Online exam in Average For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT
Average-Test 6
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Subject :- Quantitative Aptitude
Chapter :- Averages- Test 6
Questions :- 25
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the average marks in science subject of a class of students is 68.if the marks of two students were 48 and 65 of the actual marks 72 and 61 respectively,then what would be the correct average?
Correct
here,sum of added quantity-sum of removed quantity=-n.X
(72+61)-(48+65)=20.X
133-113=20.X
X=20/20=1
so,actual average=68+1=69
Incorrect
here,sum of added quantity-sum of removed quantity=-n.X
(72+61)-(48+65)=20.X
133-113=20.X
X=20/20=1
so,actual average=68+1=69
Question 2 of 30
2. Question
1 points
The average weight of a group of 75 girls was calculated as 47 KG. it was late discovered that, the weight of one of the girls was read as 45 kg, whereas her actual weight was 25 kg. what is the actual average weight of the group of 75 girls? ( rounded off to two digits after decimal )
Correct
Here, sum of added quantity-sum of removed quantity= -N.X
25-45=-75.X
X=20/75=0.26
therefore, new average=47-0.26=46.73 KG
Incorrect
Here, sum of added quantity-sum of removed quantity= -N.X
25-45=-75.X
X=20/75=0.26
therefore, new average=47-0.26=46.73 KG
Question 3 of 30
3. Question
1 points
The average height of 13 girls in a class is 144×8/13 cm.The average height of 11 boy in the class is 169×5/11 cm.There are only 24 students in the class .what is the overall average height (in cm ) of all the students together in the class?
Correct
Here,sum of the total height of 13 girls in the class=13×1880/13=1880 cm
sum of the total height of 11 boys i the class=11×1864/11=1864 cm
therefore,overall average height =1180+1864/24=156 cm
Incorrect
Here,sum of the total height of 13 girls in the class=13×1880/13=1880 cm
sum of the total height of 11 boys i the class=11×1864/11=1864 cm
therefore,overall average height =1180+1864/24=156 cm
Question 4 of 30
4. Question
1 points
average score of rahul, mansih and suresh is 63. rahul’s score is 15 less than ajay and 10 more than mansih. if ajay scored 30 marks more than the average score of rahul, mansih and suresh, than what is the sum of mansih’s and suresh’s scores?
Correct
here, total score of rahul, mansih and suresh= 3X63=189
ajay’s score = 63+30 =93
rahul’s score = 78
mansih’s score = 68
so, sum of mansih and suresh score = 68+43 = 111
Incorrect
here, total score of rahul, mansih and suresh= 3X63=189
ajay’s score = 63+30 =93
rahul’s score = 78
mansih’s score = 68
so, sum of mansih and suresh score = 68+43 = 111
Question 5 of 30
5. Question
1 points
The average age of 80 boys in a class is 15 Yr. the average age of a group of 15 boys in the class is 16 Yr. and the average age of another 25 boys in the class is 14 Yr. what is the average age of the remaining boys in the class?
Correct
let the required average age of the remaining boys be X
now, according to the question,
80×15 = 15×16 + 25×14 + 40xX
1200 = 240 + 350 + 40X
40X = 1200-240-350
40X = 610
X = 610/40 = 15.25 Yr
Incorrect
let the required average age of the remaining boys be X
now, according to the question,
80×15 = 15×16 + 25×14 + 40xX
1200 = 240 + 350 + 40X
40X = 1200-240-350
40X = 610
X = 610/40 = 15.25 Yr
Question 6 of 30
6. Question
1 points
The average of 5 numbers is 56. if the average of 1st four numbers is 54, what is the value of the 5th number?
Correct
here,total sum of 5 numbers=56×5=280
sum of 1st four numbers = 4×54 = 216
therefore, value of 5th number=280-216=64
Incorrect
here,total sum of 5 numbers=56×5=280
sum of 1st four numbers = 4×54 = 216
therefore, value of 5th number=280-216=64
Question 7 of 30
7. Question
1 points
The average of 5 numbers is 65. the average of 1st two numbers is 81 and the average of the last two numbers is 38. what is the 3rd number?
