Online Quiz in Ages For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT
Ages-Test 3
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Subject :- Quantitative Aptitude
Chapter :- Ages- Test 3
Questions :- 25
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The present age of Sumit is 1/8th of his father. After 4 years, the father‘s age will be
twice the age of Raman. If Raman celebrated his 6th birthday eight years ago, what is
Sumit‘s present age?
Correct
Present ratio Sumit : Father is 1 : 8……………. (1)
4 years after, Father : Raman is 2 : 1………………..(2)
Raman‘s 6th birthday was 8 years ago, so after 4 years he will be 18 years old
Put in equation (2), Raman = 18, Father = 36
So present age of father = 32
So of Sumit is 32/8 = 4 years
Incorrect
Present ratio Sumit : Father is 1 : 8……………. (1)
4 years after, Father : Raman is 2 : 1………………..(2)
Raman‘s 6th birthday was 8 years ago, so after 4 years he will be 18 years old
Put in equation (2), Raman = 18, Father = 36
So present age of father = 32
So of Sumit is 32/8 = 4 years
Question 2 of 25
2. Question
1 points
Sita‘s present age is five times of her daughter‘s age and 1/3rd of her father‘s age. If the
average age of all the three is 28 years, then find the difference between Sita‘s
daughter‘s age and her father‘s age.
Correct
Sita : Daughter = 5 : 1
Sita : Father = 1: 3 or 5 : 15
Total age of 3 = 1 + 5 + 15 = 21
So average = 21/3 = 7
7…….28
1……..4
Sita‘s daughter = 4
So her father‘s = 60
Difference = 56 years
Incorrect
Sita : Daughter = 5 : 1
Sita : Father = 1: 3 or 5 : 15
Total age of 3 = 1 + 5 + 15 = 21
So average = 21/3 = 7
7…….28
1……..4
Sita‘s daughter = 4
So her father‘s = 60
Difference = 56 years
Question 3 of 25
3. Question
1 points
Sheetal‘s age at the time of her marriage was 4/5th of her present age. If she married 6
years ago and now she has a son who is 1/10th of her present age, then find the age of
her son 5 years hence.
Correct
4/5 * 6 = 24/30
24 => at the time of marriage
30 years => now
Son = 1/10 of present age = 1/10 * 30 = 3 years
5 years hence = 3+5 = 8 years
Incorrect
4/5 * 6 = 24/30
24 => at the time of marriage
30 years => now
Son = 1/10 of present age = 1/10 * 30 = 3 years
5 years hence = 3+5 = 8 years
Question 4 of 25
4. Question
1 points
Ram is 6 years elder then his brother and 5 years younger than her sister Sheena.
When Sheena was born, her father‘s age was 24 and when Ram‘s brother was born his
mother‘s age was 29. Find the difference between ages of Ram‘s father and his
mother.
Correct
Bother=x
Ram=x+6
Sheena=x+11
Father=x+11+24=x+35
Mother=x+29
Difference=x+35 –(x+29)=6 years
Incorrect
Bother=x
Ram=x+6
Sheena=x+11
Father=x+11+24=x+35
Mother=x+29
Difference=x+35 –(x+29)=6 years
Question 5 of 25
5. Question
1 points
When a couple was married, their average age was 22 years. When their first child was
born, the average age of all the three became16 years. When their second child was
born, the average of all 4 became 15 years. Find the average age of couple at the time
when their second child was born.
Correct
At the time of marriage total age of couple=44
when 1st child is born total age of three=16*3=48
Difference=48-44=4 years (Child is of 0 years hence this is the sum of age incrase of
couple)
When second child is born sum of age=4*15=60 years
=> increase of 12 years after first child, means age of husband, wife and first child
increased by 4 years each. SO increase in husband and wife total age = 8 years
total increase =4+8=12
total age=44+12=56; average=56/2=28 years
Incorrect
At the time of marriage total age of couple=44
when 1st child is born total age of three=16*3=48
Difference=48-44=4 years (Child is of 0 years hence this is the sum of age incrase of
couple)
When second child is born sum of age=4*15=60 years
=> increase of 12 years after first child, means age of husband, wife and first child
increased by 4 years each. SO increase in husband and wife total age = 8 years
total increase =4+8=12
total age=44+12=56; average=56/2=28 years
Question 6 of 25
6. Question
1 points
Five years ago, the ratio of ages of A and B was 5 : 3 and five years hence from now,
the ratio will become 7 : 5. Find the average of their present ages.
