Online exam in Boat and Stream For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT
Boat and Stream-Test 1
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Subject :- Quantitative Aptitude
Chapter :- Boat and Stream-Test 1
Questions :- 25
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Ram goes downstream with a boat to some destination and returns upstream to his
original places in 6 hours. If the speed of the boat in still water and the stream are
12km/hr and 5 km/hr respectively, then find the distance of the destination form the
starting position.
Correct
T = 2xD/(x^2 – y^2)
=> D = 119*6/2*12 = 29.75km
Incorrect
T = 2xD/(x^2 – y^2)
=> D = 119*6/2*12 = 29.75km
Question 2 of 25
2. Question
1 points
A boat travels downstream for 14km and upstream for 9km. If the boat took total
of 5 hours for its journey. What is the speed of the river flow if the speed of the
boat in still water is 5km/hr?
Correct
Let the speed of the stream be x km/hr.
Upward speed = (5 – x)km/hr.
Downward speed = (5 + x)km/hr.
14/(5+x) + 9/(5-x) = 5
=> x = 2km/hr.
Incorrect
Let the speed of the stream be x km/hr.
Upward speed = (5 – x)km/hr.
Downward speed = (5 + x)km/hr.
14/(5+x) + 9/(5-x) = 5
=> x = 2km/hr.
Question 3 of 25
3. Question
1 points
When a person is moving in the direction perpendicular to the direction of the current
is 20km/hr , speed of the current is 5km/hr. Then find the speed of the person against
the current?
Correct
Speed of the person = 20 – 5 = 15km/hr
Speed of the person against the current =
15 – 5 = 10km/hr.
Incorrect
Speed of the person = 20 – 5 = 15km/hr
Speed of the person against the current =
15 – 5 = 10km/hr.
Question 4 of 25
4. Question
1 points
A boat goes 6 km an hour in still water, it takes thrice as much time in going the same
distance against the current comparison to the direction of the current. Find the speed
of the current.
Correct
Let the speed of the stream be x km/hr
speed of the still water = 6 km/hr
Downstream speed = (6+x) km/hr
Upstream speed = (6-x)km/hr
Now,
3[D/(6+x)] = D/(6-x)
=> x = 3 km/hr
Incorrect
Let the speed of the stream be x km/hr
speed of the still water = 6 km/hr
Downstream speed = (6+x) km/hr
Upstream speed = (6-x)km/hr
Now,
3[D/(6+x)] = D/(6-x)
=> x = 3 km/hr
Question 5 of 25
5. Question
1 points
There are two places A and B which are separated by a distance of 100 k. Two boats
starts form both the places at the same time towards each other. If one boat is going
downstream then the other one is going upstream, if the speed of A and B is 12 km/hr. and 13 km/hr. respectively. Find at how much time will they meet each other.
Correct
Downstream = (12+x)km/hr
Upstream = (13-x)km/hr
Time = Distance / Relative speed
Relative speed = 12 + x + 13 – x = 25 km/hr
Time = 100/25 = 4 hours
Incorrect
Downstream = (12+x)km/hr
Upstream = (13-x)km/hr
Time = Distance / Relative speed
Relative speed = 12 + x + 13 – x = 25 km/hr
Time = 100/25 = 4 hours
Question 6 of 25
6. Question
1 points
A girl was travelling in a boat, suddenly wind starts blowing and blows her hat and
started floating back downstream. The boat continued to travel upstream for 12 more
minutes before she realized that her hat had fallen off. She turned back downstream and
she caught her hat as soon as she reached the starting point. If her hat flew off exactly
2 km from where she started. What is the speed of the water?
A ship sails 30km of a river towards upstream in 6 hours. How long will it take to cover the same distance downstream. If the speed of the current is (1/4)rd of the speed of the boat in still water.
Correct
Let x be speed of the boat and y be the speed of the current.
Downstream speed = x + y
Upstream speed = x – y
x –y = 30/6 = 5 km/hr.
Now,
x = 4y
x – y = 4y – y = 3y
=> x = (20/3)km/hr and y = (5/3)km/hr
Therefore, x + y = (25/3) km/hr.
Time during downstream = 90/25 =3.6 hrs.
Incorrect
Let x be speed of the boat and y be the speed of the current.
Downstream speed = x + y
Upstream speed = x – y
x –y = 30/6 = 5 km/hr.
Now,
x = 4y
x – y = 4y – y = 3y
=> x = (20/3)km/hr and y = (5/3)km/hr
Therefore, x + y = (25/3) km/hr.
Time during downstream = 90/25 =3.6 hrs.
Question 8 of 25
8. Question
1 points
A man can row 6 km/hr in still water. If the speed of the current is 2 km/hr, it takes 4
hours more in upstream than in the downstream for the same distance. Find the
distance.