Correct
here, total sum of 5 numbers = 5×65=325
sum of 1st two numbers = 2×81=162
sum of last two numbers = 2×38=76
so, 3rd number = 325-(162+76)=325-238=87
Incorrect
here, total sum of 5 numbers = 5×65=325
sum of 1st two numbers = 2×81=162
sum of last two numbers = 2×38=76
so, 3rd number = 325-(162+76)=325-238=87
Question 8 of 30
8. Question
1 points
The sum of 5 numbers is 290. the average of 1st two numbers is 48.5 and the average of last two numbers is 53.5. what is the 3rd number?
Correct
Here, sum of 5 numbers = 290
sum of 1st two numbers = 2×48.5=97
sum of last two numbers = 2×53.5=107
therefore, 3rd number = 290-(97+107)=86
Incorrect
Here, sum of 5 numbers = 290
sum of 1st two numbers = 2×48.5=97
sum of last two numbers = 2×53.5=107
therefore, 3rd number = 290-(97+107)=86
Question 9 of 30
9. Question
1 points
The sum of 5 numbers is 306.4. the average of 1st two numbers is 431 and the average of last two numbers is 214.5. what is the 3rd number?
Correct
Here, sum of 5 numbers = 5×306.4 = 1532
sum of 1st two numbers = 2×431 = 862
sum of last two numbers = 2×214.5 = 429
therefore, 3rd number = 1532-(862+429)=241
Incorrect
Here, sum of 5 numbers = 5×306.4 = 1532
sum of 1st two numbers = 2×431 = 862
sum of last two numbers = 2×214.5 = 429
therefore, 3rd number = 1532-(862+429)=241
Question 10 of 30
10. Question
1 points
kamlesh bought 65 books for Rs 1050 from one shop and 50 books for Rs 1020 from another. what is the average price, he paid per book?
The average of the age of sumit, krishna and rishabh is 43 Yr and the average of the ages of sumit, rishabh and rohit is 49 Yr. if rohit is 54 Yr old, then what is krishna’s age?
Correct
here, total ages of sumit, krishna and rishabh = 3×43 = 129
total ages of sumit, rishabh and rohit = 3×49 = 147
now, rohit’s age = 54 Yr
then, sumit and rishabh’s age = 147-54 = 93 Yr
krishna’s age = 129-93 Yr = 36 Yr
Incorrect
here, total ages of sumit, krishna and rishabh = 3×43 = 129
total ages of sumit, rishabh and rohit = 3×49 = 147
now, rohit’s age = 54 Yr
then, sumit and rishabh’s age = 147-54 = 93 Yr
krishna’s age = 129-93 Yr = 36 Yr
Question 12 of 30
12. Question
1 points
The average of 7 boys sitting in a row facing north is 26 Yr. if the average age of 1st 3 boys is 19 Yr and the average age of last 3 boys is 32 Yr, then what is the age of the boy who is sitting in the middle of the row?
Correct
here, age of the 4th boy = (26×7-3×19-3×32) Yr = 182-57-96 = 29 Yr
Incorrect
here, age of the 4th boy = (26×7-3×19-3×32) Yr = 182-57-96 = 29 Yr
Question 13 of 30
13. Question
1 points
3 years ago, the average age of A and B was 18 Yr. when C join them, the average becomes 22 Yr how old is C now ( in yrs )?
Correct
here, total present ages of A and B = 18×2+6=42 Yr
now, total ages of A B and C = 3×22=66 Yr
therefore, C’s age = 66-42=24 Yr
Incorrect
here, total present ages of A and B = 18×2+6=42 Yr
now, total ages of A B and C = 3×22=66 Yr
therefore, C’s age = 66-42=24 Yr
Question 14 of 30
14. Question
1 points
Average weight of 3 boys P, T and R is 54×1/3 kg, while the average weight of 3 boys T, F and G is 53 kg. what is the average weight of P, T, R, F and H?
Correct
here, average weight of P, T and R = 54×1/3 kg
total weight of P, T and R = 3×163/3 = 163 kg
again, total weight of T, F and G = 3×53=159 kg
further, it cant be solved, so data is inadequate
Incorrect
here, average weight of P, T and R = 54×1/3 kg
total weight of P, T and R = 3×163/3 = 163 kg
again, total weight of T, F and G = 3×53=159 kg
further, it cant be solved, so data is inadequate
Question 15 of 30
15. Question
1 points
Of the 3 numbers, the average of the 1st and the 2nd is grater than the average of 2nd and 3rd by 15.what is the difference between the 1st and the 3rd of the 3 numbers?
