream is 3 Km/hr, then what is the distance between A
and B if the ratio of distance between A to C and distance between B to C is 2:1?
Correct
10 = D/12 + D/18
D = 72
Incorrect
10 = D/12 + D/18
D = 72
Question 8 of 25
8. Question
1 points
A Ship of Length 300m traveling from point A to B downstream passes a Ghat along
the river in 18 sec, while in return it passes the same Ghat in 24 sec. If the rate of current
is 9 Km/hr. Then what is the length of the Ghat?
Correct
(S+9)*18 = (S-9)*24
S =63
300+x = 72*5/18*18
x =60
Incorrect
(S+9)*18 = (S-9)*24
S =63
300+x = 72*5/18*18
x =60
Question 9 of 25
9. Question
1 points
Speeds of Boat A and B in still water are in the ratio of 3:2 Rate of current is 10 Km/hr.
Both Boats started from Point P to point Q downstream at the same time. After Boat B
reaching Point Q, in return journey, it is powered by engine due to which the speed of
the boat in still water is increased by 70%, while retuned Boat A returned to Point Q as usual. Both the boats returned back to point P at the same time. Then what is the speed of Boat A?
Correct
S 1 /S 2 = 3/2
R = 10
then
(1/3x+10)+ (1/3x-10) = (1/2x+10) + (1/3.4x-10)
x = 10
Speed of boat A =3*10 = 30
Incorrect
S 1 /S 2 = 3/2
R = 10
then
(1/3x+10)+ (1/3x-10) = (1/2x+10) + (1/3.4x-10)
x = 10
Speed of boat A =3*10 = 30
Question 10 of 25
10. Question
1 points
A Boat took 8 hours less to travel a distance downstream than to travel the same
distance upstream. If the speed of a boat in still water is 9 Km/hr and speed of a stream is 3 Km/hr. In total how much distance traveled by boat?
Correct
8 =D(1/6 – 1/12)
D =96
Total = 96+96 =192
Incorrect
8 =D(1/6 – 1/12)
D =96
Total = 96+96 =192
Question 11 of 25
11. Question
1 points
If Nishu can swim downstream at 6 kmph and upstream at 2 kmph.What is his speed in still water ?
Correct
If the speed downloadstream is a km/ hr and the
speed upstream is b km/ hr
then Speed in still water is = ½ (a+b) km / hr
[memory tool last 2 L cross and make
+] Explanation:
Given : speed downstream a = 6 km ph
Speed upstream b = 2kmph
Speed in still water = ½ (a+b) kmph
= ½ (6+2)
= 8/2 = 4kmph
speed in still water = 4kmph
Incorrect
If the speed downloadstream is a km/ hr and the
speed upstream is b km/ hr
then Speed in still water is = ½ (a+b) km / hr
[memory tool last 2 L cross and make
+] Explanation:
Given : speed downstream a = 6 km ph
Speed upstream b = 2kmph
Speed in still water = ½ (a+b) kmph
= ½ (6+2)
= 8/2 = 4kmph
speed in still water = 4kmph
Question 12 of 25
12. Question
1 points
Ashok can row upstream at 8kmph and downstream at 12kmph.What is the
speed of the stream ?
Correct
If the speed downstream is a kmph and the speed
upstream is b kmph
then
Speed of the stream = ½ (a-b) kmph
Explanation:
Speed downstream a = 12kmph
Speed upstream b = 8 kmph
Speed of the stream = ½ (a-b) = ½ (12-8)
= 4/2 = 2 kmph
speed of the stream = 2kmph
Incorrect
If the speed downstream is a kmph and the speed
upstream is b kmph
then
Speed of the stream = ½ (a-b) kmph
Explanation:
Speed downstream a = 12kmph
Speed upstream b = 8 kmph
Speed of the stream = ½ (a-b) = ½ (12-8)
= 4/2 = 2 kmph
speed of the stream = 2kmph
Question 13 of 25
13. Question
1 points
A man rows 750m in 775 seconds against the stream and returns in 7
1/2 minutes. What is rowing speed in still water ?