Correct
Let the distance be D.
Downstream speed = 8 km/hr
Upstream speed = 4km/hr
From the question,
Upstream = Downstream + 4
D/4 = D/8 + 4
D/4 = (D + 32)/8
D = 32 km
Incorrect
Let the distance be D.
Downstream speed = 8 km/hr
Upstream speed = 4km/hr
From the question,
Upstream = Downstream + 4
D/4 = D/8 + 4
D/4 = (D + 32)/8
D = 32 km
Question 9 of 25
9. Question
1 points
The speed of the motor boat is that of the current of water is 36:5 . The boat goes along with the current in 5 hours 10 minutes . How much time it will take to come back .
In a fixed time, a boy swims double the distance along the current that he swims
against the current. If the speed of the current is 3km/hr. , then what is the speed
of the boy in still water ?
Correct
Let the speed of boy in still water be x
km/hr
and the speed of current is given = 3 km/hr
Downstream speed = (x+3) km/hr
Upstream speed = (x-3) km/hr
Let time be t hours
(x+3)*t = 2 {(x-3)*t}
=> x = 9 km/hr
Incorrect
Let the speed of boy in still water be x
km/hr
and the speed of current is given = 3 km/hr
Downstream speed = (x+3) km/hr
Upstream speed = (x-3) km/hr
Let time be t hours
(x+3)*t = 2 {(x-3)*t}
=> x = 9 km/hr
Question 11 of 25
11. Question
1 points
A man can row 40 kmph in still water and the river is running at 10 kmph. If the man
takes 2 hr to row to a place and back, how far is the place?
Correct
Given u=40 , v=10
D= t[(u2-v2)/2u]
=2*[(402-102)/2*40]
=2*(1600-100)/80
2*1500/80==>37.5km
Incorrect
Given u=40 , v=10
D= t[(u2-v2)/2u]
=2*[(402-102)/2*40]
=2*(1600-100)/80
2*1500/80==>37.5km
Question 12 of 25
12. Question
1 points
A man rows to a place 60 km distant and come back in 35 hours. He finds that he can
row 4 km with the stream in the same time as 3 km against the stream. Find the speed
in still water and in stream:
Correct
If he moves 4 km downstream in x hours.
Downstream speed=4/x
Upstream speed=3/x
Then 60/(4/x) + 60/(3/x)=35
60[(3x+4x)/12]=35
60*7x/12=35
5*7x=35==> x=1km.
Then Downstream speed=4km/hr ,
Upstream speed=3km/hr
U=(4+3)/2=7/2=3.5km/hr
V=(4-3)/2=1/2=0.5km/hr
Incorrect
If he moves 4 km downstream in x hours.
Downstream speed=4/x
Upstream speed=3/x
Then 60/(4/x) + 60/(3/x)=35
60[(3x+4x)/12]=35
60*7x/12=35
5*7x=35==> x=1km.
Then Downstream speed=4km/hr ,
Upstream speed=3km/hr
U=(4+3)/2=7/2=3.5km/hr
V=(4-3)/2=1/2=0.5km/hr
Question 13 of 25
13. Question
1 points
Speed of a boat in standing water is 12 kmph and the speed of the stream is 3 kmph. A man rows to a place at a distance of 6300 km and comes back to the starting point. The total time taken by him is:
Correct
Downstream speed = (12 + 3) = 15 km/hr
Upstream speed = (12 – 3) = 9 km/hr
Total time taken =6300/15+6300/9
=420+700==>1120hrs.
Incorrect
Downstream speed = (12 + 3) = 15 km/hr
Upstream speed = (12 – 3) = 9 km/hr
Total time taken =6300/15+6300/9
=420+700==>1120hrs.
Question 14 of 25
14. Question
1 points
A boat takes 26 hours for travelling downstream from point A to point B and
coming back to point C midway between A and B. If the velocity of the stream is 4
km/hr and the speed of the boat in still water is 10 km/hr, what is the distance
between A and B?
Correct
Downstream speed = 10+4 = 14
Upstream speed = 10-4 = 6
Now total time is 26 hours
If distance between A and B is d, then
distance BC = d/2
Now distance/speed = time, so
d/14 + (d/2)/6= 26
13d/84=26
Solve, d = 168 km
Incorrect
Downstream speed = 10+4 = 14
Upstream speed = 10-4 = 6
Now total time is 26 hours
If distance between A and B is d, then
distance BC = d/2
Now distance/speed = time, so
d/14 + (d/2)/6= 26
13d/84=26
Solve, d = 168 km
Question 15 of 25
15. Question
1 points
At his usual rowing rate, Rahul can travel 12 miles downstream in a certain river in 6
hours less than it takes him to travel the same distance upstream. But if he could
double his usual rowing rate for his 24-mile round trip, the downstream 12 miles would
then take only one hour less than the upstream 12 miles. What is the speed of the
current in miles per hour?
