Online Mock Test in Ages For Quantitative Aptitude for Competitive exams like IBPS BANK PO/Clerical,SBI,RRB,SSC,LIC,UPSC-CSAT,SCRA.MAT,CMAT,MBA,SNAP,CAT,NTSE,CLAT
Ages-Test 2
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Subject :- Quantitative Aptitude
Chapter :- Ages- Test 2
Questions :- 25
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Meena married 10 years ago. Today her age is 7/5 times her age at the time of her
marriage. Her daughter age is 1/5 of her age. What is the ratio of Meena‘s age to her
daughter age after 5 years?
Correct
Let‘s Meena‘s age be x
X=7/5*(x-10)==>x=35.
And her daughter‘s age 35/5=7.
After5yrs M:D=40:12==>10:3
Incorrect
Let‘s Meena‘s age be x
X=7/5*(x-10)==>x=35.
And her daughter‘s age 35/5=7.
After5yrs M:D=40:12==>10:3
Question 2 of 25
2. Question
1 points
Father is aged three times more than his son kavin. After 8 years, he would be two and
a half times of kavin‘s age. After further 8 years, how many times would he be of
kavin‘s age?
Correct
Assume that kavin‘s present age =x.
Then, father‘s present age =3x+x=4x
After 8 years, father‘s age=2 ½ times of kavin‘s age.
(4x+8)=2 1/2(x+8)==>3x=24
X=8.
Then x kavin‘s age=8,her father‘s age 4*8=32.
After 8+8 =16yrs.their age‘s are 24 and 48.
It is 2 times.
Incorrect
Assume that kavin‘s present age =x.
Then, father‘s present age =3x+x=4x
After 8 years, father‘s age=2 ½ times of kavin‘s age.
(4x+8)=2 1/2(x+8)==>3x=24
X=8.
Then x kavin‘s age=8,her father‘s age 4*8=32.
After 8+8 =16yrs.their age‘s are 24 and 48.
It is 2 times.
Question 3 of 25
3. Question
1 points
Mr. X has three sons namely P, Q and R. P is the eldest son of Mr. X while R is the
youngest one. The present ages of all three of them are square numbers. The sum of
their ages after 5 years is 44. What is the age of P after three years?
Correct
Square numbers – x, y, z
(x + 5) + (y + 5)+ (z + 5) = 44
x + y + z = 44 – 15 = 29
Possible values of x, y, z = 4, 9, 16 [Out of 1, 4, 9, 16, 25] P‘s present age = 16; after
three years = 19
Incorrect
Square numbers – x, y, z
(x + 5) + (y + 5)+ (z + 5) = 44
x + y + z = 44 – 15 = 29
Possible values of x, y, z = 4, 9, 16 [Out of 1, 4, 9, 16, 25] P‘s present age = 16; after
three years = 19
Question 4 of 25
4. Question
1 points
Three years ago the average age of Ramesh‘s family having 5 members was 17 years.
Ramesh becomes father but the average age of his family is same today. What is the
present age of baby?
Correct
The age of 5 members 3 years ago=17×5=85 years
Total age of 5 members at present= 85 + (5×3)=100 years
Total age of 6 members at present =17×6=102 years…
(as average is same at present so we took 17)
Hence, age of baby = 102-100 = 2 years
Incorrect
The age of 5 members 3 years ago=17×5=85 years
Total age of 5 members at present= 85 + (5×3)=100 years
Total age of 6 members at present =17×6=102 years…
(as average is same at present so we took 17)
Hence, age of baby = 102-100 = 2 years
Question 5 of 25
5. Question
1 points
The ratio between the present ages of A and B is 6:7. If B is 4 years old than A, what
will be the ratio of the ages of A and after 4 years.
Correct
Let A age and B age is 6x years and 7x years.
Then 7x – 6x = 4 <=> x = 4
So required ratio will be (6x+4): (7x+4) => 28:32 => 7:8
Incorrect
Let A age and B age is 6x years and 7x years.
Then 7x – 6x = 4 <=> x = 4
So required ratio will be (6x+4): (7x+4) => 28:32 => 7:8
Question 6 of 25
6. Question
1 points
Four years ago the ratio of ages of A &B was 3 : 5 and five year hence the ratio will
become 6:8. Find the present age of A?
Correct
Incorrect
Question 7 of 25
7. Question
1 points
Six year ago the ratio of ages of A & B was 1:3 and after six year the ratio becomes
2:3. Find the sum of present ages of A & B.
Correct
Incorrect
Question 8 of 25
8. Question
1 points
The present ratio of ages of A & B is 11:12 and the ratio of ages of A‘s 2yr back and B‘s
6yr after is 2:3. Find age of A 6yr after?
