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Ages-Test 4

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Ages-Test 4

Subject :- Quantitative Aptitude

Chapter :- Ages- Test 4

Questions :- 25

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Question 1 of 25

1. Question
1 points
Ratio of ages of Reena and Prerna is 2 : 3 and the ratio of ages of Tiya and Reena is 3: 1. If the ratio of age of Prerna four years hence to age of Tiya three years hence is 5 :9, what is the total of the ages of all three?
- 75
- 77
- 87
- 78
Correct

P/R = 3/2 and R/T = 1/3
So P : R : T =
3*1 : 2*1 : 2*3 = 3 : 2 : 6
Now (3x+4)/(6x+3) = 5/9

So x = 7
P = 3x = 21, R = 2x = 14, T = 6x = 42
So P + R + T = 77

Incorrect

P/R = 3/2 and R/T = 1/3
So P : R : T =
3*1 : 2*1 : 2*3 = 3 : 2 : 6
Now (3x+4)/(6x+3) = 5/9

So x = 7
P = 3x = 21, R = 2x = 14, T = 6x = 42
So P + R + T = 77
Question 2 of 25

2. Question
1 points
Richa‘s age is thrice of Tisha‘s age while Megha‘s age is 3 less than that of Richa‘s.
The ratio of ages of Tisha‘s three years hence to Megha‘s four years ago is 3 : 5. What
is the square root of the total age of Tisha and Richa?
- 6
- 8
- 13
- 16
Correct

Tisha = x, Richa = 3x, Megha = 3x – 3
(x+3)/(3x-3-4) = 3/5
Solve, x = 9
So total age of Tisha + Richa = x + 3x = 4x = 36, So square root = √36 = 6

Incorrect

Tisha = x, Richa = 3x, Megha = 3x – 3
(x+3)/(3x-3-4) = 3/5
Solve, x = 9
So total age of Tisha + Richa = x + 3x = 4x = 36, So square root = √36 = 6
Question 3 of 25

3. Question
1 points
The ratio of age of Shaisha one year ago to Piya is 3 : 5. The sum of ages of Piya and
Misha after four years will be 50. If difference between the ages of Shaisha and Misha
is 7 years, find Misha‘s age.
- 21
- 19
- 18
- 12
- 10
Correct

(S -1)/P = 3/5
P + M + 4 + 4 = 50
So P + M = 42
S – M = 7
Solve equations, M = 12

Incorrect

(S -1)/P = 3/5
P + M + 4 + 4 = 50
So P + M = 42
S – M = 7
Solve equations, M = 12
Question 4 of 25

4. Question
1 points
Kashish‘s age is two-fifth the age of her mother. Nine years hence her age will be half
of her mother‘s age that time. What is her mother‘s present age?
- 45
- 54
- 22
- 41
Correct

K = 2M/5
(K+9) = (M+9)/2
Solve, M = 45

Incorrect

K = 2M/5
(K+9) = (M+9)/2
Solve, M = 45
Question 5 of 25

5. Question
1 points
Ratio between Rahim‘s age four years hence and Meher‘s age three years ago is 6 : 5.
If the ratio between Rahim‘s age two years ago and Meher‘s age four years hence is 6 :
11, find the ratio of Rahim‘ age to Meher‘s age.
- 5 : 9
- 9 : 4
- 2 : 11
- 7 : 9
Correct

(R+4)/(M-3) = 6/5
(R-2)/(M+4) = 12/22 = 6/11
Solve R = 14, M = 18

Incorrect

(R+4)/(M-3) = 6/5
(R-2)/(M+4) = 12/22 = 6/11
Solve R = 14, M = 18
Question 6 of 25

6. Question
1 points
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?
- 2 Times
- 2 1/2 Times
- 2 3/4 Times
- 3 Times
Correct

Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.
$(4 x + 8) = \frac{5}{2} x + 8)$
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio =
$\frac{(4 x + 16)}{(x + 16)} = \frac{48}{24} = 2$

Incorrect

Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.
$(4 x + 8) = \frac{5}{2} x + 8)$
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio =
$\frac{(4 x + 16)}{(x + 16)} = \frac{48}{24} = 2$
Question 7 of 25

7. Question
1 points
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
- 4 years
- 8 years
- 10 years
- None of These
Correct

