Online exam in Ages For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT
Ages-Test 4
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Subject :- Quantitative Aptitude
Chapter :- Ages- Test 4
Questions :- 25
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Ratio of ages of Reena and Prerna is 2 : 3 and the ratio of ages of Tiya and Reena is 3: 1. If the ratio of age of Prerna four years hence to age of Tiya three years hence is 5 :9, what is the total of the ages of all three?
Correct
P/R = 3/2 and R/T = 1/3
So P : R : T =
3*1 : 2*1 : 2*3 = 3 : 2 : 6
Now (3x+4)/(6x+3) = 5/9
So x = 7
P = 3x = 21, R = 2x = 14, T = 6x = 42
So P + R + T = 77
Incorrect
P/R = 3/2 and R/T = 1/3
So P : R : T =
3*1 : 2*1 : 2*3 = 3 : 2 : 6
Now (3x+4)/(6x+3) = 5/9
So x = 7
P = 3x = 21, R = 2x = 14, T = 6x = 42
So P + R + T = 77
Question 2 of 25
2. Question
1 points
Richa‘s age is thrice of Tisha‘s age while Megha‘s age is 3 less than that of Richa‘s.
The ratio of ages of Tisha‘s three years hence to Megha‘s four years ago is 3 : 5. What
is the square root of the total age of Tisha and Richa?
Correct
Tisha = x, Richa = 3x, Megha = 3x – 3
(x+3)/(3x-3-4) = 3/5
Solve, x = 9
So total age of Tisha + Richa = x + 3x = 4x = 36, So square root = √36 = 6
Incorrect
Tisha = x, Richa = 3x, Megha = 3x – 3
(x+3)/(3x-3-4) = 3/5
Solve, x = 9
So total age of Tisha + Richa = x + 3x = 4x = 36, So square root = √36 = 6
Question 3 of 25
3. Question
1 points
The ratio of age of Shaisha one year ago to Piya is 3 : 5. The sum of ages of Piya and
Misha after four years will be 50. If difference between the ages of Shaisha and Misha
is 7 years, find Misha‘s age.
Correct
(S -1)/P = 3/5
P + M + 4 + 4 = 50
So P + M = 42
S – M = 7
Solve equations, M = 12
Incorrect
(S -1)/P = 3/5
P + M + 4 + 4 = 50
So P + M = 42
S – M = 7
Solve equations, M = 12
Question 4 of 25
4. Question
1 points
Kashish‘s age is two-fifth the age of her mother. Nine years hence her age will be half
of her mother‘s age that time. What is her mother‘s present age?
Correct
K = 2M/5
(K+9) = (M+9)/2
Solve, M = 45
Incorrect
K = 2M/5
(K+9) = (M+9)/2
Solve, M = 45
Question 5 of 25
5. Question
1 points
Ratio between Rahim‘s age four years hence and Meher‘s age three years ago is 6 : 5.
If the ratio between Rahim‘s age two years ago and Meher‘s age four years hence is 6 :
11, find the ratio of Rahim‘ age to Meher‘s age.
Correct
(R+4)/(M-3) = 6/5
(R-2)/(M+4) = 12/22 = 6/11
Solve R = 14, M = 18
Incorrect
(R+4)/(M-3) = 6/5
(R-2)/(M+4) = 12/22 = 6/11
Solve R = 14, M = 18
Question 6 of 25
6. Question
1 points
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?
Correct
Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.
$(4x+8)=\frac{5}{2}x+8)$
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio =
$\frac{(4x+16)}{(x+16)}=\frac{48}{24}=2$
Incorrect
Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.
$(4x+8)=\frac{5}{2}x+8)$
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio =
$\frac{(4x+16)}{(x+16)}=\frac{48}{24}=2$
Question 7 of 25
7. Question
1 points
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Correct
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years
Incorrect
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years
Question 8 of 25
8. Question
1 points
A father said to his son, “I was as old as you are at the present at the time of your birth”. If the father’s age is 38 years now, the son’s age five years back was:
Correct
Let the son’s present age be x years. Then, (38 – x) = x
2x = 38.
x = 19.
Son’s age 5 years back (19 – 5) = 14 years
Incorrect
Let the son’s present age be x years. Then, (38 – x) = x
2x = 38.
x = 19.
Son’s age 5 years back (19 – 5) = 14 years
Question 9 of 25
9. Question
1 points
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
Correct
Let C’s age be x years. Then, B’s age = 2x years. A’s age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B’s age = 2x = 10 years
Incorrect
Let C’s age be x years. Then, B’s age = 2x years. A’s age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B’s age = 2x = 10 years
Question 10 of 25
10. Question
1 points
Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand’s present age in years?
Correct
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then,5x + 3
=
4x + 3 9
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x – 44x = 33 – 27
x = 6.
Anand’s present age = 4x = 24 years.
Incorrect
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then,5x + 3
=
4x + 3 9
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x – 44x = 33 – 27
x = 6.