Correct
———————A———–B
5 years ago—–5————-3
…………………—7————–5
In both case increase of 2 years 7-5=2 and 5-3=2
hence this increase of 2 years is for 10 years
=>1=5
hence A=5*5+5=30
B=3*5+5=20
Average=25
Incorrect
———————A———–B
5 years ago—–5————-3
…………………—7————–5
In both case increase of 2 years 7-5=2 and 5-3=2
hence this increase of 2 years is for 10 years
=>1=5
hence A=5*5+5=30
B=3*5+5=20
Average=25
Question 7 of 25
7. Question
1 points
Four years ago, the ratio of ages of Vishal and Devansh was 3 : 5. Four years from
now, the respective ratio will become 2 : 3. What is the ratio of age of Vishal 4 years
ago and Devansh‘s present age?
Correct
—————————–V——————–D
4 years ago ————–3———————-5 ——-(eq 1)
4 years hence————2———————–3 ——- (eq 2)
Difference of V= 3-2=1; Difference of D= 5-3=2
to make this difference equal multiply eq 2, by 2 we get
—————————–V——————–D
4 years ago ————–3———————-5 ——-(eq 1)
4 years hence————4———————–6 ——- (eq 2)
difference = 1 in both case
This is for 8 years =>1= 8 years
V=3*8=24 (4 years ago)
D=5*8=40 (4 years ago)
ratio =24/44=6:11
Incorrect
—————————–V——————–D
4 years ago ————–3———————-5 ——-(eq 1)
4 years hence————2———————–3 ——- (eq 2)
Difference of V= 3-2=1; Difference of D= 5-3=2
to make this difference equal multiply eq 2, by 2 we get
—————————–V——————–D
4 years ago ————–3———————-5 ——-(eq 1)
4 years hence————4———————–6 ——- (eq 2)
difference = 1 in both case
This is for 8 years =>1= 8 years
V=3*8=24 (4 years ago)
D=5*8=40 (4 years ago)
ratio =24/44=6:11
Question 8 of 25
8. Question
1 points
The average age of 10 men increased by 1 when two men of age 25 and 27 years are
replaced by 2 other men. Find the average age of new men.
Correct
Sum of age of leaving person=52
total increase of of age=10*1=10 years
increased total age due to addition of two men=52+10=62; Avg=31
Incorrect
Sum of age of leaving person=52
total increase of of age=10*1=10 years
increased total age due to addition of two men=52+10=62; Avg=31
Question 9 of 25
9. Question
1 points
The average age of a group of 20 men is 22 years. If two men whose age are 24 and
31 years respectively join the group, the average age of new group increase or
decrease by
Correct
When 2 new people join if the sum of their age is 44 then the average will not change,
but the sum of age of new people is 55 i.e increase of 11
hence avg increases by 11/22=0.5 years.
Incorrect
When 2 new people join if the sum of their age is 44 then the average will not change,
but the sum of age of new people is 55 i.e increase of 11
hence avg increases by 11/22=0.5 years.
Question 10 of 25
10. Question
1 points
The ratio of present age of Tiya and Piya is 3 : 5 and the ratio of ages of Tiya 5 years
ago and Piya 5 years hence is 1 : 3. Find the present age of Piya.
Correct
T/P=3/5 ——- (i)
T-5/P+5 =1/3 ———- (ii)
Solve and get
T=15 years
P= 25 years
Incorrect
T/P=3/5 ——- (i)
T-5/P+5 =1/3 ———- (ii)
Solve and get
T=15 years
P= 25 years
Question 11 of 25
11. Question
1 points
Four times the difference in ages of C and A is one more than the age if B. Percentage
of A‘s age to C‘s age is 75%. If ratio of B‘s age 5 years hence to C‘s age 1 year ago is
4 : 3. Find the average of ages A and C.
Correct
4 (C-A) = B + 1
A/C * 100 = 75
(B+5)/(C-1) = 4/3
Solve
A = 12, C = 16
Average of A and B=12+16/2=14
Incorrect
4 (C-A) = B + 1
A/C * 100 = 75
(B+5)/(C-1) = 4/3
Solve
A = 12, C = 16
Average of A and B=12+16/2=14
Question 12 of 25
12. Question
1 points
10 years ago daughter‘s age was two-fifth of her mother‘s age that time. While 10 years
hence her age will be three-fifth of her mother‘s age then. Find the difference in the
ages of the two.
Correct
(x-10) = 2/5 (y-10)
(x+10) = 3/5 (y+10)
Solve, x = 26 and y = 50
50-26=24
Incorrect
(x-10) = 2/5 (y-10)
(x+10) = 3/5 (y+10)
Solve, x = 26 and y = 50
50-26=24
Question 13 of 25
13. Question
1 points
B is as more younger than C as he is elder than A. Ratio of ages of A to C is 5 : 9. If B‘s
age after 10 years will be 24, find the average of all of their present ages.