Correct
Let the speed of Rahul in still water be x mph
and the speed of the current be y mph
Then, Speed upstream = (x – y) mph
Speed downstream = (x + y) mph
Distance = 12 miles
Time taken to travel upstream – Time taken
to travel downstream = 6 hours
12/(x-y) – 12/(x+y)=6
x2=y2+4y—1
Now he doubles his speed. i.e., his new
speed = 2x
Now, Speed upstream = (2x – y) mph
Speed downstream = (2x + y) mph
In this case, Time taken to travel upstream
– Time taken to travel downstream = 1 hour
12/(2x-y) – 12/(2x+y) = 1
4×2=y2+24y—2
From 1 and 2 we get
4y+y2=(24y +y2)/4
Y=8/3==> 2 2/3 mph
Incorrect
Let the speed of Rahul in still water be x mph
and the speed of the current be y mph
Then, Speed upstream = (x – y) mph
Speed downstream = (x + y) mph
Distance = 12 miles
Time taken to travel upstream – Time taken
to travel downstream = 6 hours
12/(x-y) – 12/(x+y)=6
x2=y2+4y—1
Now he doubles his speed. i.e., his new
speed = 2x
Now, Speed upstream = (2x – y) mph
Speed downstream = (2x + y) mph
In this case, Time taken to travel upstream
– Time taken to travel downstream = 1 hour
12/(2x-y) – 12/(2x+y) = 1
4×2=y2+24y—2
From 1 and 2 we get
4y+y2=(24y +y2)/4
Y=8/3==> 2 2/3 mph
Question 16 of 25
16. Question
1 points
There is a road beside a river. Two friends started from a place A, moved to a temple
situated at another place B and then returned to A again. One of them moves on
a cycle at a speed of 6 km/hr, While the other sails on a boat at a speed of 8 km/hr.
If the river flows at the speed of 6 km/hr, which of the two friends will return to
place A first?
Correct
Average speed of the cyclist =6 km/hr
Downstream speed=8+6=14 km/hr
Upstream speed =8−6=2 km/hr
Therefore, average speed of the sailor
=2*14*2/(14+2)
=3.5km/hr
Average speed of the cyclist is more than
that of the sailor. Therefore, the cyclist will
return first.
Incorrect
Average speed of the cyclist =6 km/hr
Downstream speed=8+6=14 km/hr
Upstream speed =8−6=2 km/hr
Therefore, average speed of the sailor
=2*14*2/(14+2)
=3.5km/hr
Average speed of the cyclist is more than
that of the sailor. Therefore, the cyclist will
return first.
Question 17 of 25
17. Question
1 points
A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it
takes 4 hours to cover the same distance running downstream. What is the ratio
between the speed of the boat and speed of the water current respectively?
Correct
Let the man’s rate upstream be x kmph and
that downstream be y kmph.
Then, distance covered upstream in 8 hrs
48 min = Distance covered downstream in
4 hrs.
X*8 4/5 =4y
44/5x=4y
Y=11/5x.
Required ratio (y+x)/2=(y-x)/2
16x/10:6x/10
8:3
Incorrect
Let the man’s rate upstream be x kmph and
that downstream be y kmph.
Then, distance covered upstream in 8 hrs
48 min = Distance covered downstream in
4 hrs.
X*8 4/5 =4y
44/5x=4y
Y=11/5x.
Required ratio (y+x)/2=(y-x)/2
16x/10:6x/10
8:3
Question 18 of 25
18. Question
1 points
A man takes thrice as long to row a distance against the stream as to row the
same distance in favour of the stream. The ratio of the speed of the boat (in still water)
and the stream is:
Correct
Lets upstream be xkm/hr
Downstream be 3x km/hr
U: V=(3x+x)/2: (3x-x)/2
4x/2:2x/2
2:1
Incorrect
Lets upstream be xkm/hr
Downstream be 3x km/hr
U: V=(3x+x)/2: (3x-x)/2
4x/2:2x/2
2:1
Question 19 of 25
19. Question
1 points
A boat running downstream covers a distance of 40 km in 4 hrs and covering the
same distance upstream in 8 hrs. What is the speed of a boat in still water.
Correct
Downstream speed=40/4=10km/hr
Upstream speed=40/8=5km/hr
So speed of boat in still
water=(10+5)/2=15/2
=7.5km/hr
Incorrect
Downstream speed=40/4=10km/hr
Upstream speed=40/8=5km/hr
So speed of boat in still
water=(10+5)/2=15/2
=7.5km/hr
Question 20 of 25
20. Question
1 points
A boat can travel 3.5 km upstream in 14 min. If the ratio of the speed of the boat
in still water to the speed of the stream is 7:2. How much time will the boat take to
cover 36 km downstream ?