Correct
i) Speed in still water = ½ (a+b) kmph where ‘a’ is speed
downstream and ‘b’ is speed upstream
ii) a km / hr = a x 5/18 m /s
iii) a m/sec = a x 18/5 km/hr
Explanation:
Speed upstream ‘b’ = 750m / 775 sec = 30/31 m/sec
Speed downstream ‘a’ = 750 m/ (15/2)minutes [
1min=60 sec] a = 750m/450 sec =5/3 m/sec
speed in still water = ½ (a+b)
= ½ (750/450 + 750/675 ) m /sec
= ½ (750/450 + 750/675 ) x 18/5 km/hr
= ½ (5/3 + 30/31) x 18/5 km/hr
= 4.7 km/hr
Incorrect
i) Speed in still water = ½ (a+b) kmph where ‘a’ is speed
downstream and ‘b’ is speed upstream
ii) a km / hr = a x 5/18 m /s
iii) a m/sec = a x 18/5 km/hr
Explanation:
Speed upstream ‘b’ = 750m / 775 sec = 30/31 m/sec
Speed downstream ‘a’ = 750 m/ (15/2)minutes [
1min=60 sec] a = 750m/450 sec =5/3 m/sec
speed in still water = ½ (a+b)
= ½ (750/450 + 750/675 ) m /sec
= ½ (750/450 + 750/675 ) x 18/5 km/hr
= ½ (5/3 + 30/31) x 18/5 km/hr
= 4.7 km/hr
Question 14 of 25
14. Question
1 points
A man can row 9 (1/3) kmph in still water and finds that it takes him thrice as much time to row up than as to row down the same distance in the river. What is speed of the current ?
Correct
Let man’s rate upstream be x km/hr. Then his
rate downstream is 3 x km/hr
Given:
Speed in still water = 9 (1/3) = 28/3 km/hr
i.e, ½ (a+b) = 28/3 km/hr
½ (x+3x) = 28/3
2x = 28/3 x = 28/ 2 x 3 = 14/3 km/hr
rate upstream b = 14/3 km/hr and
rate downstream a = 14/3 x 3 = 14 km/hr
speed of the current = ½ (a-b) = ½ (14 – 14/3)
= ½ (42-14/3) = 28/6 = 4 (2/3) km/hr
Incorrect
Let man’s rate upstream be x km/hr. Then his
rate downstream is 3 x km/hr
Given:
Speed in still water = 9 (1/3) = 28/3 km/hr
i.e, ½ (a+b) = 28/3 km/hr
½ (x+3x) = 28/3
2x = 28/3 x = 28/ 2 x 3 = 14/3 km/hr
rate upstream b = 14/3 km/hr and
rate downstream a = 14/3 x 3 = 14 km/hr
speed of the current = ½ (a-b) = ½ (14 – 14/3)
= ½ (42-14/3) = 28/6 = 4 (2/3) km/hr
Question 15 of 25
15. Question
1 points
Sham can row a boat at 10kmph in still water. IF the speed of the stream is 6kmph, the time taken to row a distance of 80km down the stream is
Correct
Given:
Speed in still water, ½ (a+b) = 10 km/hr
a+b = 20 km/hr…………….(1)
speed of the stream, ½ (a-b) = 6km/hr
a-b = 12 km/hr …………….(2)
(1)+(2 ) we get 2a = 32
a = 16 km/hr
speed downstream =distance traveled / time taken
time taken = 80/16 = 5 hours
Incorrect
Given:
Speed in still water, ½ (a+b) = 10 km/hr
a+b = 20 km/hr…………….(1)
speed of the stream, ½ (a-b) = 6km/hr
a-b = 12 km/hr …………….(2)
(1)+(2 ) we get 2a = 32
a = 16 km/hr
speed downstream =distance traveled / time taken
time taken = 80/16 = 5 hours
Question 16 of 25
16. Question
1 points
A boat takes 4 hours for traveling downstream from point P to point Q and coming back to point P upstream. If the velocity of the stream is 2 km ph and the speed of the boat in still water is 4 kmph, what is the distance between P and Q?
Correct
Speed of stream = ½ (a-b) km/hr
Speed of still water = ½ (a+b) km/hr
Explanation:
Time taken by boat to travel upstream and
downstream = 4 hours
Velocity of the stream, ½ (a-b) = 2km/hr
a-b = 4km/hr ……………….( 1)
velocity of the boat in still water = ½ (a+b) =
4km/hr
a+b = 8 km/hr ………………(2)
1 +2 we get a = 6 km/hr ,b = 2km/hr
let the distance between A and B be x km
x / 2 + x / 6 = 4
3x + x / 6 = 4 4x = 24 so,x = 6
distance between P and Q = 6km
Incorrect
Speed of stream = ½ (a-b) km/hr
Speed of still water = ½ (a+b) km/hr
Explanation:
Time taken by boat to travel upstream and
downstream = 4 hours
Velocity of the stream, ½ (a-b) = 2km/hr
a-b = 4km/hr ……………….( 1)
velocity of the boat in still water = ½ (a+b) =
4km/hr
a+b = 8 km/hr ………………(2)
1 +2 we get a = 6 km/hr ,b = 2km/hr
let the distance between A and B be x km
x / 2 + x / 6 = 4
3x + x / 6 = 4 4x = 24 so,x = 6
distance between P and Q = 6km
Question 17 of 25
17. Question
1 points
Speed of a boat in standing water is 9 kmph and the speed of the
stream is 1.5 kmph. A man rows to a place at a distance of 10.5 km and
comes back to the starting point. Find the total time taken by him.