Correct
B‘s present age = 24-10 = 14
So C‘ age = 14+x
And A‘ age = 14-x
(14+x)/(14-x) = 9/5
Solve, x = 4
So average age = (10+14+18)/3 = 14 years
Incorrect
B‘s present age = 24-10 = 14
So C‘ age = 14+x
And A‘ age = 14-x
(14+x)/(14-x) = 9/5
Solve, x = 4
So average age = (10+14+18)/3 = 14 years
Question 14 of 25
14. Question
1 points
Kaira is 4 years younger to his brother. Her father was 30 years old when her sister
was born while her mother was was 30 years old when she was born. If her sister was
4 years old when their brother was born, find the age of her father when her mother
was born.
Correct
When Kaira was born:
Mother was 30.
She is 4 years younger to her brother, so brother was 4 years old.
Sister was 4 years old when brother was born, so sister is 4 years elder to brother, so
sister was 8 years old.
Father was 30 when sister was born, so father is 30 years elder to sister, so father was
30+8 = 38 years old.
Now when Kaira was born, mother was 30 and father was 38
So difference in their ages is 8 years. So when mother was born, father was 8.
Incorrect
When Kaira was born:
Mother was 30.
She is 4 years younger to her brother, so brother was 4 years old.
Sister was 4 years old when brother was born, so sister is 4 years elder to brother, so
sister was 8 years old.
Father was 30 when sister was born, so father is 30 years elder to sister, so father was
30+8 = 38 years old.
Now when Kaira was born, mother was 30 and father was 38
So difference in their ages is 8 years. So when mother was born, father was 8.
Question 15 of 25
15. Question
1 points
6 years ago, three times the age of B was 2 more than the age if A that time. 6 years
hence, twice age of B will be equal to A‘s age that time. Find the total of their ages.
Correct
3 * (B-6) = 2 + (A-6)
2 * (B+6) = A + 6
Solve, A = 46, B = 20
=46+20=66
Incorrect
3 * (B-6) = 2 + (A-6)
2 * (B+6) = A + 6
Solve, A = 46, B = 20
=46+20=66
Question 16 of 25
16. Question
1 points
If 6 years are subtracted from the present age of Babita and the remainder is divided by
18, then the present age of her granddaughter Geeta is obtained. If Geeta is 2 years
younger to Sita whose age is 5 years, then what is Babita‘s present age?
Correct
Geeta‘s age = (5-2) = 3 years
Let age of Babita = x years
So (x-6)/18 = 3,Solve, x = 60
Incorrect
Geeta‘s age = (5-2) = 3 years
Let age of Babita = x years
So (x-6)/18 = 3,Solve, x = 60
Question 17 of 25
17. Question
1 points
A‘s age is twice C‘ age. Ratio of age of B 2 years hence to age of C 2 years ago is 5 :
2. C is 14 years younger than D. Difference in ages of D and A is 4 years. Find the
average of their ages.
Correct
A = 2C
(B+2)/(C-2) = 5/2
C = D – 14
D – A = 4
Solve, A = 20, B = 18, C = 10, D = 24
Incorrect
A = 2C
(B+2)/(C-2) = 5/2
C = D – 14
D – A = 4
Solve, A = 20, B = 18, C = 10, D = 24
Question 18 of 25
18. Question
1 points
When the couple was married the average of their ages was 25 years. When their first
child was born, the average age of family became 18 years. When their second child
was born, the average age of the family became 15 years. Find the average age of the
couple now.
Correct
Sum of ages of couple = 25*2 = 50
When 1st child born, total age of 3 = 18*3 = 54 years
At this time the child‘s age was 0, so age of father and mother would have increased by
same. So increased by 2 years each. So 50 +2 + 2 = 54
Now when 2nd child born, total age of 4 = 15*4 = 60
So this time second child‘s age = 0 and age of father, mother and first child would have
increased by same. So increased by 2 each such that 54 + 2+2+2 = 60
So now this time (after 4 years from age 50), total age of couple is 50+4+4 = 58
So average = 29 years
Incorrect
Sum of ages of couple = 25*2 = 50
When 1st child born, total age of 3 = 18*3 = 54 years
At this time the child‘s age was 0, so age of father and mother would have increased by
same. So increased by 2 years each. So 50 +2 + 2 = 54
Now when 2nd child born, total age of 4 = 15*4 = 60
So this time second child‘s age = 0 and age of father, mother and first child would have
increased by same. So increased by 2 each such that 54 + 2+2+2 = 60
So now this time (after 4 years from age 50), total age of couple is 50+4+4 = 58
So average = 29 years
Question 19 of 25
19. Question
1 points
Ratio of age of A to B is 3 : 2 and that of A to C is 1 : 2. Difference in ages of B and C is
24 years. Find the average of their present ages.