Correct
here, let 3 numbers be x,y and z
x+y/2-y+z/2 = 15
x+y-y-z = 30
x-z = 30
Incorrect
here, let 3 numbers be x,y and z
x+y/2-y+z/2 = 15
x+y-y-z = 30
x-z = 30
Question 16 of 30
16. Question
1 points
The average of marks obtained in 120 students was 35. if average of passed candidates was 39 and that of failed candidates is 15, the numbers of candidates who passed the examination is
Correct
here, total marks obtained by 120 students = 120×35 = 4200
let the number of passed candidates = X
then, total marks obtained by passed candidates = X x 39
and, total marks obtained by failed candidates = (120-X)x15
again, 39 X + (120-X)x15 = 4200
39X + 1800-15X = 4200
X = 2400/24=100
Incorrect
here, total marks obtained by 120 students = 120×35 = 4200
let the number of passed candidates = X
then, total marks obtained by passed candidates = X x 39
and, total marks obtained by failed candidates = (120-X)x15
again, 39 X + (120-X)x15 = 4200
39X + 1800-15X = 4200
X = 2400/24=100
Question 17 of 30
17. Question
1 points
A team of 8 persons joins a shooting competition.The best marksmen scored 85 points.if he had scored 92 points,then the average score for the team would have been 84.the number of points the team scored was
Correct
Here,the no of points team scored=8×84-92+85 = 672-92+85 = 665
Incorrect
Here,the no of points team scored=8×84-92+85 = 672-92+85 = 665
Question 18 of 30
18. Question
1 points
What fraction must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the three fractions?
The average age of the family of 5 members is 24.if the present age of youngest member is 8 yr,hen what was the average age of the family at the time of the birth of the youngest member?
Correct
Here,total age of 5 members = 5×24=120 yr
8 yr ago,total age of the family =120-40= 80yr
therefore,average=80/4=20yr
Incorrect
Here,total age of 5 members = 5×24=120 yr
8 yr ago,total age of the family =120-40= 80yr
therefore,average=80/4=20yr
Question 20 of 30
20. Question
1 points
Find the average age of 12.5,11.6,13.2,15.6 and 9.8
Correct
Incorrect
Question 21 of 30
21. Question
1 points
What will be the average of even numbers between 11 to 63?
Correct
Incorrect
Question 22 of 30
22. Question
1 points
if the algebraic sum of deviations of 20 observations measured from 23 is 70,then mean of these observations would be
Correct
Incorrect
Question 23 of 30
23. Question
1 points
8 consecutive numbers are given.if the average of two numbers that appear in the middle is 6,then the sum of 8 given numbers is
Correct
Incorrect
Question 24 of 30
24. Question
1 points
Calculate the average of the cubes of first five natural numbers.
Correct
Incorrect
Question 25 of 30
25. Question
1 points
The average cost of 5 books and 4 pens is Rs 36.The average cost of 7 books and 8 pens is Rs 48.Find out the cost of 12 books and 12 pens together.
Correct
Incorrect
Question 26 of 30
26. Question
1 points
if 2 students of weight 51.5 kg and 50 kg are joined,then the average becomes 54 kg in a class.Find the number of students in the beginning.
Correct
Incorrect
Question 27 of 30
27. Question
1 points
The average of 30 observations is 45.if 3 new observation 42,44 and 48 be added,then find the new average.
Correct
Incorrect
Question 28 of 30
28. Question
1 points
The average age of a class of 45 girls is 16 yr.The average age of 15 of them was 12 yr and another 10 was 14 yr.Find the average age of the remaining girls.
Correct
Incorrect
Question 29 of 30
29. Question
1 points
Sum of three consecutive even numbers is 68 more than the average of the numbers.Find the middle number.
Correct
Incorrect
Question 30 of 30
30. Question
1 points
The average of 100 numbers is 50.it is found that,while calculating the average,2 numbers namely 71 and 65 were wrongly read as 17 and 56. the correct average is