Correct
i. speed = distance traveled / time taken
ii. speed of the stream = ½ (a-b) km/hr
iii. speed in still water = ½ (a+b) km/hr
Explanation:
Speed in still water= ½ (a+b) = 9km ph
= a+b = 18 …………….1
speed of the stream = ½ (a-b) = 1.5 kmph
= a-b = 3 kmph…………2
solving 1 and 2 gives a = 10.5km/hr ; b=7.5 kmphr
Total time taken by him = 105/10.5 + 105/7.5 = 24 hours
Incorrect
i. speed = distance traveled / time taken
ii. speed of the stream = ½ (a-b) km/hr
iii. speed in still water = ½ (a+b) km/hr
Explanation:
Speed in still water= ½ (a+b) = 9km ph
= a+b = 18 …………….1
speed of the stream = ½ (a-b) = 1.5 kmph
= a-b = 3 kmph…………2
solving 1 and 2 gives a = 10.5km/hr ; b=7.5 kmphr
Total time taken by him = 105/10.5 + 105/7.5 = 24 hours
Question 18 of 25
18. Question
1 points
A man rows to a place 48km distant and back in 14 hours. He finds that he can row 4km with the stream in the same time as 3km against the stream. Find the rate of the stream.
Correct
Speed of the stream = ½ (a-b) km / hr
Speed = distance traveled / time taken
Explanation:
Suppose he moves 4km downstream in x hours
Then, downstream a= 4 / x km/hr
Speed upstream b = 3/ x km/hr
48 / (4 /x) + 48 / (3/x) = 14
12x + 16x = 14
x = 1/2
a=8 km/hr ,b = 6 km/hr
rate of stream = ½ (8 – 6 )
= 1 km/hr
Incorrect
Speed of the stream = ½ (a-b) km / hr
Speed = distance traveled / time taken
Explanation:
Suppose he moves 4km downstream in x hours
Then, downstream a= 4 / x km/hr
Speed upstream b = 3/ x km/hr
48 / (4 /x) + 48 / (3/x) = 14
12x + 16x = 14
x = 1/2
a=8 km/hr ,b = 6 km/hr
rate of stream = ½ (8 – 6 )
= 1 km/hr
Question 19 of 25
19. Question
1 points
There is road besides a river. Two friends started from a place P, moved to a shopping
mall situated at another place Q and then returned to P again. One of them moves on a cycle at a speed of 12 km/hr, while the other sails on a boat at a speed of 10 km/hr. If the river flows at the speed of 4 km/hr, which of the two friends will return to place P?
Correct
The cyclist moves both ways at a speed of 12khr
so average speed fo the
cyclist – 12 km/hr
boat sailor moves downstream at 10+4 =
14km/hr and upstream 10-
4 = 6km/hr
Average speed of the boat sailor = 2 x 14 x 6 /14 +6 = 42/ 5 = 8.4km/hr
The average speed of cyclist is greater .so,cyclist
comes first and return to
place P.
Incorrect
The cyclist moves both ways at a speed of 12khr
so average speed fo the
cyclist – 12 km/hr
boat sailor moves downstream at 10+4 =
14km/hr and upstream 10-
4 = 6km/hr
Average speed of the boat sailor = 2 x 14 x 6 /14 +6 = 42/ 5 = 8.4km/hr
The average speed of cyclist is greater .so,cyclist
comes first and return to
place P.
Question 20 of 25
20. Question
1 points
A this usual rowing rate, Mohit can travel 12 miles downstream in a certain river in 6
hours less than it takes him to travel the same distance upstream. But if he could double
his usual rowing rate for his 24 miles round trip, the downstream 12 miles would then
take only one hour less than the upstream 12 miles. What is the speed of the current in
miles per hour?