Correct
A/B = 11/12 ……….(1)
(A-2)/(B+6) = 2/3………(2)
By solving above equation we will get A = 22
So age of A 6yr after = 22+6 =28yr
Incorrect
A/B = 11/12 ……….(1)
(A-2)/(B+6) = 2/3………(2)
By solving above equation we will get A = 22
So age of A 6yr after = 22+6 =28yr
Question 9 of 25
9. Question
1 points
The average of 20 students class is 21. If the age of teacher is included then average
increase by 2yr. Find age of teacher?
Correct
If the age of teacher is 21 then average remains unchanged but due to increase by 2yr,
it means teacher gave 2yr to everyone( 20+1) =21
21 + (21*2)
21+ 42= 63 yr
Incorrect
If the age of teacher is 21 then average remains unchanged but due to increase by 2yr,
it means teacher gave 2yr to everyone( 20+1) =21
21 + (21*2)
21+ 42= 63 yr
Question 10 of 25
10. Question
1 points
Sita‘s present age is 1(2/5) times of her age at the time of marriage. She married 10yr
ago. Now she has a son whose age is 1 more than 1/5th of her age at the time of
marriage. Find the age of son?
Correct
Incorrect
Question 11 of 25
11. Question
1 points
The ratio of father and son‘s age is 7:4. The product of their ages is 2800. The ratio of
their ages after 2yr will be ?
Correct
Sol : let their age is 7x and 4x
Product = 28x² = 2800
x² =100
x = 10
Their ages = 70 : 40
2yrs after = 72 42
12 : 7
Incorrect
Sol : let their age is 7x and 4x
Product = 28x² = 2800
x² =100
x = 10
Their ages = 70 : 40
2yrs after = 72 42
12 : 7
Question 12 of 25
12. Question
1 points
The sum of the ages of father and son is 45yrs. Five years ago the product of their
ages was 4 times the father‘s age at that time the present ages of father & son are ?
Correct
F + S = 45
5yr ago F + S = 35
A.T.Q = F * S = 4* F
S = 4yr
F = 31yr
Present age = 31+5 =36yr
4+5= 9 yr
Incorrect
F + S = 45
5yr ago F + S = 35
A.T.Q = F * S = 4* F
S = 4yr
F = 31yr
Present age = 31+5 =36yr
4+5= 9 yr
Question 13 of 25
13. Question
1 points
The ratio between the ages of father & son at present is 7:3. 4yr hence the ratio
between son & his mother will be 1:2. Find the ratio of the present ages of father &
mother?
Correct
Let age of father & son …. 7x, 3x
4yr hence, son‘s age = 3x+4
Ratio of ages of son & mother … 3x+4 : M = 1:2
M = 6x+8
F + M = 7x : 6x+4
We can‘t find value of x. so ans is D.
Incorrect
Let age of father & son …. 7x, 3x
4yr hence, son‘s age = 3x+4
Ratio of ages of son & mother … 3x+4 : M = 1:2
M = 6x+8
F + M = 7x : 6x+4
We can‘t find value of x. so ans is D.
Question 14 of 25
14. Question
1 points
Three years ago the father was 7times as old as his son. Three year hence the father‘s
age would be 4times that of his son. Find present ages of father and son?
Correct
Incorrect
Question 15 of 25
15. Question
1 points
Mikesh was thrice as old as ajay 20 yrs back. How old is ajay today, if mikesh will be 50
yrs old 10 year hence?
Correct
Mikesh‘s present age =50-10 = 40yr
20 yrs back from now mikesh age = 20yr
Ajay is half = 10yr
Now ajay age = 10+20 =30yr
Incorrect
Mikesh‘s present age =50-10 = 40yr
20 yrs back from now mikesh age = 20yr
Ajay is half = 10yr
Now ajay age = 10+20 =30yr
Question 16 of 25
16. Question
1 points
Ratio of present age of A and B is 7 : 9 and ratio of ages of A 5 years back and age of
B 5 years later is 3:5. Find the present age of B.
Correct
A/B=7/9
(A-5)/(B+5)=3/5
solve both and get A=35 and B=45
Incorrect
A/B=7/9
(A-5)/(B+5)=3/5
solve both and get A=35 and B=45
Question 17 of 25
17. Question
1 points
5 years ago the ratio of ages of A and B are 5:7 and 10 years hence from now ratio will
become 4:5. Find the average of present age of A and B.