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years

Incorrect

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years
Question 8 of 25

8. Question
1 points
A father said to his son, “I was as old as you are at the present at the time of your birth”. If the father’s age is 38 years now, the son’s age five years back was:
- 14 years
- 19 years
- 33 years
- 38 years
Correct

Let the son’s present age be x years. Then, (38 – x) = x
2x = 38.
x = 19.
Son’s age 5 years back (19 – 5) = 14 years

Incorrect

Let the son’s present age be x years. Then, (38 – x) = x
2x = 38.
x = 19.
Son’s age 5 years back (19 – 5) = 14 years
Question 9 of 25

9. Question
1 points
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
- 7
- 8
- 9
- 10
Correct

Let C’s age be x years. Then, B’s age = 2x years. A’s age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B’s age = 2x = 10 years

Incorrect

Let C’s age be x years. Then, B’s age = 2x years. A’s age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B’s age = 2x = 10 years
Question 10 of 25

10. Question
1 points
Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand’s present age in years?
- 24
- 27
- 40
- None of these
Correct

Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then,5x + 3
=
4x + 3 9
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x – 44x = 33 – 27
x = 6.
Anand’s present age = 4x = 24 years.

Incorrect

Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then,5x + 3
=
4x + 3 9
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x – 44x = 33 – 27
x = 6.
Anand’s present age = 4x = 24 years.
Question 11 of 25

11. Question
1 points
A man is 24 years older than his son. In two years, his age will be twice the age of his son.The present age of his son is:
- 14 years
- 18 years
- 20 years
- 22 years
Correct

Let the son’s present age be x years. Then, man’s present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.

Incorrect

Let the son’s present age be x years. Then, man’s present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
Question 12 of 25

12. Question
1 points
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar’s age at present?
- 16 years
- 18 years
- 20 years
- None of these
Correct

Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then,(6x + 6) + 4
=
11
(5x + 6) + 4 10
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar’s present age = (5x + 6) = 16 years

Incorrect

Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then,(6x + 6) + 4
=
11
(5x + 6) + 4 10
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar’s present age = (5x + 6) = 16 years
Question 13 of 25

13. Question
1 points
The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be:
- 12 years
- 14 years
- 18 years
- 20 years
Correct

Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 – x) – 6 = 5(x – 6)
54 – x = 5x – 30
6x = 84
x = 14.
Son’s age after 6 years = (x+ 6) = 20 years

Incorrect

Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 – x) – 6 = 5(x – 6)
54 – x = 5x – 30
6x = 84
x = 14.
Son’s age after 6 years = (x+ 6) = 20 years
Question 14 of 25

14. Question
1 points
At present, the ratio between the ages of Arun and Deepak is 4 : 3. After 6 years, Arun’s age will be 26 years. What is the age of Deepak at present ?
- 12 years
- 15 years
- 19 years
- 21 years
Correct

Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,
4x + 6 = 26 4x = 20
x = 5.
Deepak’s age = 3x = 15 years

Incorrect

Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,
4x + 6 = 26 4x = 20
x = 5.
Deepak’s age = 3x = 15 years
Question 15 of 25

15. Question
1 points
Sachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7 : 9, how old is Sachin?
- 16 years
- 18 years
- 26 years
- 24.5 years
Correct

Let Rahul’s age be x years.
Then, Sachin’s age = (x – 7) years.
$\frac{x - 7}{x} = \frac{7}{9}$
9x – 63 = 7x
2x = 63
x = 31.5
Hence, Sachin’s age =(x – 7) = 24.5 years.

Incorrect

Let Rahul’s age be x years.
Then, Sachin’s age = (x – 7) years.
$\frac{x - 7}{x} = \frac{7}{9}$
9x – 63 = 7x
2x = 63
x = 31.5
Hence, Sachin’s age =(x – 7) = 24.5 years.
Question 16 of 25

16. Question
1 points
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
- 8, 20, 28
- 16, 28, 36
- 20, 35, 45
- None of these
Correct

Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
20x = 80
x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.