Correct
Speed of the stream = ½ (a-b) km/hr
Explanation:
Let the speed in still water be x m/hr
Speed of stream be y m/hr
Then, speed upstream = x-y m/hr and
Speed downstream = x+y m/hr
12/x-y – 12 / x+y = 6 so,6 (x^2 – y^2) = 24 y
x^2 – y^2 = 4y
x^2 = y^2 + 4y…………..1
also
12/ 2x-y – 12/2x +y = 1 4x^2 – y^2 = 24y
x^2 = [24y + y^2] / 4 ……………….2
16y + 4y^2 = 24y + y2 [put X^2 value from 1]
3y^2 = 8 y so, y = 8/3
speed of the current = 8/3 m/hr = 2 (2/3) m/hr
Incorrect
Speed of the stream = ½ (a-b) km/hr
Explanation:
Let the speed in still water be x m/hr
Speed of stream be y m/hr
Then, speed upstream = x-y m/hr and
Speed downstream = x+y m/hr
12/x-y – 12 / x+y = 6 so,6 (x^2 – y^2) = 24 y
x^2 – y^2 = 4y
x^2 = y^2 + 4y…………..1
also
12/ 2x-y – 12/2x +y = 1 4x^2 – y^2 = 24y
x^2 = [24y + y^2] / 4 ……………….2
16y + 4y^2 = 24y + y2 [put X^2 value from 1]
3y^2 = 8 y so, y = 8/3
speed of the current = 8/3 m/hr = 2 (2/3) m/hr
Question 21 of 25
21. Question
1 points
A boat takes 28 hours for travelling downstream from point A to point B and
coming back to point C midway between A and B. If the velocity of the stream is 6km/hr
and the speed of the boat in still water is 9 km/hr, what is the distance between A and B?
Correct
Downstream speed = 9+6 = 15
Upstream speed = 9-6 = 3
Now total time is 28 hours
If distance between A and B is d, then distance
BC = d/2
Now distance/speed = time, so
d/15 + (d/2)/3= 28
Solve, d = 120 km
Incorrect
Downstream speed = 9+6 = 15
Upstream speed = 9-6 = 3
Now total time is 28 hours
If distance between A and B is d, then distance
BC = d/2
Now distance/speed = time, so
d/15 + (d/2)/3= 28
Solve, d = 120 km
Question 22 of 25
22. Question
1 points
Speed of a man in still water is 5 km/hr and the river is running at 3km/hr. The total
time taken to go to a place and come back is 10 hours. What is the distance travelled?
Correct
Down speed= 5+3= 8
Up speed= 5-3=2
Let distance travelled = X
(X/8)+(X/2)= 10
X= 16 km
Total distance is 16+16=32
Incorrect
Down speed= 5+3= 8
Up speed= 5-3=2
Let distance travelled = X
(X/8)+(X/2)= 10
X= 16 km
Total distance is 16+16=32
Question 23 of 25
23. Question
1 points
A boat running upstream takes 9 hours 48 minutes to cover a certain distance, while it
takes 7 hours to cover the same distance running downstream. What is the ratio
between the speed of the boat and speed of the water current respectively?
Correct
Distance covered upstream in 9hrs 48 min =
Distance covered downstream in 7hrs
(X-Y) 49/5=(X+Y)7
X/y=1/6
Incorrect
Distance covered upstream in 9hrs 48 min =
Distance covered downstream in 7hrs
(X-Y) 49/5=(X+Y)7
X/y=1/6
Question 24 of 25
24. Question
1 points
A boat can travel 20 km downstream in 24 min. The ratio of the speed of the boat in still water to the speed of the stream is 4 : 1. How much time will the boat take to cover 15 km upstream?
Correct
Down speed =20/24*60=50km/hr
4:1 =4x:x
Downstream speed = 4x+x=5x
Upstream speed = 4x-x=3x
5x= 50; x=10
so up speed 3*10=30
Time = 15/30*60= 30min.
Incorrect
Down speed =20/24*60=50km/hr
4:1 =4x:x
Downstream speed = 4x+x=5x
Upstream speed = 4x-x=3x
5x= 50; x=10
so up speed 3*10=30
Time = 15/30*60= 30min.
Question 25 of 25
25. Question
1 points
A boat whose speed in 20 km/hr in still water goes 40 km downstream and comes
back in a total of 5 hours. The approx. speed of the stream (in km/hr) is:
Correct
Let the speed of the stream be x km/hr. Then,
Speed downstream = (20 + x) km/hr,
Speed upstream = (20 – x) km/hr.
40/20+x + 40/20-x = 5
X = 9 approx
Incorrect
Let the speed of the stream be x km/hr. Then,
Speed downstream = (20 + x) km/hr,
Speed upstream = (20 – x) km/hr.
40/20+x + 40/20-x = 5
X = 9 approx