Correct
—————————–A ———— B
5 years ago ————- 5 ———- 7
10 years hence ——– 4 ———–5
Difference = ——– (-1)——– (-2)
to make these two difference equal multiply the second equation with (7-5)=2
So we get
—————————–A ———— B
5 years ago ————- 5 ———- 7
10 years hence ——– 8 ———–10
Difference = ——– (+3)——– (+3)
3=15 years (5 ago + 10 hence)
1=5 years
=> 5 = 25 years (5 years ago of A)
=>7=35 years (5 years ago of B)
Hence A=25+5=30
B=35+5=40 years
Avg=70/2=35
Incorrect
—————————–A ———— B
5 years ago ————- 5 ———- 7
10 years hence ——– 4 ———–5
Difference = ——– (-1)——– (-2)
to make these two difference equal multiply the second equation with (7-5)=2
So we get
—————————–A ———— B
5 years ago ————- 5 ———- 7
10 years hence ——– 8 ———–10
Difference = ——– (+3)——– (+3)
3=15 years (5 ago + 10 hence)
1=5 years
=> 5 = 25 years (5 years ago of A)
=>7=35 years (5 years ago of B)
Hence A=25+5=30
B=35+5=40 years
Avg=70/2=35
Question 18 of 25
18. Question
1 points
The present age of a son is 40% of his father age. And the age of his mother is 220%
of his age. The average age of three members is 38. Find the present age of mother.
Correct
Son= 40% of father.
F:S=5:2
Mother=220% of son=11/5
M:S=11:5
make F:M:S =25:22:10
avg=(25+22+10)/3=19
19=38
1=2
=>22=44
Incorrect
Son= 40% of father.
F:S=5:2
Mother=220% of son=11/5
M:S=11:5
make F:M:S =25:22:10
avg=(25+22+10)/3=19
19=38
1=2
=>22=44
Question 19 of 25
19. Question
1 points
Rama got married 8 years ago. Her present age is 1 (1/3) times of her age at the time
of marriage. She has a son who is one eighth of her present age. Then find the age of
her son.
Correct
1 (1/3)=4/3
Ratio of present age of Rama and her age at time of marriage=4:3 ——– difference =1
1=8 years
4=32
age of son=32/8=4 years
Incorrect
1 (1/3)=4/3
Ratio of present age of Rama and her age at time of marriage=4:3 ——– difference =1
1=8 years
4=32
age of son=32/8=4 years
Question 20 of 25
20. Question
1 points
A says to B ―I am thrice as old as you are when I was as old as you were‖. If age of B is
20 years find the age of A
Correct
Incorrect
Question 21 of 25
21. Question
1 points
The fathers age is four times as much as the sum of the age of his three children but 6
years hence his age will be thrice as the sum of their age. The present age of father is?
Correct
Let sum of children age=x ; hence father =4x
(4x+6)/x+6 = 3/1
x=12;
father=48
Incorrect
Let sum of children age=x ; hence father =4x
(4x+6)/x+6 = 3/1
x=12;
father=48
Question 22 of 25
22. Question
1 points
In a class of 20 students the average of all the students is 18 years. If the age of their
teacher is added then the average becomes 19 years. Find the age of teacher after 5
year.
Correct
Let age of teacher=x
(total age)/ total people=19
360+x/21=19
x=39
hence age after 5 years=44
Incorrect
Let age of teacher=x
(total age)/ total people=19
360+x/21=19
x=39
hence age after 5 years=44
Question 23 of 25
23. Question
1 points
In a family there are 5 brothers in a gap of 2 years. If therir average age is 22 find the
sum of eldest and youngest brother.
Correct
difference is same, hence 22 i.e is average is the age of middle son i.e
18,20,22,24,26 : age of 5 son
18+26=44
Incorrect
difference is same, hence 22 i.e is average is the age of middle son i.e
18,20,22,24,26 : age of 5 son
18+26=44
Question 24 of 25
24. Question
1 points
Four years ago the ratio of ages of A and B is 3:5. After four years from now the ratio
will be 5:7. Then find the ratio of their present age.
Correct
. A B
4 years ago = 3 5
4 years after = 5 7
Difference = 2 2
2=8 (4 ago + 4 hence)
1=4
present age A= 3*4 + 4=16
B=5*4 +4=24
16/24=2:3
Incorrect
. A B
4 years ago = 3 5
4 years after = 5 7
Difference = 2 2
2=8 (4 ago + 4 hence)
1=4
present age A= 3*4 + 4=16
B=5*4 +4=24
16/24=2:3
Question 25 of 25
25. Question
1 points
The average age of a couple at the time of their marriage was 22. Two years after the
marriage their child was born. Now he is 4 years old. Find the average age of their
present age.
Correct
Sum of couples age at time of marriage=2*22=44
when son was born, total age=44+2+2=48
After 4 years total age=48+4+4+4=60
avg=60/3=20
Incorrect
Sum of couples age at time of marriage=2*22=44
when son was born, total age=44+2+2=48