5x = 15
x = 3
Downstream = 9*3 = 27
Time taken for 36km = 36*60/27 = 80min
Question 21 of 25
21. Question
1 points
Vimal can row a certain distance downstream in 14 hours and return the same
distance in 21 hours. If the speed of the stream is 6 kmph, Find the speed of Vimal
in the still water?
Correct
Speed of Vimal in still water = x
Downstream Speed = (x + 6)
Upstream Speed = (x – 6)
Downstream Distance = Upstream Distance
14(x + 6) = 21(x – 6)
2x + 12 = 3x – 18
x = 30 kmph.
Incorrect
Speed of Vimal in still water = x
Downstream Speed = (x + 6)
Upstream Speed = (x – 6)
Downstream Distance = Upstream Distance
14(x + 6) = 21(x – 6)
2x + 12 = 3x – 18
x = 30 kmph.
Question 22 of 25
22. Question
1 points
Rahul can row a certain distance downstream in 12 hour and return the same distance in 18 hour. If the speed of Rahul in still water is 12 kmph, find the speed of the stream?
Correct
Let the speed of the stream be x kmph
Down stream = (12+x)
Up stream = (12−x)
suppose the distance traveled be y
y/(12+x) = 12 —(1)
y/(12−x)= 18 —-(2)
From eqn (1) and (2)
x= 2.4 kmph
Incorrect
Let the speed of the stream be x kmph
Down stream = (12+x)
Up stream = (12−x)
suppose the distance traveled be y
y/(12+x) = 12 —(1)
y/(12−x)= 18 —-(2)
From eqn (1) and (2)
x= 2.4 kmph
Question 23 of 25
23. Question
1 points
Anil can row 18 kmph in still water and he finds that it takes him twice as long to row
up as to row down the river. Find the rate of stream?
Correct
Stream Speed = a kmph
Time Taken = x km
Downstream speed = (18 + a) kmph
Upstream speed = (18 – a) kmph
Time taken to travel downstream = 2 *
Time taken to travel upstream
(18 + a) / x = 2(18 + a) / x
18 + a = 36 – 2a
3a = 18
a = 6 kmph
OR USE FORMULA
Speed of boat = [tu+td]/[tu-td] * Speed of stream
So 18 = [2x + x]/[2x – x] * Speed of stream
Incorrect
Stream Speed = a kmph
Time Taken = x km
Downstream speed = (18 + a) kmph
Upstream speed = (18 – a) kmph
Time taken to travel downstream = 2 *
Time taken to travel upstream
(18 + a) / x = 2(18 + a) / x
18 + a = 36 – 2a
3a = 18
a = 6 kmph
OR USE FORMULA
Speed of boat = [tu+td]/[tu-td] * Speed of stream
So 18 = [2x + x]/[2x – x] * Speed of stream
Question 24 of 25
24. Question
1 points
Mr. Suresh can row to a place 48 km away and come back in 14 hours. He finds that
he can row 4 km with the stream in the same time as 3 km against the stream. The
rate of the stream is?
Correct
Downstream speed = 4/x kmph
upstream speed = 3/x kmph
48/(4/x) + 48/(3/x) = 14
Solving we get x = 1/2 kmph
So, Speed of downstream = 8 kmph, Speed
of upstream = 6 kmph
Stream Speed = 1/2(8 – 6) kmph = 1 kmph
Incorrect
Downstream speed = 4/x kmph
upstream speed = 3/x kmph
48/(4/x) + 48/(3/x) = 14
Solving we get x = 1/2 kmph
So, Speed of downstream = 8 kmph, Speed
of upstream = 6 kmph
Stream Speed = 1/2(8 – 6) kmph = 1 kmph
Question 25 of 25
25. Question
1 points
Mr.Ramesh’s speed with the current is 20 kmph and the speed of the current is 5
kmph. Ramesh’s speed against the current is?
Correct
Ramesh’s speed with the current = 20 kmph
=> Ramesh’s speed + speed of the current
= 20 kmph
Speed of the current = 5 kmph
Speed of Ramesh = 20 – 5 = 15 kmph
Ramesh’s speed against the current = speed
of Ramesh – speed of the current = 15 – 5= 10 kmph
Incorrect
Ramesh’s speed with the current = 20 kmph
=> Ramesh’s speed + speed of the current
= 20 kmph
Speed of the current = 5 kmph
Speed of Ramesh = 20 – 5 = 15 kmph
Ramesh’s speed against the current = speed
of Ramesh – speed of the current = 15 – 5= 10 kmph