Correct
B/A = 2/3 and A/C = 1/2
So B : A : C = 2*1 : 3*1 : 3*2 = 2 : 3 : 6
So 6x – 2x = 24, 4x = 24, x = 6
So total of their present ages = (2+3+6)*6. So average = (2+3+6)*6 / 3 = 22 years
Incorrect
B/A = 2/3 and A/C = 1/2
So B : A : C = 2*1 : 3*1 : 3*2 = 2 : 3 : 6
So 6x – 2x = 24, 4x = 24, x = 6
So total of their present ages = (2+3+6)*6. So average = (2+3+6)*6 / 3 = 22 years
Question 20 of 25
20. Question
1 points
Ratio of ages of A 5 years hence to B‘s age 3 years ago is 5 : 3. Also ratio of ages of A
4 years ago to B‘s age 2 years hence is 4 : 5. Find the age of the elder.
Correct
(A+5)/(B-3) = 5/3
(A-4)/(B+2) = 4/5
Solve A = 20, B = 18
Incorrect
(A+5)/(B-3) = 5/3
(A-4)/(B+2) = 4/5
Solve A = 20, B = 18
Question 21 of 25
21. Question
1 points
The ratio of ages of Sneha to Bhavna is 6 : 13. Also ratio between Kritika‘s age two
years after and Bhavna‘s age 4 years after will be 2 : 3. If the average age of Sneha
and Kritika is 15 years, what will be Kritika‘s age three years hence?
Correct
S/B = 6/13
(K+2)/(B+4) = 2/3
S + K = 2*15 = 30
Solve the equations, K = 12, So K + 3 = 15
Incorrect
S/B = 6/13
(K+2)/(B+4) = 2/3
S + K = 2*15 = 30
Solve the equations, K = 12, So K + 3 = 15
Question 22 of 25
22. Question
1 points
Difference between ages of Raman and Preet is 16 years. If Raman‘s age ten years
hence will be two times the age of Preet, find Raman‘s age.
Correct
R – P = 16
(R + 10) = 2P
Solve, R = 42
Incorrect
R – P = 16
(R + 10) = 2P
Solve, R = 42
Question 23 of 25
23. Question
1 points
Three years ago, Pihu was thrice old as Ravi that time. How old is Pihu today if ratio of
age of Pihu six years hence to Ravi‘s age four years ago is 9 : 2?
Correct
(P – 3) = 3* (R-3)
(P + 6)/(R – 4) = 9/2
Solve both equations, P = 30
Incorrect
(P – 3) = 3* (R-3)
(P + 6)/(R – 4) = 9/2
Solve both equations, P = 30
Question 24 of 25
24. Question
1 points
The average age of Yogita, Kanika and Prachi is 14 years. The ratio of Yogita‘s age
one year ago to Kanika‘s age one years hence to Prachi‘s age three years hence is 5 :
6 : 4. Find ratio of Yogita‘s age two years hence to Prachi‘s age.
Correct
Y + K + P = 42
(Y – 1) : (K + 1) : (P + 3) = 5 : 6 : 4
So (5x + 1) + (6x – 1) + (4x – 3) = 42
Solve, x = 3
So Yogita‘s age 1 ago hence = 5x = 15, so present age = 16
Prachi‘s age 3 years hence = 4x = 12, so present age = 9
So (Y+2)/P = 18/9 = 2/1
Incorrect
Y + K + P = 42
(Y – 1) : (K + 1) : (P + 3) = 5 : 6 : 4
So (5x + 1) + (6x – 1) + (4x – 3) = 42
Solve, x = 3
So Yogita‘s age 1 ago hence = 5x = 15, so present age = 16
Prachi‘s age 3 years hence = 4x = 12, so present age = 9
So (Y+2)/P = 18/9 = 2/1
Question 25 of 25
25. Question
1 points
Sneha‘s mother‘s age is five years more than twice the age of Sneha. When Sneha
was born, her brother Rahul was four years old and her father two years older than her
mother. If the average age of her mother and father is 46 years. Find the ratio of age of
Rahul to that of Sneha.
Correct
Let age of Sneha = x, So age of Mother = 2x+5, Rahul = x+4, Father = 2x+7
(2x+5 + 2x+7) = 2*46
So x = 20
So (x+4)/x = 24/20 = 6/5
Incorrect
Let age of Sneha = x, So age of Mother = 2x+5, Rahul = x+4, Father = 2x+7
(2x+5 + 2x+7) = 2*46
So x = 20
So (x+4)/x = 24/20 = 6/5