Anand’s present age = 4x = 24 years.
Question 11 of 25
11. Question
1 points
A man is 24 years older than his son. In two years, his age will be twice the age of his son.The present age of his son is:
Correct
Let the son’s present age be x years. Then, man’s present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
Incorrect
Let the son’s present age be x years. Then, man’s present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
Question 12 of 25
12. Question
1 points
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar’s age at present?
Correct
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then,(6x + 6) + 4
=
11
(5x + 6) + 4 10
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar’s present age = (5x + 6) = 16 years
Incorrect
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then,(6x + 6) + 4
=
11
(5x + 6) + 4 10
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar’s present age = (5x + 6) = 16 years
Question 13 of 25
13. Question
1 points
The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be:
Correct
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 – x) – 6 = 5(x – 6)
54 – x = 5x – 30
6x = 84
x = 14.
Son’s age after 6 years = (x+ 6) = 20 years
Incorrect
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 – x) – 6 = 5(x – 6)
54 – x = 5x – 30
6x = 84
x = 14.
Son’s age after 6 years = (x+ 6) = 20 years
Question 14 of 25
14. Question
1 points
At present, the ratio between the ages of Arun and Deepak is 4 : 3. After 6 years, Arun’s age will be 26 years. What is the age of Deepak at present ?
Correct
Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,
4x + 6 = 26 4x = 20
x = 5.
Deepak’s age = 3x = 15 years
Incorrect
Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,
4x + 6 = 26 4x = 20
x = 5.
Deepak’s age = 3x = 15 years
Question 15 of 25
15. Question
1 points
Sachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7 : 9, how old is Sachin?
Correct
Let Rahul’s age be x years.
Then, Sachin’s age = (x – 7) years.
$\frac{x\u20137}{x}=\frac{7}{9}$
9x – 63 = 7x
2x = 63
x = 31.5
Hence, Sachin’s age =(x – 7) = 24.5 years.
Incorrect
Let Rahul’s age be x years.
Then, Sachin’s age = (x – 7) years.
$\frac{x\u20137}{x}=\frac{7}{9}$
9x – 63 = 7x
2x = 63
x = 31.5
Hence, Sachin’s age =(x – 7) = 24.5 years.
Question 16 of 25
16. Question
1 points
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Correct
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
20x = 80
x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Incorrect
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
20x = 80
x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Question 17 of 25
17. Question
1 points
Ayesha’s father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
Correct
Mother’s age when Ayesha’s brother was born = 36 years.
Father’s age when Ayesha’s brother was born = (38 + 4) years = 42 years.
Required difference = (42 – 36) years = 6 years
Incorrect
Mother’s age when Ayesha’s brother was born = 36 years.
Father’s age when Ayesha’s brother was born = (38 + 4) years = 42 years.
Required difference = (42 – 36) years = 6 years
Question 18 of 25
18. Question
1 points
A person’s present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?
Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50
years, what is definitely the difference between R and Q’s age?
Correct
R – Q = R- T Q = T.
Also, R + T = 50 R + Q = 50.
So, (R – Q) cannot be determined
Incorrect
R – Q = R- T Q = T.
Also, R + T = 50 R + Q = 50.
So, (R – Q) cannot be determined
Question 20 of 25
20. Question
1 points
The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age will be twice that of his son. The ratio of their present ages is:
Correct
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3
Incorrect
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3
Question 21 of 25
21. Question
1 points
The height of 5 boyis is recorded as, 146, cm, 154 cm,164 cm, 148 cm and 158 cm. What is the average height of all these boys?
James’s father was 30 years old when he was born. His mother’s age was 24 when his sister who is 5 years younger to him, was born. What is the difference between the age of James’s father and Mother?
Correct
James’ age F-30
Sister’s age=F-35
M=24+Sister’s age
M=24+F-35
F-M=11
Incorrect
James’ age F-30
Sister’s age=F-35
M=24+Sister’s age
M=24+F-35
F-M=11
Question 23 of 25
23. Question
1 points
David’s present age is 2/7 th of his father’s present age. David’s brother is three year older to james.The respective ratio between present ages of David father and David’s brother is 14:5. What is the present age of David?
Correct
Incorrect
Question 24 of 25
24. Question
1 points
Ronit’s age is 10 Years more than Rohit’s age. Also Ronit Was twice old as Rohit 15 Years ago.What will be the age of Ronit 6 Years after?
Correct
Rohit=x,Ronith=x+10
(x+10)-15=2(x-15)
Solve,x=25
Ronit’s 6 Years after=x+10+6=41
Incorrect
Rohit=x,Ronith=x+10
(x+10)-15=2(x-15)
Solve,x=25
Ronit’s 6 Years after=x+10+6=41
Question 25 of 25
25. Question
1 points
18 Years ago the ratio of ‘A’s age to B’s age was 8:13. Present age of their ages ratio is 5:7. What is the present age of B?