Incorrect

Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
20x = 80
x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Question 17 of 25

17. Question
1 points
Ayesha’s father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
- 2 years
- 4 years
- 6 years
- 8 years
Correct

Mother’s age when Ayesha’s brother was born = 36 years.
Father’s age when Ayesha’s brother was born = (38 + 4) years = 42 years.
Required difference = (42 – 36) years = 6 years

Incorrect

Mother’s age when Ayesha’s brother was born = 36 years.
Father’s age when Ayesha’s brother was born = (38 + 4) years = 42 years.
Required difference = (42 – 36) years = 6 years
Question 18 of 25

18. Question
1 points
A person’s present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?
- 32 years
- 36 years
- 40 years
- 48 years
Correct

Let the mother’s present age be x years.

Then, the person’s present age =
$(\frac{2}{5} x) Years$
Therefore
$(\frac{2}{5} x + 8) = \frac{1}{2} (x + 8)$
2(2x + 40) = 5(x + 8)
x = 40.

Incorrect

Let the mother’s present age be x years.

Then, the person’s present age =
$(\frac{2}{5} x) Years$
Therefore
$(\frac{2}{5} x + 8) = \frac{1}{2} (x + 8)$
2(2x + 40) = 5(x + 8)
x = 40.
Question 19 of 25

19. Question
1 points
Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50
years, what is definitely the difference between R and Q’s age?
- 1 year
- 2 year
- 25 year
- Data inadequate
Correct

R – Q = R- T Q = T.
Also, R + T = 50 R + Q = 50.
So, (R – Q) cannot be determined

Incorrect

R – Q = R- T Q = T.
Also, R + T = 50 R + Q = 50.
So, (R – Q) cannot be determined
Question 20 of 25

20. Question
1 points
The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age will be twice that of his son. The ratio of their present ages is:
- 5 : 2
- 7 : 3
- 9 : 2
- 13 : 4
Correct

Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3

Incorrect

Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3
Question 21 of 25

21. Question
1 points
The height of 5 boyis is recorded as, 146, cm, 154 cm,164 cm, 148 cm and 158 cm. What is the average height of all these boys?
- 152 cm
- 158 cm
- 156 cm
- 154 cm
- None of these
Correct

Average height =
$\frac{146 + 154 + 164 + 148 + 158}{5} = \frac{770}{5} = 154 cm$

Incorrect

Average height =
$\frac{146 + 154 + 164 + 148 + 158}{5} = \frac{770}{5} = 154 cm$
Question 22 of 25

22. Question
1 points
James’s father was 30 years old when he was born. His mother’s age was 24 when his sister who is 5 years younger to him, was born. What is the difference between the age of James’s father and Mother?
- 8
- 10
- 6
- 11
- 9
Correct

James’ age F-30

Sister’s age=F-35

M=24+Sister’s age

M=24+F-35

F-M=11

Incorrect

James’ age F-30

Sister’s age=F-35

M=24+Sister’s age

M=24+F-35

F-M=11
Question 23 of 25

23. Question
1 points
David’s present age is 2/7 th of his father’s present age. David’s brother is three year older to james.The respective ratio between present ages of David father and David’s brother is 14:5. What is the present age of David?
- 12 Years
- 23 Years
- 19 Years
- 27 Years
- 13 Years
Correct

Incorrect
Question 24 of 25

24. Question
1 points
Ronit’s age is 10 Years more than Rohit’s age. Also Ronit Was twice old as Rohit 15 Years ago.What will be the age of Ronit 6 Years after?
- 41
- 40
- 35
- 45
- 38
Correct

Rohit=x,Ronith=x+10

(x+10)-15=2(x-15)

Solve,x=25

Ronit’s 6 Years after=x+10+6=41

Incorrect

Rohit=x,Ronith=x+10

(x+10)-15=2(x-15)

Solve,x=25

Ronit’s 6 Years after=x+10+6=41
Question 25 of 25

25. Question
1 points
18 Years ago the ratio of ‘A’s age to B’s age was 8:13. Present age of their ages ratio is 5:7. What is the present age of B?
- 90 Years
- 70 Years
- 60 Years
- 50 Years
- None of these
Correct

$8 x + \frac{18}{13} x + 18 = \frac{5}{7} 56 x + 126 = 65 x + 90 9 x = 36 x = 4 B = 13 * 4 + 18 = 70$

Incorrect

$8 x + \frac{18}{13} x + 18 = \frac{5}{7} 56 x + 126 = 65 x + 90 9 x = 36 x = 4 B = 13 * 4 + 18 = 70$

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